Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.

**If the length of a rectangular plot increases by 30% while its breadth remains same, what will be the ratio of the areas of new and old figures**

A. 1 : 3

B. 13 : 10

C. 3 : 1

D. 4 : 7**B. 13 : 10**

Explanation:

Length increases by 30%, breadth by 0%

So area increases by 30%

Old area = a, then new area = 130/100 * a

Ratio = 13 : 10**Two cylindrical vessels with radii 15 cm and 10 cm and heights 35 cm and 15 cm resp are filled with water. If this water is poured into a cylindrical vessel 15 cm in height, then the radius of the vessel is**

A. 17.5 cm

B. 18 cm

C. 20 sm

D. 25 cm**D. 25 cm**

Explanation:

Let radius of new vessel be ‘r’. Then

πr^{2}* 15 = π * 15^{2}* 35 + π * 10^{2}* 15**A can do a piece of work in 20 days. B is 25% more efficient than A. The number of days taken by B to do the same piece or work is**

A. 15

B. 16

C. 18

D. 25**B. 16**

Explanation:

Ratio of efficiency of A : B is 1 : 125/100 = 4 : 5

Then ratio of times taken by A and B = 5 : 4

Suppose B takes ‘x’ days. So,

5 : 4 :: 20 : x

x = 4*20/5**A and B can together finish a work in 30 days. They work together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the job?**

A. 40 days

B. 50 days

C. 54 days

D. 60 days**D. 60 days**

Explanation:

Let A completes work in ‘x’ days. Then,

(1/30) * 20 + (1/x) * 20 = 1**The difference between a discount of 35% and two successive discounts of 20% on a certain bill was Rs 22. Find the amount of the bill.**

A. Rs 200

B. Rs 1100

C. Rs 2200

D. Rs 220**C. Rs 2200**

Explanation:

Let the amount of bill is Rs ‘x’. then,

65% of x – 80% of 80% of x = 22**Ratio in which water is to be added to milk so as to gain 40 5/6% profit on selling the mixture on cost price of milk is**

A. 37 : 51

B. 13 : 21

C. 120 : 49

D. 49 : 120**D. 49 : 120**

Explanation:

Water : Milk

245/6 : 100

245 : 600

49 : 120**In a mixture, A and B are in the ratio 2 : 3. 10 litres of the mixture is taken out and 10 litres of A is poured into it and the new ratio becomes 11 : 9. Find the amount of A in the original mixture.**

A. 12 litres

B. 16 litres

C. 15 litres

D. 19 litresB. 16 litres

A : B = 2 : 3

Let total = 5x + 10

(2x+10)/3x = 11/9

x = 6

Total = 5*6 + 10 = 40 litres

A = 2/5 * 40 = 16 litres**A boat takes 22 hours for travelling downstream from point A to B and coming back to point C midway between A and B. If the speed of the stream is 3 km/hr and speed of the boat in still water is 12 km/hr, then what is the distance between A and B?**

A. 120 km

B. 180 km

C. 270 km

D. 210 km**B. 180 km**

Explanation:

Downstream speed = 12+3 = 15

Upstream speed = 12-3 = 9

Let the distance from A to B is x km

downstream distance = x, upstream distance is half of x because boat goes half way upstream, then

x/15 + (x/2)/9 = 22**Oranges are bought at 11 for a rupee and an equal number more at 9 for a rupee. If these are sold at 10 for a rupee, find the loss or gain percent.**

A. 1% gain

B. 1% loss

C. 2% gain

D. 2% loss**B. 1% loss**

Explanation:

[ 2*11*9/{10(11+9)} – 1 ] * 100 = -1%

– indicates loss**A horse and a cow were sold for Rs 540, making a profit of 25% on the horse and 20% on the cow. By selling for Rs 538, the profit would be 20% on the horse and 25% on the cow. Find the total and difference between the prices of both.**

A. Rs 420, Rs 30

B. Rs 460, Rs 50

C. Rs 440, Rs 40

D. Rs 460, Rs 50**C. Rs 440, Rs 40**

Explanation:

H + C = 540+538 / 125%+120%

H – C = 540-538 / 125% – 120%

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