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Question 1 of 15
1. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the following table and answer the questions that follow:
The pie chart shows the percentage of employees in 5 departments of a company having total employees 750.
What is the total number of employees in departments B and E together in 2014?
Correct
Explanation:
(14+26)/100 * 750 = 300Incorrect
Explanation:
(14+26)/100 * 750 = 300 
Question 2 of 15
2. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the following table and answer the questions that follow:
The pie chart shows the percentage of employees in 5 departments of a company having total employees 750.
In 2015, if there is an increase of 2 % in the number of employees of department C, then how many employees are in department C in 2015?Correct
Explanation:
(102/100) * (20/100) * 750Incorrect
Explanation:
(102/100) * (20/100) * 750 
Question 3 of 15
3. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the following table and answer the questions that follow:
The pie chart shows the percentage of employees in 5 departments of a company having total employees 750.
What is the difference in the number of employees of department A and D in 2014?
Correct
Explanation:
(2218)/100 * 750Incorrect
Explanation:
(2218)/100 * 750 
Question 4 of 15
4. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the following table and answer the questions that follow:
The pie chart shows the percentage of employees in 5 departments of a company having total employees 750.
In 2014, the female employees in department E were 5/13 of total employees in that department. 4 females of E leave next year and equal males join that department, then what is the number of male employees in department E in 2015?
Correct
Explanation:
In 2014, total employees in E = (26/100) * 750 = 195
So females are (5/13) * 195 = 75, so males were = 195 – 75 = 120
In 2015, 4 males joined, so males become 120+4Incorrect
Explanation:
In 2014, total employees in E = (26/100) * 750 = 195
So females are (5/13) * 195 = 75, so males were = 195 – 75 = 120
In 2015, 4 males joined, so males become 120+4 
Question 5 of 15
5. Question
1 pointsCategory: Quantitative AptitudeDirections (1 – 5): Study the following table and answer the questions that follow:
The pie chart shows the percentage of employees in 5 departments of a company having total employees 750.
In 2014, 20% of employees in department A were post graduates which gets shifted to department D in 2015. If in department D 40% are post graduates, then what is the number of post graduate employees in department D in 2015?
Correct
Explanation:
Post grads in department A = (20/100) * (22/100) * 750 = 33
Post grads in department D = (40/100) * (18/100) * 750 = 54
So in 2015, in department D post grads becomes 54+33Incorrect
Explanation:
Post grads in department A = (20/100) * (22/100) * 750 = 33
Post grads in department D = (40/100) * (18/100) * 750 = 54
So in 2015, in department D post grads becomes 54+33 
Question 6 of 15
6. Question
1 pointsCategory: Quantitative AptitudeA and B starts a business with Rs 2800 and Rs 5400 respectively. After 4 months C joins with Rs 4800. If after a year, the difference in the shares of A and C from the total profit is Rs 400, then what is the total profit?
Correct
Explanation:
2800*12 : 5400*12 : 4800*8
14 : 27 : 16
so (16x – 14x)/(14+27+16) = 400
solve, x = 11400Incorrect
Explanation:
2800*12 : 5400*12 : 4800*8
14 : 27 : 16
so (16x – 14x)/(14+27+16) = 400
solve, x = 11400 
Question 7 of 15
7. Question
1 pointsCategory: Quantitative AptitudeA started from point P at 11 AM towards Point Q at 40 km/hr. also B started from point Q at 1 PM towards Point P at 50 km/hr. If points P and Q are 110 km apart, at what time do they meet?
Correct
Explanation:
A starts at 11 Am, after 2 hrs i.e. at 1 PM, he has covered distance = 2*40 = 80 km
Now B also started, distance between them is now 11080 = 30 km
So time they meet = 1 PM + (30/(40+50)) = 1 PM + (1/3)*60 = 1:20 PMIncorrect
Explanation:
A starts at 11 Am, after 2 hrs i.e. at 1 PM, he has covered distance = 2*40 = 80 km
Now B also started, distance between them is now 11080 = 30 km
So time they meet = 1 PM + (30/(40+50)) = 1 PM + (1/3)*60 = 1:20 PM 
Question 8 of 15
8. Question
1 pointsCategory: Quantitative Aptitude20 men do a piece of work in 15 days. 30 women do the same piece of work in 20 days. In how many days will 2 m and 4w complete this work?
Correct
Explanation:
20 m in 15 days, so 2 m in (20*15)/2 = 150
30 w in 20 days, so 4 w in (30*20)/4 = 150
So 2m + 4w in 1/150 + 1/150 = 1/75Incorrect
Explanation:
20 m in 15 days, so 2 m in (20*15)/2 = 150
30 w in 20 days, so 4 w in (30*20)/4 = 150
So 2m + 4w in 1/150 + 1/150 = 1/75 
Question 9 of 15
9. Question
1 pointsCategory: Quantitative AptitudeA can contains 34 l of milk. 4 litres of it is drawn out and 6 litres of water is poured in. If now again 6 litres of the mixture is taken out, what is the remaining quantity of milk in the mixture?
Correct
Explanation:
4 l drawn, milk = 344 = 30 l, water added 6 l
So ratio of milk to water is 30 : 6 = 5 : 1
Now 6 l of mixture taken out, so remaining milk is = 30 – (5/6) * 6 = 25Incorrect
Explanation:
4 l drawn, milk = 344 = 30 l, water added 6 l
So ratio of milk to water is 30 : 6 = 5 : 1
Now 6 l of mixture taken out, so remaining milk is = 30 – (5/6) * 6 = 25 
Question 10 of 15
10. Question
1 pointsCategory: Quantitative AptitudeHow many 5 digit numbers can be made from digits 4, 7, 3, 9, 0, 2, 1 when no digit repeats?
Correct
Explanation:
For a 5 digit number, 0 cannot be on first place, so total choices for 1st digit are 6,
Now at 2nd place 0 can also come, so total choices for 2nd digit are 6 again,
For 3rd = 5, for 4th = 4, for 5th = 3
So total numbers = 6*6*5*4*3 = 2160Incorrect
Explanation:
For a 5 digit number, 0 cannot be on first place, so total choices for 1st digit are 6,
Now at 2nd place 0 can also come, so total choices for 2nd digit are 6 again,
For 3rd = 5, for 4th = 4, for 5th = 3
So total numbers = 6*6*5*4*3 = 2160 
Question 11 of 15
11. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
9x^{2} – 9x + 2 = 0, 3y^{2} + 11y – 4 = 0
Correct
Explanation:
9x^{2} – 9x + 2 = 0
9x^{2} – 3x – 6x + 2 = 0
Gives x = 1/3, 2/3
3y^{2} + 11y – 4 = 0
3y^{2} + 12y – y – 4 = 0
Gives y = 4, 1/3
Put on number line
4…… 1/3 ….. 2/3Incorrect
Explanation:
9x^{2} – 9x + 2 = 0
9x^{2} – 3x – 6x + 2 = 0
Gives x = 1/3, 2/3
3y^{2} + 11y – 4 = 0
3y^{2} + 12y – y – 4 = 0
Gives y = 4, 1/3
Put on number line
4…… 1/3 ….. 2/3 
Question 12 of 15
12. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
x^{2} – 10x + 25 = 0, y^{2} – 9y + 20 = 0
Correct
Explanation:
x^{2} – 10x + 25 = 0
x^{2} – 5x – 5x + 25 = 0
Gives x = 5
y^{2} – 9y + 20 = 0
y^{2} – 5y – 4y + 20 = 0
Gives y = 4,5
Put on number line
4……. 5Incorrect
Explanation:
x^{2} – 10x + 25 = 0
x^{2} – 5x – 5x + 25 = 0
Gives x = 5
y^{2} – 9y + 20 = 0
y^{2} – 5y – 4y + 20 = 0
Gives y = 4,5
Put on number line
4……. 5 
Question 13 of 15
13. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
6x^{2} + 11x + 3 = 0, 20y^{2} + 9y + 1 = 0
Correct
Explanation:
6x^{2} + 11x + 3 = 0
6x^{2} + 2x + 9x + 3 = 0
Gives x = 1/3, 3/2
20y^{2} + 9y + 1 = 0
20y^{2} + 4y + 5y + 1 = 0
Gives y = 1/4, 1/5
Put on number line
3/2… 1/3……. 1/4…… 1/5Incorrect
Explanation:
6x^{2} + 11x + 3 = 0
6x^{2} + 2x + 9x + 3 = 0
Gives x = 1/3, 3/2
20y^{2} + 9y + 1 = 0
20y^{2} + 4y + 5y + 1 = 0
Gives y = 1/4, 1/5
Put on number line
3/2… 1/3……. 1/4…… 1/5 
Question 14 of 15
14. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
30x^{2} + 17x + 2 = 0, 3y^{2} + 8y + 4 = 0
Correct
Explanation:
30x^{2} + 17x + 2 = 0
30x^{2} + 5x + 12x + 2 = 0
Gives x = 1/6, 2/5
3y^{2} + 8y + 4 = 0
3y^{2} + 6y + 2y + 4 = 0
Gives y = 2, 2/3
Put on number line
2…………. 2/3………. 2/5……… 1/6Incorrect
Explanation:
30x^{2} + 17x + 2 = 0
30x^{2} + 5x + 12x + 2 = 0
Gives x = 1/6, 2/5
3y^{2} + 8y + 4 = 0
3y^{2} + 6y + 2y + 4 = 0
Gives y = 2, 2/3
Put on number line
2…………. 2/3………. 2/5……… 1/6 
Question 15 of 15
15. Question
1 pointsCategory: Quantitative AptitudeDirections (1115): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
4x^{2} – 13x + 10 = 0, 2y^{2} – 15y + 22 = 0
Correct
Explanation:
4x^{2} – 13x + 10 = 0
4x^{2} – 8x – 5x + 10 = 0
Gives x = 2, 5/4
2y^{2} – 15y + 22 = 0
2y^{2} – 4y – 11y + 22 = 0
Gives y= 11/2 , 2
Put on number line
5/4……….. 2………. 11/2Incorrect
Explanation:
4x^{2} – 13x + 10 = 0
4x^{2} – 8x – 5x + 10 = 0
Gives x = 2, 5/4
2y^{2} – 15y + 22 = 0
2y^{2} – 4y – 11y + 22 = 0
Gives y= 11/2 , 2
Put on number line
5/4……….. 2………. 11/2
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