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Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeThe total surface area of a cylinder is 3080 cm^{2}. Find the volume of this cylinder if the height of cylinder and radius of its base are in the ratio 3 : 2.
Correct
Explanation:
Height = 3x, radius = 2x
Total surface area = 2*(22/7)*(2x)*(3x+2x) = 3080
Solve, x^{2} = 49, so x = 7
So Height = 3x = 21 cm, radius = 2x = 14 cm
Volume = (22/7)*(14)^{2}*21 = 12936Incorrect
Explanation:
Height = 3x, radius = 2x
Total surface area = 2*(22/7)*(2x)*(3x+2x) = 3080
Solve, x^{2} = 49, so x = 7
So Height = 3x = 21 cm, radius = 2x = 14 cm
Volume = (22/7)*(14)^{2}*21 = 12936 
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeThere are two mixtures A and B containing water and milk. A contains 20% water and B contains 30% water. Some quantity is taken from A and double this quantity from B, they are mixed to form another mixture C. What is the percentage of milk in mixture C?
Correct
Explanation:
Let x litres taken from mixture A, then 2x litres from mixture B. So ratio of milk to water in mixture C =
80% of x + 70% of 2x : 20% of x + 30% of 2x
= (80/100) + (140/100) : (20/100) + (60/100)
= 11 : 4
So % of milk = [11/(11+4)] * 100Incorrect
Explanation:
Let x litres taken from mixture A, then 2x litres from mixture B. So ratio of milk to water in mixture C =
80% of x + 70% of 2x : 20% of x + 30% of 2x
= (80/100) + (140/100) : (20/100) + (60/100)
= 11 : 4
So % of milk = [11/(11+4)] * 100 
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeA committee of 4 members is to be made from 5 men and 5 women. What is the probability that the committee will contain more men than women?
Correct
Explanation:
Case 1: all 4 men, 0 woman
Prob. = ^{5}C_{4}/ ^{10}C_{4} = 1/42
Case 2: 3 men, 1 woman
Prob. = ^{5}C_{3} * ^{5}C_{1} / ^{10}C_{4} = 5/21
Add both cases = 1/42 + 5/21 = 11/42Incorrect
Explanation:
Case 1: all 4 men, 0 woman
Prob. = ^{5}C_{4}/ ^{10}C_{4} = 1/42
Case 2: 3 men, 1 woman
Prob. = ^{5}C_{3} * ^{5}C_{1} / ^{10}C_{4} = 5/21
Add both cases = 1/42 + 5/21 = 11/42 
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeAn article is sold at 20% loss. If both the CP and SP of article are increased by Rs 20 and Rs 100 respectively, there is a profit of 5%. What is the original cost price of the article?
Correct
Explanation:
CP = x, then SP = (80/100)*x = 4x/5
New CP = (x+20), new SP = (4x/5 + 100), profit% = 5
So (4x/5 + 100) = (105/100) * (x+20)
(4x/5 + 100) = (21/20) * (x+20)
20*100 – 20*21 = 21x – (4x/5)*20
20(10021) = 5x
Solve, x = 316Incorrect
Explanation:
CP = x, then SP = (80/100)*x = 4x/5
New CP = (x+20), new SP = (4x/5 + 100), profit% = 5
So (4x/5 + 100) = (105/100) * (x+20)
(4x/5 + 100) = (21/20) * (x+20)
20*100 – 20*21 = 21x – (4x/5)*20
20(10021) = 5x
Solve, x = 316 
Question 5 of 15
5. Question
1 pointsCategory: Quantitative Aptitude3/5th of work is completed by 20 men in 10 days working 6 hours each day. Now the remaining work is to be completed by some number of women in 10 days working 8 hours each day. If 4 women do as much work as is done by 2 men in one day, find the number of women required to complete the remaining work?
Correct
Explanation:
4 w = 2m, so 1 m = 2w
Let x men have to complete remaining (2/5th) work in 10 days working 8 hrs each day. so
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(2/5) = x*10*8*(3/5)
Solve, x = 10 men
Since, 1 m = 2w, so 10 men = 20 womenIncorrect
Explanation:
4 w = 2m, so 1 m = 2w
Let x men have to complete remaining (2/5th) work in 10 days working 8 hrs each day. so
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(2/5) = x*10*8*(3/5)
Solve, x = 10 men
Since, 1 m = 2w, so 10 men = 20 women 
Question 6 of 15
6. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The pie chart below shows the percentage of cars which each company A, B, C, D, and E produces in a week out of total 22,000 cars produced.
The table shows the ratio cars produced by each of the companies in their Mumbai and Pune plants.
Companies Ratio of the number of cars produced – Mumbai : Pune A 6 5 B 7 4 C 7 3 D 4 1 E 3 2 How many cars did company B produce in Mumbai in a week?
Correct
Explanation:
[7/(7+4)] * (20/100) * 22,000 = 2800Incorrect
Explanation:
[7/(7+4)] * (20/100) * 22,000 = 2800 
Question 7 of 15
7. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The pie chart below shows the percentage of cars which each company A, B, C, D, and E produces in a week out of total 22,000 cars produced.
The table shows the ratio cars produced by each of the companies in their Mumbai and Pune plants.
Companies Ratio of the number of cars produced – Mumbai : Pune A 6 5 B 7 4 C 7 3 D 4 1 E 3 2 Total cars produced by company A is what per cent more than total cars produced by company D?
Correct
Explanation:
Total cars by A = (25/100) * 22,000 = 5500
Cars produced by D = (15/100) * 22,000 = 3300
So required % = (55003300)/3300 * 100Incorrect
Explanation:
Total cars by A = (25/100) * 22,000 = 5500
Cars produced by D = (15/100) * 22,000 = 3300
So required % = (55003300)/3300 * 100 
Question 8 of 15
8. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The pie chart below shows the percentage of cars which each company A, B, C, D, and E produces in a week out of total 22,000 cars produced.
The table shows the ratio cars produced by each of the companies in their Mumbai and Pune plants.
Companies Ratio of the number of cars produced – Mumbai : Pune A 6 5 B 7 4 C 7 3 D 4 1 E 3 2 What is the total number of cars produced by companies A, B, C, and E together in Pune?
Correct
Explanation:
By A in Pune = (5/11) * (25/100) * 22000 = 2500
By B in Pune = (4/11) * (20/100) * 22000 = 1600
By C in Pune = (3/10) * (12/100) * 22000 = 792
By E in Pune = (2/5) * (18/100) * 22000 = 1584
Add allIncorrect
Explanation:
By A in Pune = (5/11) * (25/100) * 22000 = 2500
By B in Pune = (4/11) * (20/100) * 22000 = 1600
By C in Pune = (3/10) * (12/100) * 22000 = 792
By E in Pune = (2/5) * (18/100) * 22000 = 1584
Add all 
Question 9 of 15
9. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The pie chart below shows the percentage of cars which each company A, B, C, D, and E produces in a week out of total 22,000 cars produced.
The table shows the ratio cars produced by each of the companies in their Mumbai and Pune plants.
Companies Ratio of the number of cars produced – Mumbai : Pune A 6 5 B 7 4 C 7 3 D 4 1 E 3 2 Which of the following company produce 2nd lowest in number of cars in Pune?
Correct
Explanation:
By D in Pune = (1/5) * (15/100) * 22000 = 660Incorrect
Explanation:
By D in Pune = (1/5) * (15/100) * 22000 = 660 
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeDirections (6–10) Study the given line graph carefully and answer the questions that follow.
The pie chart below shows the percentage of cars which each company A, B, C, D, and E produces in a week out of total 22,000 cars produced.
The table shows the ratio cars produced by each of the companies in their Mumbai and Pune plants.
Companies Ratio of the number of cars produced – Mumbai : Pune A 6 5 B 7 4 C 7 3 D 4 1 E 3 2 What is the difference between the number of cars produced by companies B and C in Mumbai?
Correct
Explanation:
From question 6: By B in Mumbai = (7/11) * (20/100) * 22000 = 2800
By C in Mumbai = (7/10) * (12/100) * 22000 = 1848
Difference = 28001848Incorrect
Explanation:
From question 6: By B in Mumbai = (7/11) * (20/100) * 22000 = 2800
By C in Mumbai = (7/10) * (12/100) * 22000 = 1848
Difference = 28001848 
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeIn a family, age of father is three times the sum of ages of his 2 children Monu and Sonu. 5 years from now, the sum of ages of Monu and Sonu will be half the age of their father. What will be the total of their ages, 10 years from now?
Correct
Explanation:
Let (Monu+Sonu)’s present age= x
Then father’s present age = 3x
After 5 years, (x+5+5) = 1/2 (3x+5) [Add 5 to monu’s and sonu’s age]
Solve, x = 15
Sum of present ages = x+3x = 4x = 60
So after 10 years, add 10 age to all of them = 60+10+10+10Incorrect
Explanation:
Let (Monu+Sonu)’s present age= x
Then father’s present age = 3x
After 5 years, (x+5+5) = 1/2 (3x+5) [Add 5 to monu’s and sonu’s age]
Solve, x = 15
Sum of present ages = x+3x = 4x = 60
So after 10 years, add 10 age to all of them = 60+10+10+10 
Question 12 of 15
12. Question
1 pointsCategory: Quantitative AptitudeA and B started a business by investing Rs 10,000 and Rs 12,000 respectively. After 4 months they withdrew their half money and after another 4 Months they again withdrew their half of money of previous investment. If at the end of year A got Rs 10,500 as share of his profit, then what is the total profit made at the end of year?
Correct
Explanation:
10000*4 + 5000*4 + 2500*4 : 12,000*4 + 6000*4 + 3000*4
100 + 50 + 25 : 120 + 60 + 30
20 + 10 + 5 : 24 + 12 + 6
35 : 42
So (35/77) * x = 10,500
Solve, x = 23,100Incorrect
Explanation:
10000*4 + 5000*4 + 2500*4 : 12,000*4 + 6000*4 + 3000*4
100 + 50 + 25 : 120 + 60 + 30
20 + 10 + 5 : 24 + 12 + 6
35 : 42
So (35/77) * x = 10,500
Solve, x = 23,100 
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeA work which is completed by 24 men in 12 days is completed by 36 women in 14 days. 36 men started the work and worked for 6 days, after which they are replaced by some women. If the remaining work is to be completed in 3 days, what is the number of women required to be employed?
Correct
Explanation:
24 m in 12 days, so 36 men in (24*12)/38 = 8 days
They did work for 6 days, so work completed by them is (6/8) = 3/4
Remaining work = 1 – 3/4 = 1/4
36 women do 1 work in 14 days
Let x women have to complete 1/4 of work in 3 days, so
36*14*(1/4) = x*3*(1)
Solve, x = 42 womenIncorrect
Explanation:
24 m in 12 days, so 36 men in (24*12)/38 = 8 days
They did work for 6 days, so work completed by them is (6/8) = 3/4
Remaining work = 1 – 3/4 = 1/4
36 women do 1 work in 14 days
Let x women have to complete 1/4 of work in 3 days, so
36*14*(1/4) = x*3*(1)
Solve, x = 42 women 
Question 14 of 15
14. Question
1 pointsCategory: Quantitative AptitudeMonthly salaries of A and B is in the ratio 3 : 5 and that of C and B is 5 : 4 respectively. If there total monthly salary is Rs 1,33,000, then what is the combined monthly salary of B and C?
Correct
Explanation:
A/B = 3/5 , B/C = 4/5
So A : B : C = 3*4 : 5*4 : 5*5 = 12 : 20 : 25
Combined salary of B and C = (20+25)/(12+20+25) * 1,33,000Incorrect
Explanation:
A/B = 3/5 , B/C = 4/5
So A : B : C = 3*4 : 5*4 : 5*5 = 12 : 20 : 25
Combined salary of B and C = (20+25)/(12+20+25) * 1,33,000 
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeA rectangular sheet of 0.01 m thickness is to be made by hammering down a cube of side 6 m. If the sides of the sheet are required to be in the ratio 3 : 2, what is the largest side of sheet?
Correct
Explanation:
Sides = 3x and 2x
Now vol. of rectanglular sheet = vol. of cube
3x * 2x * (0.01) = 6*6 *6
Solve, x = 0.6
Largest side = 3x = 1.8Incorrect
Explanation:
Sides = 3x and 2x
Now vol. of rectanglular sheet = vol. of cube
3x * 2x * (0.01) = 6*6 *6
Solve, x = 0.6
Largest side = 3x = 1.8
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