**Hello Aspirants.**

Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating question sample inÂ **Quadratic Equations and MiscellaneousÂ **based on prelim pattern**,** which is common for SBI,IBPS, RBI,LIC, NICL and other competitive exams.

**Q(1-5) In the following questions two equations numbered I & II are given. You have to solve both equations and mark one of the options given below.**

**I. 30XÂ² – 172X + 238 = 0**

**II. 33YÂ² â€“ 146Y + 161 =0**

1. X >Y

2. X <Y

3. X â‰¥ Y

4. X â‰¤ Y

5. X = Y or relationship cannot be establishedAnswer –**3. X â‰¥ Y**

**Explanation :**

Solution:

X = 17/5, 14/6

Y =7/3, 23/11**I. 42XÂ² + 271X + 437 = 0**

II. 63YÂ² + 316Y + 396 = 0

1. X >Y

2. X <Y

3. X â‰¥ Y

4. X â‰¤ Y

5. X = Y or relationship cannot be establishedAnswer –**2. X <Y**

**Explanation :**

X = -23/7,- 19/6

Y = -22/9,- 18/7**I. 110XÂ² + 21X + 1 = 0**

II. 345YÂ² + 53Y + 2 = 0

1. X > Y

2. X < Y

3. X â‰¥ Y

4. X â‰¤ Y

5. X = Y or relationship cannot be establishedAnswer –**2. X < Y**

**Explanation :**

Solution:

X = -1/11, -1/10

Y =-2/23, -1/15**I. XÂ² -27âˆš5X + 910 = 0**

II. YÂ² â€“31âˆš3Y + 720 = 0

1. X >Y

2. X <Y

3. X â‰¥ Y

4. X â‰¤ Y

5. X = Y or relationship cannot be establishedAnswer –**1. X >Y**

**Explanation :**

Solution:

X = 13âˆš5, 14âˆš5

Y = 16âˆš3, 15âˆš3**I. XÂ² – 2X – 399 = 0**

II.YÂ² + 43Y + 462 = 0

1. X >Y

2. X <Y

3. X â‰¥ Y

4. X â‰¤ Y

5. X = Y or relationship cannot be establishedAnswer –**1. X >Y**

**Explanation :**

Solution:

X = -19,21

Y = -21,-22**A 180m long train crosses a Man in 9 seconds. Later if the train increased its speed and crossed another 240m train in 42 sec running in the same direction at 54 Km/hr, then find the increased speed in km/hr?**

1. 5 Km/hr

2. 18 Km/hr

3. 24 Km/hr

4. 36 Km/hr

5. NoneAnswer –**2. 18 Km/hr**

**Explanation :**

train speed = 180/9 = 20

20+x-15 = 420/42

x =5 m/sec = 18 Km/hr**Sum weights of A and B are equal to the sum of weights of C and D. B is 28 Kg heavier than A. D is 32 kg heavier than C. Sum of weights of A and C is 20 Kg. Then what is the average weight of A, B, C, and D?**

1. 24

2. 25

3. 26

4. 27

5. 28Answer –**2. 25**

**Explanation :**

A+B = C+D

B = 28+A

D = 32+C

A+C = 20

A = 11, B = 39, C = 9 and D =41

Average = 100/4 = 25**The probability that Vijay will join IIT is 2/7 and that he will join NIT is 3/5.Find that probability that he will join either IIT or NIT?**

1.4/35

2.6/35

3.29/35

4.31/35

5.NoneAnswer –**4.31/35**

**Explanation :**

2/7+3/5 = 31/35**The amount received on Rs.3325 at 9% SI per annum for 4 years is same as the amount received on Rs.(3325+X) at 11% SI per annum for 3 years. Then what is the value of X?.**

1. Rs. 25

2. Rs. 50

3. Rs. 75

4. Rs. 100

5. NoneAnswer –**3. Rs. 75**

3325+3325*9*4/100 = (3325+x)*(1+33/100)

x = 75**In a vessel, the ratio of Milk and Water is 5:1. If some quantity of water is added then the ratio becomes 4:1. Now 20 liters of the mixture is withdrawn thus in final mixture Milk is 64 liters. Then find how much water is added to the initial mixture?**

1. 4 liter

2. 5 liter

3. 6 liter

4. 8 liter

5. NoneAnswer –**1. 4 liter**

**Explanation :**

5x/x+w = 4y/y

4y-4/5*20 = 64

y = 20

x = 16

w = 4

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