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Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeDistance between point P and Q is 480 km. A train starts from point P at 6:00 AM with 60 km/hr towards Q. Another train starts from point Q towards P at 7:00 AM with 80 km/kr. At what time the trains will meet?
Correct
Explanation:
When 2nd train starts i.e. at 7 AM (1 hr after 6 AM), distance covered by first train is 60 km (i.e. in 1 hr).
Now 2nd train also starts and distance between them is now (480-60) = 420 km
Both coming in opposite direction, so relative speed = (60+80) = 140 km/hr
So time = 7:00 AM + (420/140) = 7:00 AM +3 hrs = 10:00 AMIncorrect
Explanation:
When 2nd train starts i.e. at 7 AM (1 hr after 6 AM), distance covered by first train is 60 km (i.e. in 1 hr).
Now 2nd train also starts and distance between them is now (480-60) = 420 km
Both coming in opposite direction, so relative speed = (60+80) = 140 km/hr
So time = 7:00 AM + (420/140) = 7:00 AM +3 hrs = 10:00 AM -
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeA and B started a business by investing Rs 5000 and Rs 6000 respectively. After 4 months C came with investment of Rs 7000 and B withdrew his whole amount. Now after another 4 months, B reinvested the money as before and A withdrew half of his money. If at the end of year the total profit is Rs 22,000, what is the difference between the share of profit that C gets as compared to his investment?
Correct
Explanation:
A invested 5000 for 8 months and then 2500 for 4 months. B invested 6000 for initial 4 months and then for last 4 months i.e. for 8 months. C invested 7000 for (12-4)= 8 months.
So A : B : C is
5000*8 + 2500*4 : 6000*8 : 7000*8
50*8 + 25*4 : 60*8 : 70*8
50*2 + 25 : 60*2 : 70*2
10*2 + 5 : 12*2 : 14*2
25 : 24 : 28
So C got = [28/(25+24+28)] * 22,000 = 8000
So xtra money C got is 8000-7000Incorrect
Explanation:
A invested 5000 for 8 months and then 2500 for 4 months. B invested 6000 for initial 4 months and then for last 4 months i.e. for 8 months. C invested 7000 for (12-4)= 8 months.
So A : B : C is
5000*8 + 2500*4 : 6000*8 : 7000*8
50*8 + 25*4 : 60*8 : 70*8
50*2 + 25 : 60*2 : 70*2
10*2 + 5 : 12*2 : 14*2
25 : 24 : 28
So C got = [28/(25+24+28)] * 22,000 = 8000
So xtra money C got is 8000-7000 -
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeFrom a bag containing 7 white and 5 black balls, 2 balls are drawn one by one without replacement. Find the probability that either both balls are white in color or both are different colored?
Correct
Explanation:
Case 1: When both white in color: prob. = 7/12 * 6/11 = 7/22 or 7C2/12C2 = 7/22
Case 2: When both different:
7C1 * 5C1/12C2 = 35/66
Now add both cases: prob. = 7/22 + 35/66 = 56/66 = 28/33Incorrect
Explanation:
Case 1: When both white in color: prob. = 7/12 * 6/11 = 7/22 or 7C2/12C2 = 7/22
Case 2: When both different:
7C1 * 5C1/12C2 = 35/66
Now add both cases: prob. = 7/22 + 35/66 = 56/66 = 28/33 -
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeTwo varieties of rice are mixed in the ratio 5 : 3. The mixture is sold at a profit of 10% for Rs 24.53 per kg. If the value of 1st variety of rice is Rs 20.50 per kg, how much is the cost of the 2nd variety of rice (per kg)?
Correct
Explanation:
SP = 24.53, profit = 10%, so CP = (100/110)*24.53 = Rs 22.30
1st rice………………2nd rice
20.50……………………..x
…………….22.30
x-22.30…………………..1.80
So (x – 22.30)/ 1.80 = 5/3
Solve, x = 25.30Incorrect
Explanation:
SP = 24.53, profit = 10%, so CP = (100/110)*24.53 = Rs 22.30
1st rice………………2nd rice
20.50……………………..x
…………….22.30
x-22.30…………………..1.80
So (x – 22.30)/ 1.80 = 5/3
Solve, x = 25.30 -
Question 5 of 15
5. Question
1 pointsCategory: Quantitative AptitudeAn article is sold at a discount of 25% making a profit of 20%. What would have been the profit percent if the article was sold without discount?
Correct
Explanation:
Let MP = Rs 100
at 25% discount gives: SP = Rs 75, so Discount = 25
Now profit = 20%
so CP = (100/120) * 75 = 62.5
No discount given means SP = MP = 100
So Profit% when no discount = [100-62.5/62.5]*100Incorrect
Explanation:
Let MP = Rs 100
at 25% discount gives: SP = Rs 75, so Discount = 25
Now profit = 20%
so CP = (100/120) * 75 = 62.5
No discount given means SP = MP = 100
So Profit% when no discount = [100-62.5/62.5]*100 -
Question 6 of 15
6. Question
1 pointsCategory: Quantitative AptitudeDirections (6-10): Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question:
What is the two digit number?
I. The number obtained by interchanging the digits of original number is more than the original number by 36.
II. The difference between the digits is 4 and there addition gives 8.Correct
Explanation:
Let number if 10x+y
From I: (10y+x) = (10x+y) + 36
From II: x+y = 8 and x-y = 4 or y-x = 4
If x+y = 8 and x-y = 4 gives x=6 and y=2
If x+y = 8 and y-x = 4 gives x=2 and y=6
Since we don’t know that difference between which digits is 4, cant be determined.Incorrect
Explanation:
Let number if 10x+y
From I: (10y+x) = (10x+y) + 36
From II: x+y = 8 and x-y = 4 or y-x = 4
If x+y = 8 and x-y = 4 gives x=6 and y=2
If x+y = 8 and y-x = 4 gives x=2 and y=6
Since we don’t know that difference between which digits is 4, cant be determined. -
Question 7 of 15
7. Question
1 pointsCategory: Quantitative AptitudeDirections (6-10): Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question:
What is the rate percent per annum?
I. At the end of 2 years, the difference between compound interest and simple interest is Rs 250 on an amount of Rs 35,000
II. Simple interest obtained after 4 years is Rs 5600 on an amount of Rs 20,000Correct
Explanation:
From I: we are not given that whether CI or SI are calculated at same rate or not, so cant be determined.
From II: 20,000*r*4/100 = 5600, so r=7%Incorrect
Explanation:
From I: we are not given that whether CI or SI are calculated at same rate or not, so cant be determined.
From II: 20,000*r*4/100 = 5600, so r=7% -
Question 8 of 15
8. Question
1 pointsCategory: Quantitative AptitudeDirections (6-10): Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question:
What is the length of rectangle?
I. The perimeter of rectangle is equal to the perimeter of square of area 25 sq. m.
II. The breadth of rectangle is 25 m whose area is 250 sq. m.Correct
Explanation:
From I: Perimeter of rect. Is known, but we don’t have breadth, so L cant be found.
From II: Area = L*BIncorrect
Explanation:
From I: Perimeter of rect. Is known, but we don’t have breadth, so L cant be found.
From II: Area = L*B -
Question 9 of 15
9. Question
1 pointsCategory: Quantitative AptitudeDirections (6-10): Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question:
In how many days, A alone can complete the piece of work?
I. A and B together complete twice the work in 12 days.
II. B can complete 1/2 the work in 5 days.Correct
Explanation:
From I: A+B twice work in 12 days, so 1 work in 6 days
From II: B half work in 5 days, so 1 work in 10 days
So from both, 1/A = 1/6 – 1/10Incorrect
Explanation:
From I: A+B twice work in 12 days, so 1 work in 6 days
From II: B half work in 5 days, so 1 work in 10 days
So from both, 1/A = 1/6 – 1/10 -
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeDirections (6-10): Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question:
How many marks did Shikha get in Computers?
I. She got a total of 225 marks in 3 subjects, with marks in the ratio 1 : 1 : 3.
II. She got 45 marks in Science.Correct
Explanation:
From I: we don’t know, that in the ratio which part if of computer.
From II: cant be determined
Also from both, cant be determined since we don’t know in 1 : 1 : 3, which part is what subject.Incorrect
Explanation:
From I: we don’t know, that in the ratio which part if of computer.
From II: cant be determined
Also from both, cant be determined since we don’t know in 1 : 1 : 3, which part is what subject. -
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeDirections (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
2x2 – 9x – 5 = 0, 6y2 – 13y + 6 = 0
Correct
Explanation:
2x2 – 9x – 5 = 0
2x2 – 10x + x – 5 = 0
Gives x = -1/2, 5
6y2 – 13y + 6 = 0
6y2 – 9y – 4y + 6 = 0
Gives y = 2/3, 3/2
Put on number line
-1/2… 2/3 … 3/2 …. 5Incorrect
Explanation:
2x2 – 9x – 5 = 0
2x2 – 10x + x – 5 = 0
Gives x = -1/2, 5
6y2 – 13y + 6 = 0
6y2 – 9y – 4y + 6 = 0
Gives y = 2/3, 3/2
Put on number line
-1/2… 2/3 … 3/2 …. 5 -
Question 12 of 15
12. Question
1 pointsCategory: Quantitative AptitudeDirections (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
4x2 – 5x – 6 = 0, 3y2 – 13y + 14 = 0
Correct
Explanation:
4x2 – 5x – 6 = 0
4x2 – 8x + 3x – 6 = 0
Gives x = -3/4, 2
3y2 – 13y + 14 = 0
3y2 – 6y – 7y + 14 = 0
Gives y = 2, 7/3
Put on number line
-3/4… 2… 7/3Incorrect
Explanation:
4x2 – 5x – 6 = 0
4x2 – 8x + 3x – 6 = 0
Gives x = -3/4, 2
3y2 – 13y + 14 = 0
3y2 – 6y – 7y + 14 = 0
Gives y = 2, 7/3
Put on number line
-3/4… 2… 7/3 -
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeDirections (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
4x2 – x – 3 = 0, 2y2 – 11y + 14 = 0
Correct
Explanation:
4x2 – x – 3 = 0
4x2 – 4x + 3x – 3 = 0
Gives x = -3/4, 1
2y2 – 11y + 14 = 0
2y2 – 7y – 4y + 14 = 0
Gives y = 2, 7/2
Put on number line
-3/4… 1… 2… 7/2Incorrect
Explanation:
4x2 – x – 3 = 0
4x2 – 4x + 3x – 3 = 0
Gives x = -3/4, 1
2y2 – 11y + 14 = 0
2y2 – 7y – 4y + 14 = 0
Gives y = 2, 7/2
Put on number line
-3/4… 1… 2… 7/2 -
Question 14 of 15
14. Question
1 pointsCategory: Quantitative AptitudeDirections (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
2x2 – 13x + 18 = 0, 2y2 – 3y – 27 = 0
Correct
Explanation:
2x2 – 13x + 18 = 0
2x2 – 4x – 9x + 18 = 0
Gives x = 2, 9/2
2y2 – 3y – 27 = 0
2y2 + 6y – 9y – 27 = 0
Gives y = -3, 9/2
Put on number line
-3…. 2… 9/2
When x=2, x>y(-3) and xIncorrect
Explanation:
2x2 – 13x + 18 = 0
2x2 – 4x – 9x + 18 = 0
Gives x = 2, 9/2
2y2 – 3y – 27 = 0
2y2 + 6y – 9y – 27 = 0
Gives y = -3, 9/2
Put on number line
-3…. 2… 9/2
When x=2, x>y(-3) and x -
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeDirections (11-15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
9x2 – 3x – 2 = 0, 3y2 + 16y + 5 = 0
Correct
Explanation:
9x2 – 3x – 2 = 0
9x2 + 3x – 6x – 2 = 0
Gives x = -1/3, 2/3
3y2 + 16y + 5 = 0
3y2 + 15y + y + 5 = 0
Gives y= -5, -1/3
Put on number line
-5…. -1/3… 2/3Incorrect
Explanation:
9x2 – 3x – 2 = 0
9x2 + 3x – 6x – 2 = 0
Gives x = -1/3, 2/3
3y2 + 16y + 5 = 0
3y2 + 15y + y + 5 = 0
Gives y= -5, -1/3
Put on number line
-5…. -1/3… 2/3
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