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The difference between compound interest and simple interest on a sum for 2 yrs at 20% per annum, when the interest is compounded annually is Rs 240. If the interest were compounded half yearly, the difference in two interests over same period would be

Correct

Explanation:
Difference for 2 yrs = P*20*20/100*100 = 240
Solve, P = 6000
So SI for 2 yrs = 6000*20*2/100 = 2400
Amount at compounded half yearly = 6000 [1 + 10/100]^4
Solve, Amount at compounded half yearly = 8784.6
So CI at compounded half yearly = 8784.6 – 6000 = 2784.6
So difference = 2784.6 – 2400

Incorrect

Explanation:
Difference for 2 yrs = P*20*20/100*100 = 240
Solve, P = 6000
So SI for 2 yrs = 6000*20*2/100 = 2400
Amount at compounded half yearly = 6000 [1 + 10/100]^4
Solve, Amount at compounded half yearly = 8784.6
So CI at compounded half yearly = 8784.6 – 6000 = 2784.6
So difference = 2784.6 – 2400

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Out of 10 items having same cost price, 6 are sold at 10% profit and remaining at 20% profit. If all the 10 items were sold at a profit of 10%, then profit would be Rs. 80 less than the initial profit. What is the cost price of each camera?

Correct

Explanation:
Let CP of 1 is x, then of 6 is 6x
so SP = (110/100)* 6x = 66x/10
CP of 4 = 4x so SP = (120/100)*4x = 48x/10
total SP = 66x/10 + 48x/10 = 114x/10 = 11.4x
and total CP = 6x + 4x = 10x
so profit = 11.4x – 10x = 1.4x
if all 10 items at 10% profit, SP = (110/100)*10x = 11x
and CP = 10x so profit = x
now given that, 1.4x = x + 80
solve, x = 200, CP of each is x = 200

Incorrect

Explanation:
Let CP of 1 is x, then of 6 is 6x
so SP = (110/100)* 6x = 66x/10
CP of 4 = 4x so SP = (120/100)*4x = 48x/10
total SP = 66x/10 + 48x/10 = 114x/10 = 11.4x
and total CP = 6x + 4x = 10x
so profit = 11.4x – 10x = 1.4x
if all 10 items at 10% profit, SP = (110/100)*10x = 11x
and CP = 10x so profit = x
now given that, 1.4x = x + 80
solve, x = 200, CP of each is x = 200

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A bucket contains 2 red balls, 4 blue balls, and 6 white balls. Three balls are drawn at random. What is the probability that the draw contains exactly one blue ball?

Find the least number which when divided by 3, 9, 10, 12 and 15 leaves remainders 1, 11, 12, 14, and 17 respectively.

Correct

Explanation:
Since 3-1 = 2, 11-9 = 2, 12-10 =2, 14-12 = 2, 17-15 = 2
So answer will be the LCM (3, 9, 10, 12 and 15) – 2
So 180 – 2

Incorrect

Explanation:
Since 3-1 = 2, 11-9 = 2, 12-10 =2, 14-12 = 2, 17-15 = 2
So answer will be the LCM (3, 9, 10, 12 and 15) – 2
So 180 – 2

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

In what ratio must the 3 varieties of wheat costing Rs 32, Rs 44 and Rs 55 respectively be mixed so that the resulting mixture is sold for Rs 52.8 at a profit of 10%?

Correct

Explanation:
SP = 52.8, Profit=10%, so CP = (100/110)*52.8 = 48
Now 48 is greater than 32 and 44 and less than 55
So
32…………..……. 55
…………48
7…………………..16
And
44……………………55
……………48
7……………………..4
So 1 part of 1st wheat A, 1 part of 2nd wheat B and 2 parts of 3rd wheat C gives
A : C = 7 : 16, and B : C = 7 : 4
So A : B : C = 7 : 7 : (16+4)

Incorrect

Explanation:
SP = 52.8, Profit=10%, so CP = (100/110)*52.8 = 48
Now 48 is greater than 32 and 44 and less than 55
So
32…………..……. 55
…………48
7…………………..16
And
44……………………55
……………48
7……………………..4
So 1 part of 1st wheat A, 1 part of 2nd wheat B and 2 parts of 3rd wheat C gives
A : C = 7 : 16, and B : C = 7 : 4
So A : B : C = 7 : 7 : (16+4)