Hello Aspirants

Welcome to Online **Quant** **Test** in AffairsCloud.com. We are starting **Cumulus Course for RRB Clerk 2019 Prelims Exam** and we are creating sample questions in Quant section, this type of Question will be asked in RRB Clerk 2019!!!

**Click Here to View Cumulus Course: RRB Clerk 2019 Prelims**

**RRB Clerk 2019 Prelims: Reasoning Test **– 7.00 PM Every Day

**RRB Clerk 2019 Prelims: Quant Test **– 8.00 PM Every Day

**Help:- **Share Our Cumulus Course for RRB Clerk 2019 Exam Course page to your Friends & FB Groups

**Click Here to Subscribe Crack High Level Puzzles & Seating Arrangement Questions PDF 2019 Plan**

_______________________

#### Quiz-summary

0 of 10 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

#### Information

**All the Best**

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

#### Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

#### Categories

- Quantitative Aptitude 0%

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

- Answered
- Review

- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Find out the wrong number in the following number series.**

15, 25, 36, 49, 66, 85, 110Correct**Answer: c) 66**

Explanation:

Incorrect**Answer: c) 66**

Explanation:

- Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**x**^{2}+ 18x+65 = 0

**y**^{2}+12y +35 = 0Correct**Answer: 3) x = y or relationship can’t be determined.**

**Explanation:**

x^{2}+ 18x+65 = 0

x^{2}+ 13x + 5x +65 = 0

x(x+13)+5(x+13) = 0

(x+5)(x+13) = 0

x = -5, -13y

^{2}+12y +35 = 0

y^{2}+5y+7y +35 = 0

y(y+5)+7(y+5) = 0

(y+5)(y+7) = 0

y = -5, -7Incorrect**Answer: 3) x = y or relationship can’t be determined.**

**Explanation:**

x^{2}+ 18x+65 = 0

x^{2}+ 13x + 5x +65 = 0

x(x+13)+5(x+13) = 0

(x+5)(x+13) = 0

x = -5, -13y

^{2}+12y +35 = 0

y^{2}+5y+7y +35 = 0

y(y+5)+7(y+5) = 0

(y+5)(y+7) = 0

y = -5, -7 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**? = (****-2****)**^{2}+ 111.21-20.1*11.9Correct**Answer: 5) -80**

**Explanation:**

? = ( -2 )^{2}+ 111.21-20.1*11.9

? = ( -6 )^{2}+ 111.21-20.1*11.9

? = ( -6 )^{2}– 128

? = (^{2}+ (6^{2}– 2. .6 -128

? = 12 + 108– 72-128

? = – 80Incorrect**Answer: 5) -80**

**Explanation:**

? = ( -2 )^{2}+ 111.21-20.1*11.9

? = ( -6 )^{2}+ 111.21-20.1*11.9

? = ( -6 )^{2}– 128

? = (^{2}+ (6^{2}– 2. .6 -128

? = 12 + 108– 72-128

? = – 80 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Quantity 1:**The shopkeeper sold an article at 17.5% discount on the marked price and he gains 10%. If the marked price of the article is Rs. 400, then the cost price is?

**Quantity 2:**The shopkeeper marks the price of the toy Rs. 400 and his profit is 44%. Find the cost price of the toy, if he allows a discount of 10%.Correct**Answer: a) Quantity I > Quantity II**

**Explanation:**

**Q1**

Selling price of the article = 400*(82.5/100) = 330

Cost price of the article –

CP*(110/100) = 330

CP = 330*(10/11)

CP = 300**Q2**

Selling price of the book = 400*(90/100) % = 360

CP*(144/100) = 360

CP = 360*(100/144) = 250Incorrect**Answer: a) Quantity I > Quantity II**

**Explanation:**

**Q1**

Selling price of the article = 400*(82.5/100) = 330

Cost price of the article –

CP*(110/100) = 330

CP = 330*(10/11)

CP = 300**Q2**

Selling price of the book = 400*(90/100) % = 360

CP*(144/100) = 360

CP = 360*(100/144) = 250 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**How much time boat A will take to cover a distance of 450 km in upstream?**

Statement 1: The ratio of the speed of boat A in still water to the speed of the stream is 5:1 respectively.

Statement 2: The sum of the speed of boat A in still water and the speed of boat A in downstream is 33km/h.Correct**Answer: 5) The data given in both statements 1 and 2 together are necessary to answer the question.**

Explanation:

Combining statement 1 and statement 2

Let the speed of boat A in still water = 5x and speed of stream = x

Speed of boat A downstream = 5x + x

(5x + 5x +x)= 33

11x = 33

x = 3

Speed of boat A in still water = 5x = 5*3 = 15km/h

Speed of stream = x = 3km/h

Speed of boat A in upstream = (15-3) km/h = 12 km/h

Time taken to cover 450km upstream

= (450/12)

= 37.5 hoursIncorrect**Answer: 5) The data given in both statements 1 and 2 together are necessary to answer the question.**

Explanation:

Combining statement 1 and statement 2

Let the speed of boat A in still water = 5x and speed of stream = x

Speed of boat A downstream = 5x + x

(5x + 5x +x)= 33

11x = 33

x = 3

Speed of boat A in still water = 5x = 5*3 = 15km/h

Speed of stream = x = 3km/h

Speed of boat A in upstream = (15-3) km/h = 12 km/h

Time taken to cover 450km upstream

= (450/12)

= 37.5 hours - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are three persons A, B, and C who each invested in two different scheme S1 and S2. A invested Rs. 50000 for 4 years in scheme S1 and Rs. 20000 for 2 years in scheme S2. B invested Rs. 20000 for 3 years in S1 and he did not invest in scheme S2. B also obtained a profit of Rs. 25000 by selling his bike. C invested Rs. 30000 for 6 years in scheme S1 and Rs. 5000 for 8 years in scheme S2. The total profit obtained from scheme S1 is Rs. 22000 and scheme S2 is Rs. 12000.**What is the ratio of the total profit of B to the total profit of A?**Correct**Answer: 3) 7:4**

Explanation:

Profit of A = 10000+6000 = 16000

Profit of B = 3000+ 25000 = 28000

Required ratio = (28000/16000) = 7/4

Required ratio = 7:4Overall Explanation:

Scheme S1

(Investment* time of investment) for scheme S1

A:B:C = 50000*4 : 20000*3 : 30000*6

A:B:C = 20 : 6 : 18

A:B:C = 10 : 3 : 9

Profit of A = (10/22)* 22000 = 10000

Profit of B = (3/22)*22000 = 3000

Profit of C = (9/22)*22000 = 9000

Scheme S2

(Investment* time of investment ) for scheme S2

A:C = 20000*2 : 5000*8

A:C = 40:40

A:C = 1:1

Profit of A = Profit of C = 6000Incorrect**Answer: 3) 7:4**

Explanation:

Profit of A = 10000+6000 = 16000

Profit of B = 3000+ 25000 = 28000

Required ratio = (28000/16000) = 7/4

Required ratio = 7:4Overall Explanation:

Scheme S1

(Investment* time of investment) for scheme S1

A:B:C = 50000*4 : 20000*3 : 30000*6

A:B:C = 20 : 6 : 18

A:B:C = 10 : 3 : 9

Profit of A = (10/22)* 22000 = 10000

Profit of B = (3/22)*22000 = 3000

Profit of C = (9/22)*22000 = 9000

Scheme S2

(Investment* time of investment ) for scheme S2

A:C = 20000*2 : 5000*8

A:C = 40:40

A:C = 1:1

Profit of A = Profit of C = 6000 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are three persons A, B, and C who each invested in two different scheme S1 and S2. A invested Rs. 50000 for 4 years in scheme S1 and Rs. 20000 for 2 years in scheme S2. B invested Rs. 20000 for 3 years in S1 and he did not invest in scheme S2. B also obtained a profit of Rs. 25000 by selling his bike. C invested Rs. 30000 for 6 years in scheme S1 and Rs. 5000 for 8 years in scheme S2. The total profit obtained from scheme S1 is Rs. 22000 and scheme S2 is Rs. 12000.**What is the difference between profit obtained by B from scheme S1 than profit obtained by C from scheme S2?**Correct**Answer: 2) Rs. 3000**

Explanation:

Profit obtained by C from scheme S2 = 6000

Profit obtained by B from scheme S1 = 3000

Required difference = 6000-3000 = 3000Incorrect**Answer: 2) Rs. 3000**

Explanation:

Profit obtained by C from scheme S2 = 6000

Profit obtained by B from scheme S1 = 3000

Required difference = 6000-3000 = 3000 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are three persons A, B, and C who each invested in two different scheme S1 and S2. A invested Rs. 50000 for 4 years in scheme S1 and Rs. 20000 for 2 years in scheme S2. B invested Rs. 20000 for 3 years in S1 and he did not invest in scheme S2. B also obtained a profit of Rs. 25000 by selling his bike. C invested Rs. 30000 for 6 years in scheme S1 and Rs. 5000 for 8 years in scheme S2. The total profit obtained from scheme S1 is Rs. 22000 and scheme S2 is Rs. 12000.**The total profit obtained by A from both the schemes in what percent of the amount invested by A in both the schemes?**Correct**Answer: 2) 23%**

Explanation:

Profit obtained by A from scheme S1 = 10000

Profit obtained by A from scheme S2 = 6000

Total profit obtained by A from both the schemes = 16000

Total amount invested by A in both the schemes = 50000+20000 = 70000

Required percentage = (16000/70000)*1000 = 22.8% = 23% (approx)Incorrect**Answer: 2) 23%**

Explanation:

Profit obtained by A from scheme S1 = 10000

Profit obtained by A from scheme S2 = 6000

Total profit obtained by A from both the schemes = 16000

Total amount invested by A in both the schemes = 50000+20000 = 70000

Required percentage = (16000/70000)*1000 = 22.8% = 23% (approx) - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are three persons A, B, and C who each invested in two different scheme S1 and S2. A invested Rs. 50000 for 4 years in scheme S1 and Rs. 20000 for 2 years in scheme S2. B invested Rs. 20000 for 3 years in S1 and he did not invest in scheme S2. B also obtained a profit of Rs. 25000 by selling his bike. C invested Rs. 30000 for 6 years in scheme S1 and Rs. 5000 for 8 years in scheme S2. The total profit obtained from scheme S1 is Rs. 22000 and scheme S2 is Rs. 12000.**The total profit obtained by C from both the schemes is what percent of profit obtained by B by selling his bike?**Correct**Answer: 5) 60%**

Explanation:

Profit obtained by B on selling his bike = 25000

Profit obtained by C from scheme S1 = 9000

Profit obtained by C from scheme S2 = 6000

Total profit obtained by C = 9000+6000 = 15000

Required percentage = (15000/25000)*100 = (3/5)*100 = 60%Incorrect**Answer: 5) 60%**

Explanation:

Profit obtained by B on selling his bike = 25000

Profit obtained by C from scheme S1 = 9000

Profit obtained by C from scheme S2 = 6000

Total profit obtained by C = 9000+6000 = 15000

Required percentage = (15000/25000)*100 = (3/5)*100 = 60% - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**There are three persons A, B, and C who each invested in two different scheme S1 and S2. A invested Rs. 50000 for 4 years in scheme S1 and Rs. 20000 for 2 years in scheme S2. B invested Rs. 20000 for 3 years in S1 and he did not invest in scheme S2. B also obtained a profit of Rs. 25000 by selling his bike. C invested Rs. 30000 for 6 years in scheme S1 and Rs. 5000 for 8 years in scheme S2. The total profit obtained from scheme S1 is Rs. 22000 and scheme S2 is Rs. 12000.

Find the marked price of the bike if it is equal to the sum of 125% of the total profit of A from both the schemes and 80% of the total profit of C from both the schemes?Correct**Answer: 1) Rs. 32000**

Explanation:

Total profit of A = 10000+6000 = 16000

125% of 16000 = 20000

Total profit of C = 9000+6000 = 15000

80% of 15000 = 12000

Marked price of bike = 20000+12000 = Rs. 32000Incorrect**Answer: 1) Rs. 32000**

Explanation:

Total profit of A = 10000+6000 = 16000

125% of 16000 = 20000

Total profit of C = 9000+6000 = 15000

80% of 15000 = 12000

Marked price of bike = 20000+12000 = Rs. 32000

**Click view Questions button to view Explanation****Note:-**We are providing unique questions for you to practice well, have a try !!- Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
- If you find any mistake, please tell us in the comment section.