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Quantitative Aptitude0%

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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

What is the ratio of students enrolled in Dancing from city A and E to Craft from city B and C taken together?

Correct

Explanation

Students enrolled in Dancing from city A and E = (24500 + 17500) = 42000
Students enrolled in Craft from city B and C = (22500 + 26500) = 49000
Required ratio = 42000/49000 = 6:7

Incorrect

Explanation

Students enrolled in Dancing from city A and E = (24500 + 17500) = 42000
Students enrolled in Craft from city B and C = (22500 + 26500) = 49000
Required ratio = 42000/49000 = 6:7

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

What is average enrollment in craft taken in all cities together?

Correct

Explanation
Total enrollment in craft = (20000 + 22500 + 26500 + 20000 + 24000 + 26500) = 139500
Required average = 139500/6 = 23250

Incorrect

Explanation
Total enrollment in craft = (20000 + 22500 + 26500 + 20000 + 24000 + 26500) = 139500
Required average = 139500/6 = 23250

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

If 45%, 40% and 42% of students enrolled from city C in Dancing, Drawing and Craft are female then what is difference of male to female students enrolled taken all three activities together?

Correct

Explanation
Difference in dancing = 18000 x (55 – 45)/100 = 1800
Difference in drawing = 21500 x (60 – 40)/100 = 4300
Difference in craft = 26500 x (58 – 42)/100 = 4240
Required difference = (1800 + 4300 + 4240) = 10340

Incorrect

Explanation
Difference in dancing = 18000 x (55 – 45)/100 = 1800
Difference in drawing = 21500 x (60 – 40)/100 = 4300
Difference in craft = 26500 x (58 – 42)/100 = 4240
Required difference = (1800 + 4300 + 4240) = 10340

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

If 18% and 25% students in city D and 20% and 25% of students in city A respectively from dancing
and Drawing are professional then what is the ratio of professional students enrolled in craft from A to D?

Correct

Explanation
From city A:
Dancing professional = 24500 x 20/100 = 4900
Drawing professional = 24000 x 25/100 = 6000 Total = (4900 + 6000) = 10900
Total professional = 15300 Craft professional = (15300 – 10900) = 4400
From city D:
Dancing professional = 20000 x 18/100 = 3600
Drawing professional = 18000 x 25/100 = 4500
Total = (3600 + 4500) = 8100
Total professional = 15300
Craft professional = (15300 – 8100) = 7200
Required ratio = 4400/7200 = 11:18

Incorrect

Explanation
From city A:
Dancing professional = 24500 x 20/100 = 4900
Drawing professional = 24000 x 25/100 = 6000 Total = (4900 + 6000) = 10900
Total professional = 15300 Craft professional = (15300 – 10900) = 4400
From city D:
Dancing professional = 20000 x 18/100 = 3600
Drawing professional = 18000 x 25/100 = 4500
Total = (3600 + 4500) = 8100
Total professional = 15300
Craft professional = (15300 – 8100) = 7200
Required ratio = 4400/7200 = 11:18

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Total enrollment from city B and F is approximately what percent more than that of C and E taken all activities together?

Correct

Explanation
Total enrollment from B and F = (73000 + 71000) = 144000
Total enrollment from C and E = (66000 + 64000) = 130000
Required percent = (144000 – 130000)/130000 x 100 ≈ 11%

Incorrect

Explanation
Total enrollment from B and F = (73000 + 71000) = 144000
Total enrollment from C and E = (66000 + 64000) = 130000
Required percent = (144000 – 130000)/130000 x 100 ≈ 11%

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

In a simultaneous thrown of two dice. What is the probability of getting a total of either 9 or 10?

Correct

Incorrect

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

A hollow cylindrical tube is open at both ends is made of iron 4cm thick. If the external diameter be 52cm and the length of the tube be 120cm, find the number of cubic cm of iron in it? approx

A man cover a distance in t hrs, if he met with an accident after 20km and he then run at his 3/5th of his normal speed, so he reaches his destination 40minutes late. If he met with an accident at 30km then he reaches only 30min late. Find his original speed?

Correct

Explanation
After moving 10km more, man saves 10minutes. For saving of 40minutes he has to cover 40km.
Now speed: after accident before accident
. 3 5
Time 5 3
. (+2)
2=40minutes
1=20min
(Normal time) 3= 60min
So, he covers 40km in 60min with normal speed = 40kmph

Incorrect

Explanation
After moving 10km more, man saves 10minutes. For saving of 40minutes he has to cover 40km.
Now speed: after accident before accident
. 3 5
Time 5 3
. (+2)
2=40minutes
1=20min
(Normal time) 3= 60min
So, he covers 40km in 60min with normal speed = 40kmph

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

X, Y and Z started a business with their investments in the ratio 1:2:4. After 6 months X invested the half amount more as before and Y invested twice the amount as before while Z withdraw 1/4th of their investments. Find the ratio of their profits at the end of the year.

Correct

Explanation
Let us assume their initial investments were x, 2x and 4x respectively.
Therefore, ratio of their investments during the whole year
= [(x * 6) + (3x/2 * 6)]: [(2x * 6) + (4x * 6)]: [(4x * 6) + (3x * 6)]
= 15x: 36x: 42x
= 5 :12 :14

Incorrect

Explanation
Let us assume their initial investments were x, 2x and 4x respectively.
Therefore, ratio of their investments during the whole year
= [(x * 6) + (3x/2 * 6)]: [(2x * 6) + (4x * 6)]: [(4x * 6) + (3x * 6)]
= 15x: 36x: 42x
= 5 :12 :14

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The difference between a two-digit number and the number obtained by interchanging two digits of the number is 9. The sum of the two digits of the number is 15. What is the product of two digits of two-digit number?

Correct

Explanation
Let the digit of unit place be x.
So, the digit of tens place will be (15 ⎯x)
[10 (15 ⎯x) + x]⎯[10x + (15 ⎯x)] = 9
150 ⎯10x + x ⎯10x ⎯15 + x = 9
135 ⎯18 x = 9
18x = 126
x = 7
Thus, the digits of the number are 7 and 8.
So, the multiple of digits = 56

Incorrect

Explanation
Let the digit of unit place be x.
So, the digit of tens place will be (15 ⎯x)
[10 (15 ⎯x) + x]⎯[10x + (15 ⎯x)] = 9
150 ⎯10x + x ⎯10x ⎯15 + x = 9
135 ⎯18 x = 9
18x = 126
x = 7
Thus, the digits of the number are 7 and 8.
So, the multiple of digits = 56