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Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given pie charts carefully and answer the questions that follow.
The graphs show that how many students have taken which subject in school A and school B.
What percentage of the students in school A have taken English as their subject?
Correct
Explanation:
144/360 * 100Incorrect
Explanation:
144/360 * 100 
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given pie charts carefully and answer the questions that follow.
The graphs show that how many students have taken which subject in school A and school B.
The number of students who have taken French as their subject in school A is what percent of the number of students who have taken French as their subject in school B?
Correct
Explanation:
We are not given the total number of people in both the schools, so cant be determined.Incorrect
Explanation:
We are not given the total number of people in both the schools, so cant be determined. 
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given pie charts carefully and answer the questions that follow.
The graphs show that how many students have taken which subject in school A and school B.
If 1800 students have taken German as their subject in school B, then find the difference between the number of students who have taken French and the number of students who have taken Spanish in school B.
Correct
Explanation:
60/360 * x = 1800
Solve, x = 10,800
Difference = (5448)/360 * 10800Incorrect
Explanation:
60/360 * x = 1800
Solve, x = 10,800
Difference = (5448)/360 * 10800 
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given pie charts carefully and answer the questions that follow.
The graphs show that how many students have taken which subject in school A and school B.
By approximately what percentage the number of students who have taken Spanish as their subject in school A is more than the students who have taken other languages in school A?
Correct
Explanation:
(7242)/42 * 100Incorrect
Explanation:
(7242)/42 * 100 
Question 5 of 15
5. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the given pie charts carefully and answer the questions that follow.
The graphs show that how many students have taken which subject in school A and school B.
If total students in school A are 12,000 and that in school B are 9900, then find the ratio of the number of students who have taken German in school B to those who have taken French in school A.
Correct
Explanation:
60/360 * 9900 : 66/360 * 12000Incorrect
Explanation:
60/360 * 9900 : 66/360 * 12000 
Question 6 of 15
6. Question
1 pointsCategory: Quantitative Aptitude4x^{2} + 13x + 3 = 0, 5y^{2} – 11y + 2 = 0
Correct
Explanation:
4x^{2} + 13x + 3 = 0
4x^{2} + 12x + x + 3 = 0
Gives x = 3, 1/4
5y^{2} – 11y + 2 = 0
5y^{2} – 10y – y + 2 = 0
Gives y = 1/5, 2
Put on number line
3… 1/4……. 1/5…… 2Incorrect
Explanation:
4x^{2} + 13x + 3 = 0
4x^{2} + 12x + x + 3 = 0
Gives x = 3, 1/4
5y^{2} – 11y + 2 = 0
5y^{2} – 10y – y + 2 = 0
Gives y = 1/5, 2
Put on number line
3… 1/4……. 1/5…… 2 
Question 7 of 15
7. Question
1 pointsCategory: Quantitative Aptitude20x^{2} – 3x – 2 = 0, 5y^{2} – 21y + 4 = 0
Correct
Explanation:
20x^{2} – 3x – 2 = 0
20x^{2} + 5x – 8x – 2 = 0
Gives x = 1/4, 2/5
5y^{2} – 21y + 4 = 0
5y^{2} – 20y – y + 4 = 0
Gives y = 1/5, 4
Put on number line
1/4… 1/5……. 2/5…… 4Incorrect
Explanation:
20x^{2} – 3x – 2 = 0
20x^{2} + 5x – 8x – 2 = 0
Gives x = 1/4, 2/5
5y^{2} – 21y + 4 = 0
5y^{2} – 20y – y + 4 = 0
Gives y = 1/5, 4
Put on number line
1/4… 1/5……. 2/5…… 4 
Question 8 of 15
8. Question
1 pointsCategory: Quantitative Aptitude12x^{2} + 23x + 10 = 0, 4y^{2} – 7y – 15 = 0
Correct
Explanation:
12x^{2} + 23x + 10 = 0
12x^{2} + 8x + 15x + 10 = 0
Gives x = 5/4, 2/3
4y^{2} – 7y – 15 = 0
4y^{2} – 12y + 5y – 15 = 0
Gives y = 5/4, 3
Put on number line
5/4… 2/3…… 3Incorrect
Explanation:
12x^{2} + 23x + 10 = 0
12x^{2} + 8x + 15x + 10 = 0
Gives x = 5/4, 2/3
4y^{2} – 7y – 15 = 0
4y^{2} – 12y + 5y – 15 = 0
Gives y = 5/4, 3
Put on number line
5/4… 2/3…… 3 
Question 9 of 15
9. Question
1 pointsCategory: Quantitative Aptitude3x^{2} + 4x – 4 = 0, 3y^{2} – 11y + 6 = 0
Correct
Explanation:
3x^{2} + 4x – 4 = 0
3x^{2} + 6x – 2x – 4 = 0
Gives x = 2, 2/3
3y^{2} – 11y + 6 = 0
3y^{2} – 9y – 2y + 6 = 0
Gives y = 3, 2/3
Put on number line
2… 2/3…… 3Incorrect
Explanation:
3x^{2} + 4x – 4 = 0
3x^{2} + 6x – 2x – 4 = 0
Gives x = 2, 2/3
3y^{2} – 11y + 6 = 0
3y^{2} – 9y – 2y + 6 = 0
Gives y = 3, 2/3
Put on number line
2… 2/3…… 3 
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeThe sum of money invested at compound interest amounts to Rs 4680 in 2 years and to Rs 5616 in 3 years. What was the amount of sum invested?
Correct
Explanation:
SI on 3380 for 1 yr = 5616 – 4680 = 936
So rate = (100*936/4680*1) = 20
So P (1 + 20/100)^{2} = 4680
Solve, P = 3250Incorrect
Explanation:
SI on 3380 for 1 yr = 5616 – 4680 = 936
So rate = (100*936/4680*1) = 20
So P (1 + 20/100)^{2} = 4680
Solve, P = 3250 
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeA starts a business and invests Rs 25,000. After a year he invested Rs 10,000 more and B also joined by investing Rs 35,000. After one more year, A again invested Rs 10,000 more and C also joined A and B with Rs 35,000. At the end of 3 years, what will be C’s share from a profit of Rs 1,50,000?
Correct
Explanation:
A : B : C
25000*1 + 35000*1 + 45000*1 : 35000*2 : 35000*1
3 : 2 : 1
So C gets 1/6 * 1,50,000Incorrect
Explanation:
A : B : C
25000*1 + 35000*1 + 45000*1 : 35000*2 : 35000*1
3 : 2 : 1
So C gets 1/6 * 1,50,000 
Question 12 of 15
12. Question
1 pointsCategory: Quantitative Aptitude8 men can complete a work in 12 days and 12 children can do the same work in 16 days. 16 men start the work and after 3 days, 10 of the men are replaced by 4 children. In how many days will the remaining work get completed?
Correct
Explanation:
8 m in 12 days, so 16 m in (8*12)/16 = 6 days. they worked for 3 days
So work done is (1/6)*3 = 1/2
After 3 days, 10 m left, so now 6 men, 6 m can complete work in (8*12)/6 = 16 days
And 12 c in 16 days so 4 c in 12*16/4 = 48 days
Now 6 m and 4 c have to do remaining 1 – 1/2 = 1/2 work
So (1/16 + 1/48)*x = 1/2
Solve, x = 6 daysIncorrect
Explanation:
8 m in 12 days, so 16 m in (8*12)/16 = 6 days. they worked for 3 days
So work done is (1/6)*3 = 1/2
After 3 days, 10 m left, so now 6 men, 6 m can complete work in (8*12)/6 = 16 days
And 12 c in 16 days so 4 c in 12*16/4 = 48 days
Now 6 m and 4 c have to do remaining 1 – 1/2 = 1/2 work
So (1/16 + 1/48)*x = 1/2
Solve, x = 6 days 
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeThe rectangle whose sides are 6 cm and 5cm has perimeter equal to half of the perimeter of a square. If the diameter of a circle is equal to the side of the square, find the circumference of the semicircle?
Correct
Explanation:
Perimeter if square = 2 * peri. of rect = 2 * 2(6+5) = 44
So side of square = 44/4 = 11
So diameter of circle = 11, radius = 11/2
So circumference of circle = ᴨr + d = (22/7)*(11/2) + 11Incorrect
Explanation:
Perimeter if square = 2 * peri. of rect = 2 * 2(6+5) = 44
So side of square = 44/4 = 11
So diameter of circle = 11, radius = 11/2
So circumference of circle = ᴨr + d = (22/7)*(11/2) + 11 
Question 14 of 15
14. Question
1 pointsCategory: Quantitative AptitudeA’s present age is 1/3 of B’s and B’s present age id 9/13 of C’s present age. The sum of their present ages is 125 years. What is the difference between the ages of A and C?
Correct
Explanation:
B = 9C/13 and A = 1/3(9C/13) = 3C/13
So 3C/13 + 9C/13 + C = 125
Solve, C = 65, so A = 3*65/13 = 15
So C – A = 6515Incorrect
Explanation:
B = 9C/13 and A = 1/3(9C/13) = 3C/13
So 3C/13 + 9C/13 + C = 125
Solve, C = 65, so A = 3*65/13 = 15
So C – A = 6515 
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeThe train goes from station A to B and back to station A in 19 hours where total distance covered by train is 1200 km. The train halted for one hour after reaching station B. If the average speed of train from A to B is 25% more than that from B to A, what is the speed of train from A to B station?
Correct
Explanation:
Let speed in return journey is x, then in A to B is (125/100)*x = 5x/4
So 600/x + 600/(5x/4) = 18
Solve, x = 60
So from A to B is 5*60/4Incorrect
Explanation:
Let speed in return journey is x, then in A to B is (125/100)*x = 5x/4
So 600/x + 600/(5x/4) = 18
Solve, x = 60
So from A to B is 5*60/4
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