Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.

**A does a work in 10 days, and B does the same work in 18 days. A and B started the work, by A left after some days. B completed the remaining work in 6 4/5 days. Find the number of days after which A left?**

A. 2

B. 3

C. 4

D. 5

C. 4

Explanation:

Let A left after ‘x’ days. B completed remaining work in 6 4/5 days or 34/5 days. So,

(1/10 + 1/18) * x + 1/18 * 34/5 = 1

Find x**A does a work in 10 days and B does the same work in 18 days. They started the work alternately starting with A. After how many days the work will be completed?**A. 12 days

B. 12 2/3 days

C. 20 2/3 days

D. 24 days

B. 12 2/3 days

LCM (10, 18) = 90

So total work = 90

A’s efficiency = 90/10 = 9

B’s efficiency = 90/18 = 5

2 days work (A+B) = 9+5 = 14

Multiply by 6 both side

12 days work (A+B) = 84

Remaining work = 90-84 = 6

Now A’s turn, he will complete remaining work in 6/9 or 2/3 day

So total 12 2/3 days.

**Rs 7000 is deposited in two schemes, one part at 6% per annum and other at 4% per annum. After 5 years, the total interest on both the schemes becomes Rs 1600. Find the amount deposited with 6% per annum?**

A. Rs 1000

B. Rs 2000

C. Rs 4000

D. Rs 5000

B. Rs 2000

Explanation:

Find the rate % of 5 yrs:

1600 = 7000*r*5 / 100, this gives r = 32/7%

By the method of allegation:

6 4

. 32/7

32/7 – 4 = 4/7 6 – 32/7 = 10/7

4/7 : 10/7 or 2 : 5

Amount at 6% = 2/(2+5) * 7000 = 2000

**An article is bought at an amount of Rs 840. 1/4th of it is sold at 20% loss, find the profit percent on remaining part such that there is a profit of 20% on the whole?**

A. 33 1/3%

B. 33%

C. 25%

D. 20%

A. 33 1/3%

Explanation:

Remaining part = 1- 1/4 = 3/4

1/4(-20) + 3/4(x) = 20

Find x**A train travelling at 25 km/hr leaves Delhi at 9 AM and another train travelling at 35 km/hr starts at 2 PM in the same direction. How many km form Delhi will they be together?**

A. 440 km

B. 400 km

C. 437 ½ km

D. 400 ½ km

C. 437 ½ km

Explanation:

Distance = (S1*S2)/[(S1-S2)t]

Difference in time = 2Pm – 9AM = 5 hrs

Distance = (25*35)/[(35-25)*5] = 437 ½ km**A man covers a certain distance between his house and office. If his average speed is 20 km/hr, he is late by 10 min and if his average speed is 50 km/hr, he reaches 20 min early. Find the distance between his house and office?**

A. 50 km

B. 50/3 km

C. 55 km

D. 56/7 km

B. 50/3 km

Explanation:

Distance = (S1*S2)/[(S1-S2)t]

Difference in time = (10)late – (-20)early = 30 min or 1/2 hr

Distance = (20*50)/[(50-20)*1/2] = 50/3 km**A shopkeeper bought 80 kg rice for Rs 384 and sold it at a loss of as much money as he received for 16 kg. Find selling price (per kg) of rice.**

A. Rs 3.84

B. Rs 4

C. Rs 3.60

D. Rs 4.50

B. Rs 4

Explanation:

C.P. of 80 kg – S.P. of 80 kg = S.P. of 16 kg

C.P. of 80 kg = S.P. of 96 kg

Find loss%, loss% = (96-80)/96 * 100 = 50/3*

Find S.P. per kg

**Ten years ago, A was half of B in age. If the ratio of their present ages in 3 : 4, what will be the total of their present ages?**

A. 15 yrs

B. 20 yrs

C. 35 yrs

D. 40 yrs

C. 35 yrs**The sum of the ages of a mother and her daughter is 50 yrs. Also 5 yrs ago, the mother’s age was 7 times the age of the daughter. What is the present age of the mother?**

A. 20 yrs

B. 32 yrs

C. 40 yrs

D. 45 yrs

C. 40 yrs

Explanation:

Mother = x, Daughetr = 50-x

5 yrs ago, x-5 = 7(50-x-5), this gives x = 40**A man purchased two cows for Rs 500. He sells the first at 12% loss and second at 8% gain. In this he neither gains nor loses. Find the selling price of the first cow?**

A. Rs 156

B. Rs 170

C. Rs 176

D. Rs 200

C. Rs 176

Explanation:

12 8

. 0

8 12

8 : 12 or 2 : 3

CP of 1st cow = 2/(2+3) * 500 = 200

SP = 88/100 * 200 = 176

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