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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (Q1-5). The following table gives information about the voting in six villages i.e. A, B, C, D, E and F in which candidates of two political parties P and Q contested. Based on the information given in the table, answer the following questions. Few values are missing in the table.
Number of votes polled in the favor of Q in village C are 292. Total number of registered votes in village F are how much percent more than the total number of registered votes in village C?
Correct
Answer- 2) 50%
Explanation-
Total number of votes polled in village C = 292 × 3 = 876
Total number of registered votes in village C = 876/73 × 100 = 1200
Required percentage = (1800 – 1200)/1200 × 100 = 50%Incorrect
Answer- 2) 50%
Explanation-
Total number of votes polled in village C = 292 × 3 = 876
Total number of registered votes in village C = 876/73 × 100 = 1200
Required percentage = (1800 – 1200)/1200 × 100 = 50% -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (Q1-5). The following table gives information about the voting in six villages i.e. A, B, C, D, E and F in which candidates of two political parties P and Q contested. Based on the information given in the table, answer the following questions. Few values are missing in the table.
Number of people who voted in the favor of P in village A are 258 more than that of people who voted in the favor of Q. How many people didn’t vote in village A?
Correct
Answer- 2) 215
Explanation-
Total number of votes polled in village A = 258/6 × 20 = 860
Number of people who didn’t vote = 1075 – 860 = 215Incorrect
Answer- 2) 215
Explanation-
Total number of votes polled in village A = 258/6 × 20 = 860
Number of people who didn’t vote = 1075 – 860 = 215 -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (Q1-5). The following table gives information about the voting in six villages i.e. A, B, C, D, E and F in which candidates of two political parties P and Q contested. Based on the information given in the table, answer the following questions. Few values are missing in the table.
Number of people who didn’t vote in village F are 774. By how much votes did Q win the election?
Correct
Answer- 5) 114
Explanation-
Total number of votes polled in village F = 1800 – 774 = 1026
Number of votes by which Q won = 1026/9 = 114Incorrect
Answer- 5) 114
Explanation-
Total number of votes polled in village F = 1800 – 774 = 1026
Number of votes by which Q won = 1026/9 = 114 -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (Q1-5). The following table gives information about the voting in six villages i.e. A, B, C, D, E and F in which candidates of two political parties P and Q contested. Based on the information given in the table, answer the following questions. Few values are missing in the table.
Q won by 99 votes in village E. Number of votes polled in the favor of Q in village E are 161 less the votes polled in his favor in village D. Number of votes polled in the favor of P in village D are how much more than the number of votes polled in favor of P in village E?
Correct
Answer- 3) 624
Explanation-
Total number of votes polled in village E = 66% of 550 = 363
Let the number of votes polled in favor of P are x and those polled in favor of Q are y.
x + y = 363
y – x = 99
By solving these equations, we have,
x = 132, y = 231
Number of votes polled in favor of Q in village D = 231 + 161 = 392
Total number of votes polled in village D = 82% of 1400 = 1148
Number of votes polled in the favor of P in village D = 1148 – 392 = 756
Required difference = 756 – 132 = 624Incorrect
Answer- 3) 624
Explanation-
Total number of votes polled in village E = 66% of 550 = 363
Let the number of votes polled in favor of P are x and those polled in favor of Q are y.
x + y = 363
y – x = 99
By solving these equations, we have,
x = 132, y = 231
Number of votes polled in favor of Q in village D = 231 + 161 = 392
Total number of votes polled in village D = 82% of 1400 = 1148
Number of votes polled in the favor of P in village D = 1148 – 392 = 756
Required difference = 756 – 132 = 624 -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (Q1-5). The following table gives information about the voting in six villages i.e. A, B, C, D, E and F in which candidates of two political parties P and Q contested. Based on the information given in the table, answer the following questions. Few values are missing in the table.
Number of people who didn’t vote in village B are 68 more than the number of people who voted in the favor of P in same village. Number of people who voted in the favor of Q in village B are:
Correct
Answer- 5) 374
Explanation-
Let the number of people who voted in the favor of P in village P are 6x and those who voted in favor Q are 11x.
Number of people who didn’t vote = 6x + 68
We have,
6x + 11x + 6x + 68 = 850
23x = 782, x = 34
Number of people who voted in favor of Q = 11x = 11 × 34 = 374Incorrect
Answer- 5) 374
Explanation-
Let the number of people who voted in the favor of P in village P are 6x and those who voted in favor Q are 11x.
Number of people who didn’t vote = 6x + 68
We have,
6x + 11x + 6x + 68 = 850
23x = 782, x = 34
Number of people who voted in favor of Q = 11x = 11 × 34 = 374 -
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (Q6-10). The following bar graph shows time taken (in minutes) by six inlet pipes i.e. P, Q, R, S, T and U to fill a tank alone. Based on the information given in bar graph solve the following questions.
P, Q and an outlet pipe X are opened together in the empty tank. The tank was filled in 30 minutes. In how many minutes can X alone empty the full tank?
Correct
Answer- 1) 120/7
Explanation-
LCM of 24, 20 and 30 = 120
Parts filled by P in 1 minute = 120/24 = 5
Parts filled by Q in 1 minute = 120/20 = 6
Parts filled by all three in 1 minute = 120/30 = 4
Parts filled by X in 1 minute = 5 + 6 – 4 = 7
Time taken by X to empty the tank = 120/7 minutesIncorrect
Answer- 1) 120/7
Explanation-
LCM of 24, 20 and 30 = 120
Parts filled by P in 1 minute = 120/24 = 5
Parts filled by Q in 1 minute = 120/20 = 6
Parts filled by all three in 1 minute = 120/30 = 4
Parts filled by X in 1 minute = 5 + 6 – 4 = 7
Time taken by X to empty the tank = 120/7 minutes -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (Q6-10). The following bar graph shows time taken (in minutes) by six inlet pipes i.e. P, Q, R, S, T and U to fill a tank alone. Based on the information given in bar graph solve the following questions.
In how much time will S and U fill the half empty tank when opened together?
Correct
Answer- 4) 10 minutes
Explanation-
LCM of 30 and 60 = 60
Parts filled by S in 1 minute = 60/30 = 2
Parts filled by U in 1 minute = 60/60 = 1
Time taken to fill the tank = 60/(2 + 1) = 60/3 = 20 minutes
Time taken to fill the half empty tank = 20/2 = 10 minutesIncorrect
Answer- 4) 10 minutes
Explanation-
LCM of 30 and 60 = 60
Parts filled by S in 1 minute = 60/30 = 2
Parts filled by U in 1 minute = 60/60 = 1
Time taken to fill the tank = 60/(2 + 1) = 60/3 = 20 minutes
Time taken to fill the half empty tank = 20/2 = 10 minutes -
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (Q6-10). The following bar graph shows time taken (in minutes) by six inlet pipes i.e. P, Q, R, S, T and U to fill a tank alone. Based on the information given in bar graph solve the following questions.
T and a pipe D can fill a tank in 15 minutes. In how much time pipe D can fill 4/5th of the tank alone?
Correct
Answer- 3) 18 minutes
Explanation-
LCM of 45 and 15 = 45
Parts filled by T in 1 minute = 45/45 = 1
Parts filled by T and D in 1 minute = 45/15 = 3
Parts filled by D in 1 minute = 3 – 1 = 2
Time taken by D to fill 2/5 of the tank = 4/5 × 45/2 = 18 minutesIncorrect
Answer- 3) 18 minutes
Explanation-
LCM of 45 and 15 = 45
Parts filled by T in 1 minute = 45/45 = 1
Parts filled by T and D in 1 minute = 45/15 = 3
Parts filled by D in 1 minute = 3 – 1 = 2
Time taken by D to fill 2/5 of the tank = 4/5 × 45/2 = 18 minutes -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (Q6-10). The following bar graph shows time taken (in minutes) by six inlet pipes i.e. P, Q, R, S, T and U to fill a tank alone. Based on the information given in bar graph solve the following questions.
Q, S and T are opened in the empty tank alternatively starting with Q i.e. Q in the first minute, S in the second minute, T in the third minute and again Q in the fourth minute and so on. In how much time will the tank be filled completely?
Correct
Answer- 5) 28 minutes
Explanation-
LCM of 20, 30 and 45 = 180
Parts of tank filled in 1st minute = 180/20 = 9
Parts of tank filled in 2nd minute = 180/30 = 6
Parts of tank filled in 3rd minute = 180/45 = 4
We have, 9 + 6 + 4 = 19
And 19 × 9 = 171
Therefore, parts of tank filled in 27 minutes = 171
Remaining parts = 180 – 171 = 9 which will be filled by Q in 28th minute.
Therefore, total time taken to fill the tank = 28 minutesIncorrect
Answer- 5) 28 minutes
Explanation-
LCM of 20, 30 and 45 = 180
Parts of tank filled in 1st minute = 180/20 = 9
Parts of tank filled in 2nd minute = 180/30 = 6
Parts of tank filled in 3rd minute = 180/45 = 4
We have, 9 + 6 + 4 = 19
And 19 × 9 = 171
Therefore, parts of tank filled in 27 minutes = 171
Remaining parts = 180 – 171 = 9 which will be filled by Q in 28th minute.
Therefore, total time taken to fill the tank = 28 minutes -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (Q6-10). The following bar graph shows time taken (in minutes) by six inlet pipes i.e. P, Q, R, S, T and U to fill a tank alone. Based on the information given in bar graph solve the following questions.
In approximately how much time P, Q and R will fill the empty tank when opened together?
Correct
Answer- 2) 7 minutes
Explanation-
LCM of 24, 20 and 18 = 360
Parts of tank filled in 1 minute by P = 360/24 = 15
Parts of tank filled in 1 minute by Q = 360/20 = 18
Parts of tank filled in 1 minute by R = 360/18 = 20
Time taken to fill the tank = 360/(15 + 18 + 20) = 360/53 = 7 minutes (approx.)Incorrect
Answer- 2) 7 minutes
Explanation-
LCM of 24, 20 and 18 = 360
Parts of tank filled in 1 minute by P = 360/24 = 15
Parts of tank filled in 1 minute by Q = 360/20 = 18
Parts of tank filled in 1 minute by R = 360/18 = 20
Time taken to fill the tank = 360/(15 + 18 + 20) = 360/53 = 7 minutes (approx.)
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