Hello Aspirants
Welcome to Online Quant Test in AffairsCloud.com. We are starting Cumulus Course for RRB Clerk 2019 Prelims Exam and we are creating sample questions in Quant section, this type of Question will be asked in RRB Clerk 2019!!!
Click Here to View Cumulus Course: RRB Clerk 2019 Prelims
RRB Clerk 2019 Prelims: Reasoning Test – 7.00 PM Every Day
RRB Clerk 2019 Prelims: Quant Test – 8.00 PM Every Day
Help: Share Our Cumulus Course for RRB Clerk 2019 Exam Course page to your Friends & FB Groups
Click Here to Subscribe Crack High Level Puzzles & Seating Arrangement Questions PDF 2019 Plan
_______________________
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the speed of a boat and current is 7:2. The ratio of time taken of distance “D+25” downstream and distance “D” upstream is 3:2. Find distance D.
Correct
Answer: 3) 250/17
Explanation:
Let the speed of boat in still water = 7x and speed of current = 2x
Downstream speed = 7x+2x = 9x
Upstream speed = 7x2x = 5x
Distance = Speed*time
Time = Distance/Speed
T1 = (D+25)/9x
T2 = (D)/5x
ATQ,
T1:T2 = 3:2
{(D+25)/9x}: {(D)/5x} = 3:2
{(D+25)/9x} / {(D)/5x} = 3/2
{(D+25)*5x/9x*D} = 3/2
(5D+125)/9D = 3/2
10D+250 = 27D
17D = 250
D = 250/17Incorrect
Answer: 3) 250/17
Explanation:
Let the speed of boat in still water = 7x and speed of current = 2x
Downstream speed = 7x+2x = 9x
Upstream speed = 7x2x = 5x
Distance = Speed*time
Time = Distance/Speed
T1 = (D+25)/9x
T2 = (D)/5x
ATQ,
T1:T2 = 3:2
{(D+25)/9x}: {(D)/5x} = 3:2
{(D+25)/9x} / {(D)/5x} = 3/2
{(D+25)*5x/9x*D} = 3/2
(5D+125)/9D = 3/2
10D+250 = 27D
17D = 250
D = 250/17 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeThere are two books, Book A is sold at 15% profit & both the books have the same cost price, the overall profit by selling both the books is 12%, and if Book B is sold at Rs.18 more than the cost price of book A then find the cost price of book B.
Correct
Answer: 4) Rs. 200
Explanation:
Let the cost price of each book = 100x
Total cost price of both the books = 100x+100x = 200x
Total selling price of books = (112/100)*200x = 224x
Selling price of book A = (115/100)*100x = 115x
Therefore, selling price of book B = 224x – 115x = 109x
ATQ,
109x100x = 18
9x = 18
x = 2
Therefore, cost price of book B = 100x = 100*2 = Rs. 200Incorrect
Answer: 4) Rs. 200
Explanation:
Let the cost price of each book = 100x
Total cost price of both the books = 100x+100x = 200x
Total selling price of books = (112/100)*200x = 224x
Selling price of book A = (115/100)*100x = 115x
Therefore, selling price of book B = 224x – 115x = 109x
ATQ,
109x100x = 18
9x = 18
x = 2
Therefore, cost price of book B = 100x = 100*2 = Rs. 200 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude20 men can complete a work in 28 days, 45 men start work and work for x days after that 15 more men joined them and complete remaining work in 3 (5/6) days, find the value of x.
Correct
Answer: c) 22/3
Explanation:
Let the total work is 20*28 = 560 units
Work done by 45 men in x days = 45x
Work done by (45+15) men in 3 (5/6) days = 60*(23/6) = 230
Work left = 560 – 230 = 330
45x = 330
x = 330/45 = 110/15 = (22/3)Incorrect
Answer: c) 22/3
Explanation:
Let the total work is 20*28 = 560 units
Work done by 45 men in x days = 45x
Work done by (45+15) men in 3 (5/6) days = 60*(23/6) = 230
Work left = 560 – 230 = 330
45x = 330
x = 330/45 = 110/15 = (22/3) 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA vessel contains 120 litres of a mixture of milk and wine in the ratio 6:11. 35 litres of this mixture was taken out and replaced with 65 litres of milk. What is the approximate percentage of wine in the resultant mixture?
Correct
Answer: 4) 37%
Explanation:
Milk: Wine = 3:8
Volume of solution = 120 litres
Solution taken out = 35 litres
Volume of solution left = 12035 = 85 litres
In 85 litres
Milk = 85*(6/17) = 30 litres
And wine = 85*(11/17) = 55 litres
65 litres milk is added
Milk = 30+65 = 95
Total solution = 95+55 = 150 litres
Percentage of wine = (55/150)*100 = (11/30)*100 = 110/3 = 37% (approx)Incorrect
Answer: 4) 37%
Explanation:
Milk: Wine = 3:8
Volume of solution = 120 litres
Solution taken out = 35 litres
Volume of solution left = 12035 = 85 litres
In 85 litres
Milk = 85*(6/17) = 30 litres
And wine = 85*(11/17) = 55 litres
65 litres milk is added
Milk = 30+65 = 95
Total solution = 95+55 = 150 litres
Percentage of wine = (55/150)*100 = (11/30)*100 = 110/3 = 37% (approx) 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeProfit earned by an organisation is distributed among officers and clerks in the ratio of 2:5. If the number of officers is 20 and the number of clerks is 55 and the amount received by each clerk is Rs. 33000, what was the total amount of profit earned?
Correct
Answer: 2) Rs. 2.541 million
Explanation:
Total amount distributed among clerks = 33000*55 = 1815000
Let the amount distributed to officers be x
ATQ,
(x / 1815000) = 2/5
x = 726000
Total profit earned = 1815000+726000 = 2541000Incorrect
Answer: 2) Rs. 2.541 million
Explanation:
Total amount distributed among clerks = 33000*55 = 1815000
Let the amount distributed to officers be x
ATQ,
(x / 1815000) = 2/5
x = 726000
Total profit earned = 1815000+726000 = 2541000 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThree friends A, B and C jog around a circular stadium and complete one round in 36, 24 and 40 seconds respectively. In how many minutes will all the three meet again at the starting point?
Correct
Answer: 3) 6 minutes
Explanation:
LCM of 36, 24, 40 = 360
Hence, they all will meet again at the starting point after 360/60 = 6 minutesIncorrect
Answer: 3) 6 minutes
Explanation:
LCM of 36, 24, 40 = 360
Hence, they all will meet again at the starting point after 360/60 = 6 minutes 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeAshok and Anupam together can complete an assignment of data entry in 10 days. Ashok’s speed is 60% of Anupam’s speed and the total key depressions in the assignment are 804,000. What is Anupam’s speed in key depressions per hour if they work for 5 hours a day.
Correct
Answer: 5) 10050
Explanation:
Ratio between work done by Ashok and Anupam = 60:100 = 3:5
Total work done by Anupam = (5/8)*804000 = 502500
Total working hours by Anupam = 10*5 = 50 hours
Anupam’s speed = (502500/50) = 10050 key depressions per hourIncorrect
Answer: 5) 10050
Explanation:
Ratio between work done by Ashok and Anupam = 60:100 = 3:5
Total work done by Anupam = (5/8)*804000 = 502500
Total working hours by Anupam = 10*5 = 50 hours
Anupam’s speed = (502500/50) = 10050 key depressions per hour 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeTwo trains, A and B, start from stations X and Y towards each other. They take 3 hours 36 minutes and 2 hours 30 minutes to reach Y and X respectively after they meet. If train B is moving at 36 km/hr, then the speed of train A is
Correct
Answer: b) 30 km/hr
Explanation:
Incorrect
Answer: b) 30 km/hr
Explanation:

Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThere are three positive numbers. The average of all the three numbers is 4 less than the value of the highest number. The average of the lowest and the secondlowest number is 10. What is the highest number?
Correct
Answer: c) 16
Explanation:
The average of the lowest and the second lowest number is 10.
(lowest + second lowest number)/2 = 10
(lowest + second lowest number) = 20
Let the highest number is x
ATQ,
(lowest + second lowest number + highest number)/3 = highest number – 4
(20+x)/3 = x4
20 + x = 3x – 12
2x = 32
x = 16Incorrect
Answer: c) 16
Explanation:
The average of the lowest and the second lowest number is 10.
(lowest + second lowest number)/2 = 10
(lowest + second lowest number) = 20
Let the highest number is x
ATQ,
(lowest + second lowest number + highest number)/3 = highest number – 4
(20+x)/3 = x4
20 + x = 3x – 12
2x = 32
x = 16 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe students of three states A, B and C take a mock test. The average score of students of state A is 65. The average score of students of state B is 52. The average score of students of state C is 72. The average score of students of state A and B is 60 and the average score of students of state B and C is 64. Then the approximate average score of states A, B and C is
Correct
Answer: 2) 64.5
Explanation:
The average score of classes A, B and C
= (16*65 + 10*52+72*15)/ (16+10+15)
= (2640/41)
= 64.5(approx)Incorrect
Answer: 2) 64.5
Explanation:
The average score of classes A, B and C
= (16*65 + 10*52+72*15)/ (16+10+15)
= (2640/41)
= 64.5(approx)
________________________
 Click view Questions button to view Explanation
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
 If you find any mistake, please tell us in the comment section.