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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Pipes A and B can fill an empty bucket in 15 and 20 minutes respectively. The same full bucket can be emptied by another pipe C in 30 minutes. First A is opened for 2 minutes, followed B and then C for 2 minutes each. If the process continues like this, in how much total time will the bucket get filled?

Correct

Explanation:
In 1 minute, A does 1/15 work, B does 1/20 work and C does -1/30 work
So in 2 minutes, A does 2/15 work, B does 2/20 work and C does -2/30 work
After (2+2+2) = 6 minutes, work done is (2/15) + (2/20) – (2/130) = 1/6
Multiply by 5 both sides, so
After 30 minutes, work done is 5/6
Remaining work = 1 – 5/6 = 1/6. Now after this – A’s turn and in next 2 minutes A does 2/15 work, so now work left = 1/6 – 2/15 = 1/30
So now 32 minutes passed, remaining work is 1/30 and now is B’s turn. B does 1/20 work in 1 min, so the remaining 1/30 work in 2/3 minutes
So in total 32 2/3 minutes

Incorrect

Explanation:
In 1 minute, A does 1/15 work, B does 1/20 work and C does -1/30 work
So in 2 minutes, A does 2/15 work, B does 2/20 work and C does -2/30 work
After (2+2+2) = 6 minutes, work done is (2/15) + (2/20) – (2/130) = 1/6
Multiply by 5 both sides, so
After 30 minutes, work done is 5/6
Remaining work = 1 – 5/6 = 1/6. Now after this – A’s turn and in next 2 minutes A does 2/15 work, so now work left = 1/6 – 2/15 = 1/30
So now 32 minutes passed, remaining work is 1/30 and now is B’s turn. B does 1/20 work in 1 min, so the remaining 1/30 work in 2/3 minutes
So in total 32 2/3 minutes

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

A certain amount invested at the rate of 6% per annum for 4 years gives a simple interest of Rs 600. Had the same amount was invested at the rate of 4% per annum compounded annually, what compound interest would be obtained after 2 years?

Correct

Explanation:
600 = P*6*4/100
So principal = Rs 2500
CI = 2500 [(1 +4/100)^2 – 1]

Incorrect

Explanation:
600 = P*6*4/100
So principal = Rs 2500
CI = 2500 [(1 +4/100)^2 – 1]

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Two right circular cones have their perimeters in the ratio 3 : 4. The ratio of the heights of the cones is 1 : 2 respectively. What is the ratio of their volumes respectively?

A, B and C invested Rs 5000, Rs 6000 and Rs 6500 in a business. After the end of 4 months all of them withdrew Rs 500. After a total of 8 months from the start of business all of them added Rs 500 in their investments. Find the ratio of their shares in total profit at the end of a year.

Correct

Explanation:
After 4 months all withdraw Rs 500 and after another 4 months (8 months from start) all add Rs 500. So this means 5000, 6000 and 6500 are invested for 4+4 = 8 months and with Rs 500 withdraw 4500, 5500 and 6000 are invested for 4 months respectively by A, B and C.
So ratio =
5000*8 + 4500*4 : 6000*8 + 5500*4 : 6500*8 + 6000*4
50*2 + 45 : 60*2 + 55 : 65*2 + 60
10*2 + 9 : 12*2 + 11 : 13*2 + 12
29 : 35 : 38

Incorrect

Explanation:
After 4 months all withdraw Rs 500 and after another 4 months (8 months from start) all add Rs 500. So this means 5000, 6000 and 6500 are invested for 4+4 = 8 months and with Rs 500 withdraw 4500, 5500 and 6000 are invested for 4 months respectively by A, B and C.
So ratio =
5000*8 + 4500*4 : 6000*8 + 5500*4 : 6500*8 + 6000*4
50*2 + 45 : 60*2 + 55 : 65*2 + 60
10*2 + 9 : 12*2 + 11 : 13*2 + 12
29 : 35 : 38

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

In an examination it is required to get 450 marks of the aggregate marks to pass. One of the students got 43% marks and he was declared failed by 20 marks. Find the maximum aggregate marks of the examination.

Correct

Explanation:
He got failed by 20 marks so has received (450-20) = 430 marks which is equal to 43% of aggregate marks
So 43% of aggregate marks = 430
aggregate marks = 43000/43

Incorrect

Explanation:
He got failed by 20 marks so has received (450-20) = 430 marks which is equal to 43% of aggregate marks
So 43% of aggregate marks = 430
aggregate marks = 43000/43