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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**Different number of units of electricity is consumed by three houses i.e. A, B and C in a month. Total number of units of electricity consumed by house B is 50 units less than that of house A and total units of electricity consumed by house C is 130 units more than that of house B. Number of units of electricity consumed by lights in house C is double to that of in house A and number of units of electricity consumed by lights in house B is 20% more than that of house A. Total number of units of electricity consumed by lights in house A, B and C together is 63 units. Total number of units of electricity consumed by house A is square of the number of units of electricity consumed by lights in house A. Number of units of electricity consumed by fans in house B is 35. Ratio of number of units of electricity consumed by fans in house A, B and C is 4:5:3 respectively.**Number of units of electricity consumed by appliances other than fans and lights in house C is:**Correct**Answer- 3) 254**

**Explanation-**

Let the number of units of electricity consumed by lights in house A = y

Number of units of electricity consumed by lights in house C = 2y

Number of units of electricity consumed by lights in house B = 120% of y = 1.2y

We have,

y + 2y + 1.2y = 63

4.2y = 63

y = 15

Therefore,

Number of units of electricity consumed by lights in house A = 15

Number of units of electricity consumed by lights in house B = 1.2 × 15 = 18

Number of units of electricity consumed by lights in house C = 2 × 15 = 30

Number of units of electricity consumed by fans in house B = 35

Number of units of electricity consumed by fans in house A = 35/5 × 4 = 28

Number of units of electricity consumed by fans in house C = 35/5 × 3 = 21

Total number of units of electricity consumed by house A = (15)^{2}= 225

Total number of units of electricity consumed by house B = 225 – 50 = 175

Total number of units of electricity consumed by house C = 175 + 130 = 305

Number of units of electricity consumed by appliances other than lights and fans in house C = 305 – (30 + 21) = 305 – 51 = 254Incorrect**Answer- 3) 254**

**Explanation-**

Let the number of units of electricity consumed by lights in house A = y

Number of units of electricity consumed by lights in house C = 2y

Number of units of electricity consumed by lights in house B = 120% of y = 1.2y

We have,

y + 2y + 1.2y = 63

4.2y = 63

y = 15

Therefore,

Number of units of electricity consumed by lights in house A = 15

Number of units of electricity consumed by lights in house B = 1.2 × 15 = 18

Number of units of electricity consumed by lights in house C = 2 × 15 = 30

Number of units of electricity consumed by fans in house B = 35

Number of units of electricity consumed by fans in house A = 35/5 × 4 = 28

Number of units of electricity consumed by fans in house C = 35/5 × 3 = 21

Total number of units of electricity consumed by house A = (15)^{2}= 225

Total number of units of electricity consumed by house B = 225 – 50 = 175

Total number of units of electricity consumed by house C = 175 + 130 = 305

Number of units of electricity consumed by appliances other than lights and fans in house C = 305 – (30 + 21) = 305 – 51 = 254 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**Different number of units of electricity is consumed by three houses i.e. A, B and C in a month. Total number of units of electricity consumed by house B is 50 units less than that of house A and total units of electricity consumed by house C is 130 units more than that of house B. Number of units of electricity consumed by lights in house C is double to that of in house A and number of units of electricity consumed by lights in house B is 20% more than that of house A. Total number of units of electricity consumed by lights in house A, B and C together is 63 units. Total number of units of electricity consumed by house A is square of the number of units of electricity consumed by lights in house A. Number of units of electricity consumed by fans in house B is 35. Ratio of number of units of electricity consumed by fans in house A, B and C is 4:5:3 respectively.**In house B, how much percent of electricity is consumed by fans out of total electricity consumed by it?**Correct**Answer- 4) 20%**

Explanation-

Required percentage = 35/175 × 100 = 20% (watch solution of Q 1)Incorrect**Answer- 4) 20%**

Explanation-

Required percentage = 35/175 × 100 = 20% (watch solution of Q 1) - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**Different number of units of electricity is consumed by three houses i.e. A, B and C in a month. Total number of units of electricity consumed by house B is 50 units less than that of house A and total units of electricity consumed by house C is 130 units more than that of house B. Number of units of electricity consumed by lights in house C is double to that of in house A and number of units of electricity consumed by lights in house B is 20% more than that of house A. Total number of units of electricity consumed by lights in house A, B and C together is 63 units. Total number of units of electricity consumed by house A is square of the number of units of electricity consumed by lights in house A. Number of units of electricity consumed by fans in house B is 35. Ratio of number of units of electricity consumed by fans in house A, B and C is 4:5:3 respectively.**15% of the electricity consumed by appliances other than fans and lights is spent on ACs in house B. How much number of units of electricity is consumed by ACs in house B?**Correct**Answer- 2) 18.3**

Explanation-

Required number of units = 15% of (175 – 35 – 18) = 15% of 122 = 18.3 unitsIncorrect**Answer- 2) 18.3**

Explanation-

Required number of units = 15% of (175 – 35 – 18) = 15% of 122 = 18.3 units - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**Different number of units of electricity is consumed by three houses i.e. A, B and C in a month. Total number of units of electricity consumed by house B is 50 units less than that of house A and total units of electricity consumed by house C is 130 units more than that of house B. Number of units of electricity consumed by lights in house C is double to that of in house A and number of units of electricity consumed by lights in house B is 20% more than that of house A. Total number of units of electricity consumed by lights in house A, B and C together is 63 units. Total number of units of electricity consumed by house A is square of the number of units of electricity consumed by lights in house A. Number of units of electricity consumed by fans in house B is 35. Ratio of number of units of electricity consumed by fans in house A, B and C is 4:5:3 respectively.**Number of units of electricity consumed by fans in house A is:**Correct**Answer- 2) 28**

Explanation-

Number of units of electricity consumed by fans in house A = 28 unitsIncorrect**Answer- 2) 28**

Explanation-

Number of units of electricity consumed by fans in house A = 28 units - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5).**Different number of units of electricity is consumed by three houses i.e. A, B and C in a month. Total number of units of electricity consumed by house B is 50 units less than that of house A and total units of electricity consumed by house C is 130 units more than that of house B. Number of units of electricity consumed by lights in house C is double to that of in house A and number of units of electricity consumed by lights in house B is 20% more than that of house A. Total number of units of electricity consumed by lights in house A, B and C together is 63 units. Total number of units of electricity consumed by house A is square of the number of units of electricity consumed by lights in house A. Number of units of electricity consumed by fans in house B is 35. Ratio of number of units of electricity consumed by fans in house A, B and C is 4:5:3 respectively.**Approximately how much percent of electricity is consumed by appliances other than fans and lights in house A?**Correct**Answer- 5) 81%**

Explanation-

Required percentage = 182/225 × 100 = 81% (approx.)Incorrect**Answer- 5) 81%**

Explanation-

Required percentage = 182/225 × 100 = 81% (approx.) - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The table below shows the percentage of men out of total men who worked on even days in three different months i.e. June, July and August. Rest of the men worked on even days of the respective months. Study the table carefully and answer the following questions.**

**In how many days will 240 men complete the same work completed on even days in the month of June?**Correct**Answer- 4) 34**

Explanation-

Let the number of days be x.

Number of men who worked on even days in June = 32% of 1700 = 544

Number of even days in June = 15

We have,

544 × 15 = 240 × x

x = 8160/240 = 34Incorrect**Answer- 4) 34**

Explanation-

Let the number of days be x.

Number of men who worked on even days in June = 32% of 1700 = 544

Number of even days in June = 15

We have,

544 × 15 = 240 × x

x = 8160/240 = 34 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The table below shows the percentage of men out of total men who worked on even days in three different months i.e. June, July and August. Rest of the men worked on even days of the respective months. Study the table carefully and answer the following questions.**

**Amount of work done on odd days in July is approximately how much percent of the amount of work done on even days in August?**Correct**Answer- 1) 57%**

Explanation-

Number of men who worked on odd days in July = 42% of 1200 = 504

Total number of odd days in July = 16

Number of men who worked on even days in August = 45% of 2100 = 945

Total number of even days in August = 15

Required percentage = 504 × 16/(945 × 15) × 100 = 806400/14175 = 57% (approx.)Incorrect**Answer- 1) 57%**

Explanation-

Number of men who worked on odd days in July = 42% of 1200 = 504

Total number of odd days in July = 16

Number of men who worked on even days in August = 45% of 2100 = 945

Total number of even days in August = 15

Required percentage = 504 × 16/(945 × 15) × 100 = 806400/14175 = 57% (approx.) - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The table below shows the percentage of men out of total men who worked on even days in three different months i.e. June, July and August. Rest of the men worked on even days of the respective months. Study the table carefully and answer the following questions.**

**Standard work time is 8 hours. In how many days the work which was done on even days in August will be completed by 700 men if each man works for 9 hours a day?**Correct**Answer- 3) 18**

Explanation-

Number of men who worked on even days in August = 45% of 2100 = 945

Number of even days in August = 15

Let the required number of days = x

Then,

945 × 8 × 15 = 700 × 9 × x

x = 945 × 8 × 15/(700 × 9) = 18 daysIncorrect**Answer- 3) 18**

Explanation-

Number of men who worked on even days in August = 45% of 2100 = 945

Number of even days in August = 15

Let the required number of days = x

Then,

945 × 8 × 15 = 700 × 9 × x

x = 945 × 8 × 15/(700 × 9) = 18 days - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

**Number of men who worked on odd days in August are how much more than the number of men who worked on even days in July?**Correct**Answer- 1) 459**

Explanation-

Number of men who worked on odd days in August = 55% of 2100 = 1155

Number of men who worked on even days in July = 58% of 1200 = 696

Required difference = 1155 – 696 = 459Incorrect**Answer- 1) 459**

Explanation-

Number of men who worked on odd days in August = 55% of 2100 = 1155

Number of men who worked on even days in July = 58% of 1200 = 696

Required difference = 1155 – 696 = 459 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

**In how many days the work will be completed on odd days in June if each man works for 10 hours instead of 8 hours?**Correct**Answer- 2) 12 days**

Explanation-

Number of odd days in June = 15

Let the required number of days be x.

Then,

15 × 8 = x × 10

x = 120/10 = 12 daysIncorrect**Answer- 2) 12 days**

Explanation-

Number of odd days in June = 15

Let the required number of days be x.

Then,

15 × 8 = x × 10

x = 120/10 = 12 days

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