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Question 1 of 15

1. Question

1 points

Category: Quantitative Aptitude

Two schemes provide 6% per annum and 4% per annum simple interest. A total of Rs 7000 is deposited in both schemes. If after 5 years, the total interest received is Rs 1600, what is the sum deposited at 6% per annum?

Correct

Explanation:
Find the rate % of 5 yrs:
1600 = 7000*r*5 / 100, this gives r = 32/7%
By the method of allegation:
6……………………………..…… 4
………….….32/7
32/7 – 4 = 4/7 ……………….6 – 32/7 = 10/7
4/7 : 10/7 or 2 : 5
Amount at 6% = 2/(2+5) * 7000 = 2000

Incorrect

Explanation:
Find the rate % of 5 yrs:
1600 = 7000*r*5 / 100, this gives r = 32/7%
By the method of allegation:
6……………………………..…… 4
………….….32/7
32/7 – 4 = 4/7 ……………….6 – 32/7 = 10/7
4/7 : 10/7 or 2 : 5
Amount at 6% = 2/(2+5) * 7000 = 2000

Question 2 of 15

2. Question

1 points

Category: Quantitative Aptitude

A and B starts a business and invests Rs 2100 and Rs 3100 respectively. It was decided that A will get 25% of the profit as his salary and after deducting this, the profit will be divided among them. If at the end of year, a profit of Rs 1040 was received, how much will A get?

Correct

Explanation:
2100 : 3100
21 : 31
A gets salary = (25/100)*1040 = 260
So profit left = 1040 – 260 = 780
Now A gets his share as = (21/52) * 780 = 315
So total of A = 260+315

Incorrect

Explanation:
2100 : 3100
21 : 31
A gets salary = (25/100)*1040 = 260
So profit left = 1040 – 260 = 780
Now A gets his share as = (21/52) * 780 = 315
So total of A = 260+315

Question 3 of 15

3. Question

1 points

Category: Quantitative Aptitude

A man can row 10 km/hr in still water. When the river is running at 4 km/hr, it takes him 2 hours to row to a place and come back. How far is the place?

Correct

Explanation:
B is speed of boat in still water, R is speed of stream
Time is total time taken for upstream and downstream
Distance = time * [B^2 – R^2] / 2*B
=2 * [10^2 – 4^2] / 2*10

Incorrect

Explanation:
B is speed of boat in still water, R is speed of stream
Time is total time taken for upstream and downstream
Distance = time * [B^2 – R^2] / 2*B
=2 * [10^2 – 4^2] / 2*10

Question 4 of 15

4. Question

1 points

Category: Quantitative Aptitude

A bucket contains 2 red balls, 4 blue balls, and 6 white balls. Two balls are drawn at random. What is the probability that they are not of same color?

Correct

Explanation:
Three cases
Case 1: one red, 1 blue
Prob = ^{2}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/33
Case 2: one red, 1 white
Prob = ^{2}C_{1} × ^{6}C_{1} / ^{12}C_{2} = 2/11.
Case 3: one white, 1 blue
Prob = ^{6}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/11
Add all cases

Incorrect

Explanation:
Three cases
Case 1: one red, 1 blue
Prob = ^{2}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/33
Case 2: one red, 1 white
Prob = ^{2}C_{1} × ^{6}C_{1} / ^{12}C_{2} = 2/11.
Case 3: one white, 1 blue
Prob = ^{6}C_{1} × ^{4}C_{1} / ^{12}C_{2} = 4/11
Add all cases

Question 5 of 15

5. Question

1 points

Category: Quantitative Aptitude

In how many ways the letters of the word REVIEW can be arranged such that all consonants are together?

Correct

Explanation:
E, I, E, RVW
4 letters 4!, but since E is twice so 4!/2! = 12
And arrangement of RVW is 3!
So total 12 * 3!

Incorrect

Explanation:
E, I, E, RVW
4 letters 4!, but since E is twice so 4!/2! = 12
And arrangement of RVW is 3!
So total 12 * 3!

Question 6 of 15

6. Question

1 points

Category: Quantitative Aptitude

Find the curved surface area of a cone whose radius of base is 70 cm and volume is 862400 cm^{3}.

Correct

Explanation:
(1/3)*(22/7)*70^{2} *h = 862400
Solve, h = 168 cm
So l = √(168) ^{2} + 70^{2} =182 cm
So curved surface area is (22/7)*70*182

Incorrect

Explanation:
(1/3)*(22/7)*70^{2} *h = 862400
Solve, h = 168 cm
So l = √(168) ^{2} + 70^{2} =182 cm
So curved surface area is (22/7)*70*182

Question 7 of 15

7. Question

1 points

Category: Quantitative Aptitude

The outer and the inner perimeters of a circular path is in the ratio 11 : 7. If the path is 4 m wide, what is the diameter of the inner circle?

Correct

Explanation:
Outer/inner = 2ᴨr/2ᴨR = 11/7
So r/R = 11/7, so r = (11/7)R
r-R = 4, so (11/7)R – R = 4
R = 7, so diameter is 14

Incorrect

Explanation:
Outer/inner = 2ᴨr/2ᴨR = 11/7
So r/R = 11/7, so r = (11/7)R
r-R = 4, so (11/7)R – R = 4
R = 7, so diameter is 14

Question 8 of 15

8. Question

1 points

Category: Quantitative Aptitude

Find the least number which when divided by 12, 15, 20 and 24 leaves remainders 7, 10, 15 and 19 respectively

Correct

Explanation:
Since 12-7 = 5, 15-10 = 5, 20-15 = 5, 24-19 = 5
So answer will be the LCM of these numbers – 5
So 120 – 5

Incorrect

Explanation:
Since 12-7 = 5, 15-10 = 5, 20-15 = 5, 24-19 = 5
So answer will be the LCM of these numbers – 5
So 120 – 5

Question 9 of 15

9. Question

1 points

Category: Quantitative Aptitude

The difference between simple interest earned after 5 years at 8% p.a and compound interest earned after 3 years at 10% p.a. is Rs 1932. What is the principal amount?

HCF and LCM of two numbers is 5 and 225 respectively and the sum of these two numbers is 70. Find the sum of the reciprocals of these numbers.

Correct

Explanation:
x + y = 70, xy = 5*225 = 1125
sum of reciprocals = 1/x + 1/y = (x+y)/xy = 70/1125

Incorrect

Explanation:
x + y = 70, xy = 5*225 = 1125
sum of reciprocals = 1/x + 1/y = (x+y)/xy = 70/1125

Question 11 of 15

11. Question

1 points

Category: Quantitative Aptitude

Directions (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

3x^{2} – 37x + 114 = 0, 2y^{2} – 19y + 44 = 0

Correct

Explanation:
3x^{2} – 37x + 114 = 0
3x^{2} – 18x – 19x + 114 = 0
Gives x = 6, 19/3
2y^{2} – 19y + 44 = 0
2y^{2} – 8y – 11y + 44 = 0
Gives y = 4, 11/2
Put on number line
4…… 11/2 ….. 6 …… 19/3

Incorrect

Explanation:
3x^{2} – 37x + 114 = 0
3x^{2} – 18x – 19x + 114 = 0
Gives x = 6, 19/3
2y^{2} – 19y + 44 = 0
2y^{2} – 8y – 11y + 44 = 0
Gives y = 4, 11/2
Put on number line
4…… 11/2 ….. 6 …… 19/3

Question 12 of 15

12. Question

1 points

Category: Quantitative Aptitude

Directions (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

3x^{2} + 8x – 3 = 0, 4y^{2} – 4y – 3 = 0

Correct

Explanation:
3x^{2} + 8x – 3 = 0
3x^{2} + 9x – x – 3 = 0
Gives x = -3, 1/3
4y^{2} – 4y – 3 = 0
4y^{2} + 2y – 6y – 3 = 0
Gives y = -1/2, 3/2
Put on number line
-3……. -1/2……. 1/3… 3/2
Alternate values

Incorrect

Explanation:
3x^{2} + 8x – 3 = 0
3x^{2} + 9x – x – 3 = 0
Gives x = -3, 1/3
4y^{2} – 4y – 3 = 0
4y^{2} + 2y – 6y – 3 = 0
Gives y = -1/2, 3/2
Put on number line
-3……. -1/2……. 1/3… 3/2
Alternate values

Question 13 of 15

13. Question

1 points

Category: Quantitative Aptitude

Directions (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

5x^{2} + 3x – 2 = 0, 3y^{2} + 8y + 5 = 0

Correct

Explanation:
5x^{2} + 3x – 2 = 0
5x^{2} + 5x – 2x – 2 = 0
Gives x = -1, 2/5
3y^{2} + 8y + 5 = 0
3y^{2} + 3y + 5y + 5 = 0
Gives y = -5/3, -1
Put on number line
-5/3… -1……. 2/5

Incorrect

Explanation:
5x^{2} + 3x – 2 = 0
5x^{2} + 5x – 2x – 2 = 0
Gives x = -1, 2/5
3y^{2} + 8y + 5 = 0
3y^{2} + 3y + 5y + 5 = 0
Gives y = -5/3, -1
Put on number line
-5/3… -1……. 2/5

Question 14 of 15

14. Question

1 points

Category: Quantitative Aptitude

Directions (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

3x^{2} + 2x – 5 = 0, 9y^{2} + 3y – 20 = 0

Correct

Explanation:
3x^{2} + 2x – 5 = 0
3x^{2} – 3x + 5x – 5 = 0
Gives x = -5/3, 1
9y^{2} + 3y – 20 = 0
9y^{2} – 12 y + 15y – 20 = 0
Gives y = -5/3, 4/3
Put on number line
-5/3…………. 1………. 4/3
When x = 1, x > y=-5/3, and x < y = 4/3
So relation cant be determined.

Incorrect

Explanation:
3x^{2} + 2x – 5 = 0
3x^{2} – 3x + 5x – 5 = 0
Gives x = -5/3, 1
9y^{2} + 3y – 20 = 0
9y^{2} – 12 y + 15y – 20 = 0
Gives y = -5/3, 4/3
Put on number line
-5/3…………. 1………. 4/3
When x = 1, x > y=-5/3, and x < y = 4/3
So relation cant be determined.

Question 15 of 15

15. Question

1 points

Category: Quantitative Aptitude

Directions (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –

4x^{2} + 21x + 5 = 0, 2y^{2} – 7y + 3 = 0

Correct

Explanation:
4x^{2} + 21x + 5 = 0
4x^{2} + 20x + x + 5 = 0
Gives x = -5, -1/4
2y^{2} – 7y + 3 = 0
2y^{2} – 7y – y + 3 = 0
Gives y= 1/2 , 3
Put on number line
-5…… -1/4…….. 1/2…….. 3

Incorrect

Explanation:
4x^{2} + 21x + 5 = 0
4x^{2} + 20x + x + 5 = 0
Gives x = -5, -1/4
2y^{2} – 7y + 3 = 0
2y^{2} – 7y – y + 3 = 0
Gives y= 1/2 , 3
Put on number line
-5…… -1/4…….. 1/2…….. 3