Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in** Quadratic Equations** which is common for all the IBPS,SBI exam and other competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

**You have to solve equation I and II ,Give answer**

**1)If X>Y**

**2)If X<Y**

**3)If Xâ‰¥ Y**

**4)If Xâ‰¤ Y**

**5)If X=Y or cannot be established**

**I. 3X**^{2 }Â +23X + 44 = 0

**II. 3Y**^{2 }+ 20Y +33 = 0

**4)If Xâ‰¤ Y**

Explanation :

3x(x+4)+11(x+4)

X = -4, -11/3

3y(y+3)+11(y+3)

Y = -3, -11/3

-3,-3.6,-3.6,-4 => yyxx

xâ‰¤y

**I. 3X**^{2 }+29 X +56 = 0

**II. 2Y**^{2 }+ 15Y + 25 = 0

**5)If X=Y or cannot be established**

Explanation :

3x(x+7)+8(x+7)

X=-7, -8/3

2y(y+5)+5(y+5) = 0

Y = -5, -5/2

-2.5,-2.6,-5,-7 => yxyx

**I. 2X**^{2 }Â – X â€“ 10 = 0

**II.Â 2Y**^{2 }– Y â€“ 21 = 0

**5)If X=Y or cannot be established**

Explanation :

X(2x-5) + 2(2x-5) = 0

X = -2,5/2

Y(2y-7)+3(2y-7)= 0

Y= -3,7/2

3.5,2.5,-2,-3 => yxxy

**I. 3X**^{2 }Â – 16X + 21 = 0

**II. 3Y**^{2 }– 28Y + 65 = 0

**2)If X<Y**

Explanation :

3x(x-3) â€“ 7(x-3) = 0

X= 3,7/3

3y(y-5) â€“ 13(y-5) = 0

Y = 5,13/3

5,4.3,3,2.3 = yyxx

**I. X**^{2 }Â + 3X + 2 = 0

**II. Y**^{2 }+ 5Y +6 = 0

**3)If Xâ‰¥ Y**

Explanation :

(x+1)(x+2) = 0

X= -1,-2

(Y+2)(y+3) = 0

Y = -2,-3

-1,-2,-2,-3 => xxyy

**I. X**^{2 }= 1849

**II. Y = Â (1849)**^{1/2 }Â

**4)If Xâ‰¤ Y**

Explanation :

X = Â±43

Y = 43

xâ‰¤y

**I. 2X**^{2 }Â – X â€“ 21 = 0

**II.3Y**^{2 }+ 14Y + 15 = 0

**5)If X=Y or cannot be established**

Explanation :

2x(x+3) â€“ 7(x+3) = 0

X = -3,7/2

3y(y+3) + 5(y+3) = 0

Y = -3,-5/3

3.5, -1.6, -3,-3 => xyyx

**I. 3X**^{2 }Â – 22 X + 40 = 0

**II. 2Y**^{2 }-19 Y + 44 = 0

**4)If Xâ‰¤ Y**

Explanation :

3x(x-4) â€“ 10(x-4) = 0

x = 4,10/3

2y(y-4) â€“ 11(y-4) = 0

Y = 4,11/2

5.5,4,4,3.3 => yyxx

**I. 2X**^{2 }Â – 5X â€“ 12 = 0

**II. 2Y**^{2 }+ 11Y + 15 = 0

**1)If X>Y**

Explanation :

2x(x-4) + 3(x-4) = 0

X = 4,-3/2

2y(y+3) + 5(y+3) = 0

Y = -3,-5/2

4,-1.5,-2.5,-3 = xxyy

**I. 2X**^{2 }Â – 23X + 56 = 0

**II. Y**^{2 }– 20Y + 99 = 0

**2)If X<Y**

Explanation :

(x-8)(2y-7) = 0

8,7/2

(y-9)(y-11) = 0

Y = 9,11

11,9,8,3.5 => yyxx

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