Hello Aspirants,
Welcome to Online Quants Test in AffairsCloud.com. We are starting LIC AAO Course 2016 and we are creating sample questions in Quants section, type of which will be asked in LIC AAO 2016 !!!
 Click Here to View Stratus: LIC AAO 2016 Course
 LIC AAO 2016: Reasoning Test
 LIC AAO 2016: Quants Test
 LIC AAO 2016: General Awareness Test
 LIC AAO 2016: Computer Awareness Test
 LIC AAO 2016: English Test
Help: Share Our LIC AAO 2016 Course page to your Friends & FB Groups
_____________________________________________________________________
Quizsummary
0 of 15 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 15 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 11
 12
 13
 14
 15
 Answered
 Review

Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeTwo schemes provide 6% per annum and 4% per annum simple interest. A total of Rs 7000 is deposited in both schemes. If after 5 years, the total interest received is Rs 1600, what is the sum deposited at 6% per annum?
Correct
Explanation:
Find the rate % of 5 yrs:
1600 = 7000*r*5 / 100, this gives r = 32/7%
By the method of allegation:
6……………………………..…… 4
………….….32/7
32/7 – 4 = 4/7 ……………….6 – 32/7 = 10/7
4/7 : 10/7 or 2 : 5
Amount at 6% = 2/(2+5) * 7000 = 2000Incorrect
Explanation:
Find the rate % of 5 yrs:
1600 = 7000*r*5 / 100, this gives r = 32/7%
By the method of allegation:
6……………………………..…… 4
………….….32/7
32/7 – 4 = 4/7 ……………….6 – 32/7 = 10/7
4/7 : 10/7 or 2 : 5
Amount at 6% = 2/(2+5) * 7000 = 2000 
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeA and B starts a business and invests Rs 2100 and Rs 3100 respectively. It was decided that A will get 25% of the profit as his salary and after deducting this, the profit will be divided among them. If at the end of year, a profit of Rs 1040 was received, how much will A get?
Correct
Explanation:
2100 : 3100
21 : 31
A gets salary = (25/100)*1040 = 260
So profit left = 1040 – 260 = 780
Now A gets his share as = (21/52) * 780 = 315
So total of A = 260+315Incorrect
Explanation:
2100 : 3100
21 : 31
A gets salary = (25/100)*1040 = 260
So profit left = 1040 – 260 = 780
Now A gets his share as = (21/52) * 780 = 315
So total of A = 260+315 
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeA man can row 10 km/hr in still water. When the river is running at 4 km/hr, it takes him 2 hours to row to a place and come back. How far is the place?
Correct
Explanation:
B is speed of boat in still water, R is speed of stream
Time is total time taken for upstream and downstream
Distance = time * [B^2 – R^2] / 2*B
=2 * [10^2 – 4^2] / 2*10Incorrect
Explanation:
B is speed of boat in still water, R is speed of stream
Time is total time taken for upstream and downstream
Distance = time * [B^2 – R^2] / 2*B
=2 * [10^2 – 4^2] / 2*10 
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeA bucket contains 2 red balls, 4 blue balls, and 6 white balls. Two balls are drawn at random. What is the probability that they are not of same color?
Correct
Explanation:
Three cases
Case 1: one red, 1 blue
Prob = ^{2}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/33
Case 2: one red, 1 white
Prob = ^{2}C_{1} × ^{6}C_{1} / ^{12}C_{2} = 2/11.
Case 3: one white, 1 blue
Prob = ^{6}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/11
Add all casesIncorrect
Explanation:
Three cases
Case 1: one red, 1 blue
Prob = ^{2}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/33
Case 2: one red, 1 white
Prob = ^{2}C_{1} × ^{6}C_{1} / ^{12}C_{2} = 2/11.
Case 3: one white, 1 blue
Prob = ^{6}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/11
Add all cases 
Question 5 of 15
5. Question
1 pointsCategory: Quantitative AptitudeIn how many ways the letters of the word REVIEW can be arranged such that all consonants are together?
Correct
Explanation:
E, I, E, RVW
4 letters 4!, but since E is twice so 4!/2! = 12
And arrangement of RVW is 3!
So total 12 * 3!Incorrect
Explanation:
E, I, E, RVW
4 letters 4!, but since E is twice so 4!/2! = 12
And arrangement of RVW is 3!
So total 12 * 3! 
Question 6 of 15
6. Question
1 pointsCategory: Quantitative AptitudeFind the curved surface area of a cone whose radius of base is 70 cm and volume is 862400 cm^{3}.
Correct
Explanation:
(1/3)*(22/7)*70^{2} *h = 862400
Solve, h = 168 cm
So l = √(168) ^{2} + 70^{2} =182 cm
So curved surface area is (22/7)*70*182Incorrect
Explanation:
(1/3)*(22/7)*70^{2} *h = 862400
Solve, h = 168 cm
So l = √(168) ^{2} + 70^{2} =182 cm
So curved surface area is (22/7)*70*182 
Question 7 of 15
7. Question
1 pointsCategory: Quantitative AptitudeThe outer and the inner perimeters of a circular path is in the ratio 11 : 7. If the path is 4 m wide, what is the diameter of the inner circle?
Correct
Explanation:
Outer/inner = 2ᴨr/2ᴨR = 11/7
So r/R = 11/7, so r = (11/7)R
rR = 4, so (11/7)R – R = 4
R = 7, so diameter is 14Incorrect
Explanation:
Outer/inner = 2ᴨr/2ᴨR = 11/7
So r/R = 11/7, so r = (11/7)R
rR = 4, so (11/7)R – R = 4
R = 7, so diameter is 14 
Question 8 of 15
8. Question
1 pointsCategory: Quantitative AptitudeFind the least number which when divided by 12, 15, 20 and 24 leaves remainders 7, 10, 15 and 19 respectively
Correct
Explanation:
Since 127 = 5, 1510 = 5, 2015 = 5, 2419 = 5
So answer will be the LCM of these numbers – 5
So 120 – 5Incorrect
Explanation:
Since 127 = 5, 1510 = 5, 2015 = 5, 2419 = 5
So answer will be the LCM of these numbers – 5
So 120 – 5 
Question 9 of 15
9. Question
1 pointsCategory: Quantitative AptitudeThe difference between simple interest earned after 5 years at 8% p.a and compound interest earned after 3 years at 10% p.a. is Rs 1932. What is the principal amount?
Correct
Explanation:
P*5*8/100 – [P[1 + 10/100]^{3} – P] = 1932
P [40/100 – 1331/1000 + 1] = 1932
P [69/1000] = 1932Incorrect
Explanation:
P*5*8/100 – [P[1 + 10/100]^{3} – P] = 1932
P [40/100 – 1331/1000 + 1] = 1932
P [69/1000] = 1932 
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeHCF and LCM of two numbers is 5 and 225 respectively and the sum of these two numbers is 70. Find the sum of the reciprocals of these numbers.
Correct
Explanation:
x + y = 70, xy = 5*225 = 1125
sum of reciprocals = 1/x + 1/y = (x+y)/xy = 70/1125Incorrect
Explanation:
x + y = 70, xy = 5*225 = 1125
sum of reciprocals = 1/x + 1/y = (x+y)/xy = 70/1125 
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
3x^{2} – 37x + 114 = 0, 2y^{2} – 19y + 44 = 0
Correct
Explanation:
3x^{2} – 37x + 114 = 0
3x^{2} – 18x – 19x + 114 = 0
Gives x = 6, 19/3
2y^{2} – 19y + 44 = 0
2y^{2} – 8y – 11y + 44 = 0
Gives y = 4, 11/2
Put on number line
4…… 11/2 ….. 6 …… 19/3Incorrect
Explanation:
3x^{2} – 37x + 114 = 0
3x^{2} – 18x – 19x + 114 = 0
Gives x = 6, 19/3
2y^{2} – 19y + 44 = 0
2y^{2} – 8y – 11y + 44 = 0
Gives y = 4, 11/2
Put on number line
4…… 11/2 ….. 6 …… 19/3 
Question 12 of 15
12. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
3x^{2} + 8x – 3 = 0, 4y^{2} – 4y – 3 = 0
Correct
Explanation:
3x^{2} + 8x – 3 = 0
3x^{2} + 9x – x – 3 = 0
Gives x = 3, 1/3
4y^{2} – 4y – 3 = 0
4y^{2} + 2y – 6y – 3 = 0
Gives y = 1/2, 3/2
Put on number line
3……. 1/2……. 1/3… 3/2
Alternate valuesIncorrect
Explanation:
3x^{2} + 8x – 3 = 0
3x^{2} + 9x – x – 3 = 0
Gives x = 3, 1/3
4y^{2} – 4y – 3 = 0
4y^{2} + 2y – 6y – 3 = 0
Gives y = 1/2, 3/2
Put on number line
3……. 1/2……. 1/3… 3/2
Alternate values 
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
5x^{2} + 3x – 2 = 0, 3y^{2} + 8y + 5 = 0
Correct
Explanation:
5x^{2} + 3x – 2 = 0
5x^{2} + 5x – 2x – 2 = 0
Gives x = 1, 2/5
3y^{2} + 8y + 5 = 0
3y^{2} + 3y + 5y + 5 = 0
Gives y = 5/3, 1
Put on number line
5/3… 1……. 2/5Incorrect
Explanation:
5x^{2} + 3x – 2 = 0
5x^{2} + 5x – 2x – 2 = 0
Gives x = 1, 2/5
3y^{2} + 8y + 5 = 0
3y^{2} + 3y + 5y + 5 = 0
Gives y = 5/3, 1
Put on number line
5/3… 1……. 2/5 
Question 14 of 15
14. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
3x^{2} + 2x – 5 = 0, 9y^{2} + 3y – 20 = 0
Correct
Explanation:
3x^{2} + 2x – 5 = 0
3x^{2} – 3x + 5x – 5 = 0
Gives x = 5/3, 1
9y^{2} + 3y – 20 = 0
9y^{2} – 12 y + 15y – 20 = 0
Gives y = 5/3, 4/3
Put on number line
5/3…………. 1………. 4/3
When x = 1, x > y=5/3, and x < y = 4/3 So relation cant be determined.Incorrect
Explanation:
3x^{2} + 2x – 5 = 0
3x^{2} – 3x + 5x – 5 = 0
Gives x = 5/3, 1
9y^{2} + 3y – 20 = 0
9y^{2} – 12 y + 15y – 20 = 0
Gives y = 5/3, 4/3
Put on number line
5/3…………. 1………. 4/3
When x = 1, x > y=5/3, and x < y = 4/3 So relation cant be determined. 
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
4x^{2} + 21x + 5 = 0, 2y^{2} – 7y + 3 = 0
Correct
Explanation:
4x^{2} + 21x + 5 = 0
4x^{2} + 20x + x + 5 = 0
Gives x = 5, 1/4
2y^{2} – 7y + 3 = 0
2y^{2} – 7y – y + 3 = 0
Gives y= 1/2 , 3
Put on number line
5…… 1/4…….. 1/2…….. 3Incorrect
Explanation:
4x^{2} + 21x + 5 = 0
4x^{2} + 20x + x + 5 = 0
Gives x = 5, 1/4
2y^{2} – 7y + 3 = 0
2y^{2} – 7y – y + 3 = 0
Gives y= 1/2 , 3
Put on number line
5…… 1/4…….. 1/2…….. 3
_____________________________________________________________________
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.