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Quantitative Aptitude Questions for IBPS Exam Set – 32

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Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.

  1. If the length of a rectangular plot increases by 30% while its breadth remains same, what will be the ratio of the areas of new and old figures
    A. 1 : 3
    B. 13 : 10
    C. 3 : 1
    D. 4 : 7
    B. 13 : 10
    Explanation:
    Length increases by 30%, breadth by 0%
    So area increases by 30%
    Old area = a, then new area = 130/100 * a
    Ratio = 13 : 10

  2. Two cylindrical vessels with radii 15 cm and 10 cm and heights 35 cm and 15 cm resp are filled with water. If this water is poured into a cylindrical vessel 15 cm in height, then the radius of the vessel is
    A. 17.5 cm
    B. 18 cm
    C. 20 sm
    D. 25 cm
    D. 25 cm
    Explanation:
    Let radius of new vessel be ‘r’. Then
    πr2 * 15 = π * 152 * 35 + π * 102 * 15

  3. A can do a piece of work in 20 days. B is 25% more efficient than A. The number of days taken by B to do the same piece or work is
    A. 15
    B. 16
    C. 18
    D. 25
    B. 16
    Explanation:
    Ratio of efficiency of A : B is 1 : 125/100 = 4 : 5
    Then ratio of times taken by A and B = 5 : 4
    Suppose B takes ‘x’ days. So,
    5 : 4 :: 20 : x
    x = 4*20/5

  4. A and B can together finish a work in 30 days. They work together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the job?
    A. 40 days
    B. 50 days
    C. 54 days
    D. 60 days
    D. 60 days
    Explanation:
    Let A completes work in ‘x’ days. Then,
    (1/30) * 20 + (1/x) * 20 = 1

  5. The difference between a discount of 35% and two successive discounts of 20% on a certain bill was Rs 22. Find the amount of the bill.
    A. Rs 200
    B. Rs 1100
    C. Rs 2200
    D. Rs 220
    C. Rs 2200
    Explanation:
    Let the amount of bill is Rs ‘x’. then,
    65% of x – 80% of 80% of x = 22

  6. Ratio in which water is to be added to milk so as to gain 40 5/6% profit on selling the mixture on cost price of milk is
    A. 37 : 51
    B. 13 : 21
    C. 120 : 49
    D. 49 : 120
    D. 49 : 120
    Explanation:
    Water : Milk
    245/6 : 100
    245 : 600
    49 : 120

  7. In a mixture, A and B are in the ratio 2 : 3. 10 litres of the mixture is taken out and 10 litres of A is poured into it and the new ratio becomes 11 : 9. Find the amount of A in the original mixture.
    A. 12 litres
    B. 16 litres
    C. 15 litres
    D. 19 litres
    B. 16 litres
    A : B = 2 : 3
    Let total = 5x + 10
    (2x+10)/3x = 11/9
    x = 6
    Total = 5*6 + 10 = 40 litres
    A = 2/5 * 40 = 16 litres

  8. A boat takes 22 hours for travelling downstream from point A to B and coming back to point C midway between A and B. If the speed of the stream is 3 km/hr and speed of the boat in still water is 12 km/hr, then what is the distance between A and B?
    A. 120 km
    B. 180 km
    C. 270 km
    D. 210 km
    B. 180 km
    Explanation:
    Downstream speed = 12+3 = 15
    Upstream speed = 12-3 = 9
    Let the distance from A to B is x km
    downstream distance = x, upstream distance is half of x because boat goes half way upstream, then
    x/15 + (x/2)/9 = 22

  9. Oranges are bought at 11 for a rupee and an equal number more at 9 for a rupee. If these are sold at 10 for a rupee, find the loss or gain percent.
    A. 1% gain
    B. 1% loss
    C. 2% gain
    D. 2% loss
    B. 1% loss
    Explanation:
    [ 2*11*9/{10(11+9)} – 1 ] * 100 = -1%
    – indicates loss

  10. A horse and a cow were sold for Rs 540, making a profit of 25% on the horse and 20% on the cow. By selling for Rs 538, the profit would be 20% on the horse and 25% on the cow. Find the total and difference between the prices of both.
    A. Rs 420, Rs 30
    B. Rs 460, Rs 50
    C. Rs 440, Rs 40
    D. Rs 460, Rs 50
    C. Rs 440, Rs 40
    Explanation:
    H + C = 540+538 / 125%+120%
    H – C = 540-538 / 125% – 120%