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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The total population of Bikaner and Jaipur is 12,25,000. The difference between the total population of Bikaner and Jaipur is 55000. If the Jaipur has more population than Bikaner then the urban population of Bikaner and Jaipur together is approximately what percent of total population of these two Cities?

If the population of Bikaner is 105000 more than Kota then approximately, by what percent of urban population of Bikaner more than its Rural population?

One – fourth of total population of Jaipur is 1,60,000. If the total number of Literate in Ajmer and Kota are 48% and 44% of their population. The total number of literates in these cities is approximately what percentage compared to the total population of the same?

Correct

Explanation

1/4 * Jaipur = 1,60,000 =>Jaipur= 6,40,000
Literate population of Jaipur = 7/16 * 6,40,000 = 2,80,000
Literate population of Ajmer = 295200
Literate population of Kota= 211200
Total number of Literate = 786400
Total population of three = 1735000
Percentage =786400/1735000 * 100 = 45%

Incorrect

Explanation

1/4 * Jaipur = 1,60,000 =>Jaipur= 6,40,000
Literate population of Jaipur = 7/16 * 6,40,000 = 2,80,000
Literate population of Ajmer = 295200
Literate population of Kota= 211200
Total number of Literate = 786400
Total population of three = 1735000
Percentage =786400/1735000 * 100 = 45%

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

What is the sum of male population in Ajmer and female population in Kota together?

If the percentage of literate graduates in Jaipur is 1/5th of literate graduates in Ajmer then
what is the difference between the number of literate graduates from Kota and Jaipur?

Correct

Explanation
Literate graduates in Jaipur = 1/5 * literate graduates in Ajmer
Literate graduates in Ajmer= 55/100 * 615000 = 338250
Literate graduates in Jaipur = 1/5 * 338250 = 67650
Literate graduates in Kota = 65/100 * 480000 = 312000
Diff = 312000 – 67650 = 244350

Incorrect

Explanation
Literate graduates in Jaipur = 1/5 * literate graduates in Ajmer
Literate graduates in Ajmer= 55/100 * 615000 = 338250
Literate graduates in Jaipur = 1/5 * 338250 = 67650
Literate graduates in Kota = 65/100 * 480000 = 312000
Diff = 312000 – 67650 = 244350

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Q (6-10) Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between ‘x’ and ‘y’ and give answer

Q (6-10) Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between ‘x’ and ‘y’ and give answer

I. 3x + 2y = 301
II. 7x – 5y = 74

Correct

explanation
eqn (I) × 5 + eqn (II) × 2
15x + 10y = 1505
14x – 10y = 148
29x = 1653
x =1653/29 = 57
and y = 65 so, x < y

Incorrect

explanation
eqn (I) × 5 + eqn (II) × 2
15x + 10y = 1505
14x – 10y = 148
29x = 1653
x =1653/29 = 57
and y = 65 so, x < y

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Q (6-10) Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between ‘x’ and ‘y’ and give answer

II. 2y^{2} + 12y + 13y + 78 = 0
or, 2y (y + 6) + 13(y + 6) = 0
or, (2y + 13) (y + 6) = 0
y =-13/2, -6
x > y

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Q (6-10) Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between ‘x’ and ‘y’ and give answer

Q (6-10) Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between ‘x’ and ‘y’ and give answer

I. 6x – 5y = -47
II. 5x + 3y = 11

Correct

explanation
eqn(I) × 3 18x – 15y = -141
eqn (II) × 5 25x + 15y = 55
43x = -86
x=-2
5x + 3y = 11
3y = 11 – 5x
3y = 11 + 10
3y = 21
y = 7 so, x < y

Incorrect

explanation
eqn(I) × 3 18x – 15y = -141
eqn (II) × 5 25x + 15y = 55
43x = -86
x=-2
5x + 3y = 11
3y = 11 – 5x
3y = 11 + 10
3y = 21
y = 7 so, x < y