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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeQ (15) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
 (p + q)^{2 }= 3136
 q + 2513 = 2569
Correct
explanation
i.(p + q)^{2} = 3136
p + q = 56ii.q + 2513 = 2569
or, q = 2569 – 2513 = 56
Putting the value of q in (I) we have,
p = 0. 112
p < qIncorrect
explanation
i.(p + q)^{2} = 3136
p + q = 56ii.q + 2513 = 2569
or, q = 2569 – 2513 = 56
Putting the value of q in (I) we have,
p = 0. 112
p < q 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeQ (15) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
I. 63x 94âˆšx+ 35=0 II. 32y 52âˆšy+21=0
Correct
explanation
63x 49âˆšx45âˆšx+35=0
(9âˆšx7) (7âˆšx5) =0
X=49/81, 25/4932y 28âˆšy â€“ 24âˆšy+ 21=0
(4âˆšy 3) (8âˆšy7) =0
Y=9/16, 49/64
Therefore, relation canâ€™t be established between x
and y.Incorrect
explanation
63x 49âˆšx45âˆšx+35=0
(9âˆšx7) (7âˆšx5) =0
X=49/81, 25/4932y 28âˆšy â€“ 24âˆšy+ 21=0
(4âˆšy 3) (8âˆšy7) =0
Y=9/16, 49/64
Therefore, relation canâ€™t be established between x
and y. 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeQ (15) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
I. 14×2 + 11x – 15 = 0 II. 20y2 – 31y + 12 = 0
Correct
explanation
(7x – 5) (2x + 3) = 0
X=5/7, 3/2
(4y – 3) (5y – 4) = 0
Y=3/4, 4/5
x < yIncorrect
explanation
(7x – 5) (2x + 3) = 0
X=5/7, 3/2
(4y – 3) (5y – 4) = 0
Y=3/4, 4/5
x < y 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeQ (15) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
I. 63x 194 âˆšx+143=0 II. 99y 255âˆšy+150=0
Correct
explanation
63x117 âˆšx77âˆšx +143=0
(7âˆšx13) (9âˆšx11) =0
X=169/49, 121/8199y 90âˆšy 165âˆšy+150=0
(11âˆšy10) (9âˆšy15) =0
X=100/121, 225/81
Therefore, relation cannot be established between
x and y.Incorrect
explanation
63x117 âˆšx77âˆšx +143=0
(7âˆšx13) (9âˆšx11) =0
X=169/49, 121/8199y 90âˆšy 165âˆšy+150=0
(11âˆšy10) (9âˆšy15) =0
X=100/121, 225/81
Therefore, relation cannot be established between
x and y. 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeQ (15) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
I. 10x + 6y = 13 II. 45x + 24y = 56
Correct
explanation
On solving both eqns, x =4/5, y=5/6
x < yIncorrect
explanation
On solving both eqns, x =4/5, y=5/6
x < y 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeIf in 2015, total number of female students from school ROS was 336, then how many male students passed the exam from school NBV?
Correct
Explanation
let the total number of students who passed from school ROS be x, then 28% of x = 336 or x = 1200, now, let the total students passed from all school be y, then, 15% of y = 1200 or y =8000. Now total students passed from school NBV = 22% of 8000 =1760. Therefore, number of male students passed from school NBV = 60% of 1760 =1056.Incorrect
Explanation
let the total number of students who passed from school ROS be x, then 28% of x = 336 or x = 1200, now, let the total students passed from all school be y, then, 15% of y = 1200 or y =8000. Now total students passed from school NBV = 22% of 8000 =1760. Therefore, number of male students passed from school NBV = 60% of 1760 =1056. 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeIf total passed students from school DPI in 2015 was 2400, then what is the ratio of the numbers of
female students who passed from school CRR to that of male students who passed from school ROS?Correct
Explanation
we can say, 12% of x = 2400(x = total number of passed students in all schools or, x= 20000. Number of female passed students from school CRR = 14% of 11% of 20000 = 308
Number of male passed students from school ROS = 72% of15% of 20000 = 2160.
Required ratio = 308:2160 = 77/540Incorrect
Explanation
we can say, 12% of x = 2400(x = total number of passed students in all schools or, x= 20000. Number of female passed students from school CRR = 14% of 11% of 20000 = 308
Number of male passed students from school ROS = 72% of15% of 20000 = 2160.
Required ratio = 308:2160 = 77/540 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIf in the year 2016, there is an increase of 16% and 24% in the strength of passing students from
school ROS and DAV respectively and the total number of passed students from school CRR in the year 2015 was 1650. What would be the total number of students who passed from school DAV and ROS in 2016?Correct
Explanation
11% of x = 1650 x = total number of passed students in all school or x = 15000. Total students passed
from school ROS = 15% of 15000 = 2250, total students passed from school DAV = 24% of 15000 = 3600.
In the year 2016, total students passed from school ROS = 116% of 2250 = 2610, total students passed from school DAV = 124% of 3600 = 4464, total number of students passed in both school in 2016 = 2610+4464 = 7074Incorrect
Explanation
11% of x = 1650 x = total number of passed students in all school or x = 15000. Total students passed
from school ROS = 15% of 15000 = 2250, total students passed from school DAV = 24% of 15000 = 3600.
In the year 2016, total students passed from school ROS = 116% of 2250 = 2610, total students passed from school DAV = 124% of 3600 = 4464, total number of students passed in both school in 2016 = 2610+4464 = 7074 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIf the male students passed from school DAV in 2015 were 306. What was the total number of passed students from all schools together?
Correct
Explanation
it is given that, 68% of x = 306 (x = total number of DAV passed students) or x = 450, now, 24% of y =
450(y= total number of passed students in all schools or, y = 1875)Incorrect
Explanation
it is given that, 68% of x = 306 (x = total number of DAV passed students) or x = 450, now, 24% of y =
450(y= total number of passed students in all schools or, y = 1875) 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIf in 2015, the total number of students who passed the exam in all school was 1750. What was the total number of male students from school ROX who passed the matriculation exam?
Correct
Explanation
total number of students who passed from school ROX = 16% of 1750 = 280, number of male students who passed from school ROX = 55% of 280 = 154.Incorrect
Explanation
total number of students who passed from school ROX = 16% of 1750 = 280, number of male students who passed from school ROX = 55% of 280 = 154.
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