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Quantitative Aptitude0%

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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

An alloy whose weight is 10 kg contains 1/4th of nickel and rest copper. The alloy is mixed with another alloy which weighs 7 kg containing 1/2 of nickel and rest copper. Find the ratio of nickel to copper in the final mixture?

Correct

Explanation:
After mixing the two, quantity of nickel = 1/4 * 10 + 1/2 * 7 = 6
Quantity of copper = 3/4 * 10 + 1/2 * 7 = 11
Ratio of nickel to copper = 6 : 11

Incorrect

Explanation:
After mixing the two, quantity of nickel = 1/4 * 10 + 1/2 * 7 = 6
Quantity of copper = 3/4 * 10 + 1/2 * 7 = 11
Ratio of nickel to copper = 6 : 11

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

The sum of money invested at compound interest amounts to Rs 5040 in 2 years and to Rs 6048 in 3 years. What was the amount of sum invested?

Correct

Explanation:
SI on 5040 for 1 yr = 6048 – 5040 = 1008
So rate = (100*1008/5040*1) = 20
So P (1 + 20/100)^{2} = 5040
Solve, P = 3500

Incorrect

Explanation:
SI on 5040 for 1 yr = 6048 – 5040 = 1008
So rate = (100*1008/5040*1) = 20
So P (1 + 20/100)^{2} = 5040
Solve, P = 3500

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

An urn contains 2 red, 4 blue, 1 white and 5 green balls. A set of 4 balls is chosen randomly. What is the probability that the set contains exactly 2 blue balls?

Correct

Explanation:
Total 12 balls, 2 balls should be blue, other 2 can be any of the three colored balls
So prob. = ^{4}C_{2} × ^{8}C_{2}/^{12}C_{4}

Incorrect

Explanation:
Total 12 balls, 2 balls should be blue, other 2 can be any of the three colored balls
So prob. = ^{4}C_{2} × ^{8}C_{2}/^{12}C_{4}

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Together 6 men and 5 women completed a work taking 10 days. The same work is completed by 10 men and 5 women in 7 days. Find the number of days in which 35 women can complete the same work?

Correct

Explanation:
6m + 5w = 10 days so 60m + 50w = 1 day
10m + 5w = 7 days so 70m + 35w = 1 day
So 60m + 50w = 70m + 35w . It gives 1m = (3/2) w
6m + 5w = 10, so 6*(3/2)w + 5w = 10, so 14 w do 1 work in 10 days, so 35 w will do in (14*10)/35

Incorrect

Explanation:
6m + 5w = 10 days so 60m + 50w = 1 day
10m + 5w = 7 days so 70m + 35w = 1 day
So 60m + 50w = 70m + 35w . It gives 1m = (3/2) w
6m + 5w = 10, so 6*(3/2)w + 5w = 10, so 14 w do 1 work in 10 days, so 35 w will do in (14*10)/35

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A and B invested Rs12,000 and Rs 15,000 respectively in a business. After 4 months they both withdrew Rs 2000. After a further of half year, A invested Rs 4000 more and B invested Rs 1000 more. If a total profit received after a year is Rs 24,160, what is the difference in the shares of A and B?

Find the volume of the cone which has curved surface area as 580ᴨ sq. m. and radius of base as 20 m.

Correct

Explanation:
CSA = ᴨrl = ᴨ*20*l = 580ᴨ sq. m
So Slant height, l = 29
Now l^{2} = r^{2} + h^{2}
Solve, h = 21
So 1/3 ᴨr^{2}h = 8800

Incorrect

Explanation:
CSA = ᴨrl = ᴨ*20*l = 580ᴨ sq. m
So Slant height, l = 29
Now l^{2} = r^{2} + h^{2}
Solve, h = 21
So 1/3 ᴨr^{2}h = 8800

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

The length and the breadth of a rectangular card are increased by 1 m and 2 m respectively and due to this the area of the card increased by 66 sq. m. But if the length and breadth are decreased by 2 m and 1 m respectively, area is decreased by 51 sq. m. Find the perimeter of the original card.

Correct

Explanation:
Let original length = l, breadth = b, so area = lb
When l and b increased:
(l+1)(b+2) = lb + 66
Solve, 2l + b = 64
When both decreased:
(l-2)(b-1) = lb – 51
Solve, l + 2b = 53
Now solve both equations, l = 25, b = 14
Perimeter = 2(25+14)

Incorrect

Explanation:
Let original length = l, breadth = b, so area = lb
When l and b increased:
(l+1)(b+2) = lb + 66
Solve, 2l + b = 64
When both decreased:
(l-2)(b-1) = lb – 51
Solve, l + 2b = 53
Now solve both equations, l = 25, b = 14
Perimeter = 2(25+14)

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

There are two trains of lengths 240 m and 200 m respectively. Both start at same time. If they travel in same direction they cross each other in 44 seconds and if they travel in opposite direction towards each other, they cross each other in 8.8 seconds. What is the speed of the slowest train?

Correct

Explanation:
Let speed of 1st train = x m/s, of 2nd train = y m/s
Then when they travel in same direction, relative speed = x-y
So (240+200) = (x-y)*44. This gives x –y = 10
When they travel in opposite direction, relative speed = x+y
So (240+200) = (x+y)*8.8. This gives x + y = 50
Solve both equations, y = 20

Incorrect

Explanation:
Let speed of 1st train = x m/s, of 2nd train = y m/s
Then when they travel in same direction, relative speed = x-y
So (240+200) = (x-y)*44. This gives x –y = 10
When they travel in opposite direction, relative speed = x+y
So (240+200) = (x+y)*8.8. This gives x + y = 50
Solve both equations, y = 20

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

8 men can complete a work in 5 days. 12 women can complete in 10 days and 10 children in 24 days. 1 man, 1 woman and 1 child started the work. In how many days will the work get completed if the man did twice the work as woman and also twice the work as child?

Correct

Explanation:
Man did twice work from woman and child both. This means woman and child did equal work and man twice of that. So 2x + x + x = 1, x = 1/4
Woman did 1/4 of work, child did 1/4 of work and man 2*(1/4) = 1/2 of work
8 m in 5 days, so 1 man in 40 days, so 1/2 work in 20 days.
12 w in 10 days, so 1 woman in 120 days, so 1/4 work in 30 days.
10 c in 24 days, so 1 child in 240 days, so 1/4 work in 60 days.
So 1/20 + 1/30 + 1/60

Incorrect

Explanation:
Man did twice work from woman and child both. This means woman and child did equal work and man twice of that. So 2x + x + x = 1, x = 1/4
Woman did 1/4 of work, child did 1/4 of work and man 2*(1/4) = 1/2 of work
8 m in 5 days, so 1 man in 40 days, so 1/2 work in 20 days.
12 w in 10 days, so 1 woman in 120 days, so 1/4 work in 30 days.
10 c in 24 days, so 1 child in 240 days, so 1/4 work in 60 days.
So 1/20 + 1/30 + 1/60

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

A bag contains 5 white balls, 4 green balls and 3 red balls. Six balls are drawn at random. What is the probability that there is equal number of balls of each color?