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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The sum of two numbers is 520. If the bigger number is decreased by 4% and the smaller number is increased by 12% then the numbers obtained are equal. Find the smallest number?

Correct

Answer – 1) 240
Explanation:
Let the bigger number = A
The smaller number= 520 – A
According to question,
A * ((100-4)/100) = (520 – A) * ((100 + 12)/100)
96A/100 = (520 – A) * (112/100)
96A = (520 – A) * 112
13A = 3640
A = 280
Therefore, Bigger Number = 280
Smaller Number = 240

Incorrect

Answer – 1) 240
Explanation:
Let the bigger number = A
The smaller number= 520 – A
According to question,
A * ((100-4)/100) = (520 – A) * ((100 + 12)/100)
96A/100 = (520 – A) * (112/100)
96A = (520 – A) * 112
13A = 3640
A = 280
Therefore, Bigger Number = 280
Smaller Number = 240

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Equal sum of money are lent to X and Y at 7.5% per annum for a period of 4 years and 5 years respectively. If the difference in interest, paid by them was Rs 150. What was the sum lent to each?

Correct

Answer 4) 2000
Explanation:
Total Interest Rate for X= 7.5 * 4= 30%
Total Interest Rate for Y= 7.5 * 5= 37.5%
Difference in Rates= (37.5 – 30)% = 7.5%
According to question,
7.5% of sum= 150
1% of sum= 150/7.5
Individual Sum= (150/7.5) * 100
= Rs 2000
Therefore, Sum lent by X and Y each = Rs 2000

Incorrect

Answer 4) 2000
Explanation:
Total Interest Rate for X= 7.5 * 4= 30%
Total Interest Rate for Y= 7.5 * 5= 37.5%
Difference in Rates= (37.5 – 30)% = 7.5%
According to question,
7.5% of sum= 150
1% of sum= 150/7.5
Individual Sum= (150/7.5) * 100
= Rs 2000
Therefore, Sum lent by X and Y each = Rs 2000

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Two trains 125 meters and 115 meters in length are running towards each other on parallel lines, one at the rate of 33 Km/hr and the other at 39 Km/hr. How much time (in seconds) will they take to pass each other from the moment they meet?

Correct

Answer – 2) 12 seconds
Explanation:
Time taken by trains to cross each other in opposite direction
= (Total Distance/ Relative Speed in opposite direction)
= (125 + 115)/ ((33 + 39) * 5/18)
= (240 * 18)/ (72 * 5)
Time = 12 seconds

Incorrect

Answer – 2) 12 seconds
Explanation:
Time taken by trains to cross each other in opposite direction
= (Total Distance/ Relative Speed in opposite direction)
= (125 + 115)/ ((33 + 39) * 5/18)
= (240 * 18)/ (72 * 5)
Time = 12 seconds

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Three pipes A, B and C can fill a cistern in 6 hours. After working at it together for 2 hours, C is closed and A and B fill it in 7 hours more. How much time taken by C alone to fill the cistern?

Correct

Answer –3) 14 hours
Explanation:
Let Total capacity= 42 units
Therefore, (A + B + C) per hour work = 42/6 = 7 units
(A + B + C) fills the tank in 7 units/hr
They all worked for 2 Hours.
Total water filled= 7 * 2= 14 units
Capacity Left= 42 – 14= 28 units
A + B= 28/7= 4 units/hr
(A + B) efficiency 4 units
C’s efficiency= ((A + B + C) – (A + B))= 7 – 4= 3 units/hr
C can alone fill the cistern= Total Capacity/ Efficiency
= 42/3
= 14 hrs

Incorrect

Answer –3) 14 hours
Explanation:
Let Total capacity= 42 units
Therefore, (A + B + C) per hour work = 42/6 = 7 units
(A + B + C) fills the tank in 7 units/hr
They all worked for 2 Hours.
Total water filled= 7 * 2= 14 units
Capacity Left= 42 – 14= 28 units
A + B= 28/7= 4 units/hr
(A + B) efficiency 4 units
C’s efficiency= ((A + B + C) – (A + B))= 7 – 4= 3 units/hr
C can alone fill the cistern= Total Capacity/ Efficiency
= 42/3
= 14 hrs

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The tea costing Rs 192 per kg is to be mixed with tea costing Rs 150 per kg. In what ratio tea is mixed, when sold for Rs 194.40 per kg gives a profit of 20%?

Correct

Answer –5) 2:5
Explanation:

Incorrect

Answer –5) 2:5
Explanation:

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Find the wrong number in the series
1, 9, 32, 114, 478, 2400

What will come in the place of question mark(?) in the following question.
34 x 41 +65 x 29 -45 x 39 = ? x26 +16

Correct

Answer – 3) 58
Explanation
? x 26 = 34 x 41 + 65 x 29 – 45 x 39 -16
? x 26 = 1394 +1885 -1775-16
= 1508/26
= 58

Incorrect

Answer – 3) 58
Explanation
? x 26 = 34 x 41 + 65 x 29 – 45 x 39 -16
? x 26 = 1394 +1885 -1775-16
= 1508/26
= 58

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Shyam went to the market to buy 1.5kg of dried peas having 20% water content. He went home and soaked them for some time and the water content in the peas becomes 60%. Find the final weight of soaked peas.

Correct

Answer – 4) 3 kg
Explanation
Weight of dried peas = 1.5 kg
Water content = 20%
Hence, non-water content = 80% of 1.5
=0.8 x 1.5 = 1.2 kg (1)
Let the weight of the soaked pees = x kg
Water content = 60%
Non-water content = 40% of x kg = 0.4x (2)
From (1) and (2) an equal
Hence, 1.2x = 0.4x
X = 3

Incorrect

Answer – 4) 3 kg
Explanation
Weight of dried peas = 1.5 kg
Water content = 20%
Hence, non-water content = 80% of 1.5
=0.8 x 1.5 = 1.2 kg (1)
Let the weight of the soaked pees = x kg
Water content = 60%
Non-water content = 40% of x kg = 0.4x (2)
From (1) and (2) an equal
Hence, 1.2x = 0.4x
X = 3

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Each question is followed by two statements, I and II . Indicate your response based on the following instruction.

Which scheme between P and Q doubles the investment faster?
Statement I Scheme P – 16% per annum with interest compounded quarterly.
Statement II Scheme Q -18 % per annum with interest compounded half yearly.

Correct

Answer – 3) If the question can be answered using I and II together but not using I or II alone
Explanation
Statement I
In scheme P money grows at (1 + 4/100)2 = (1.04)2 = 1.0816
i.e the investment becomes 1.0816 times ever half year. But nothing is mentioned about Scheme Q. Hence I alone is not sufficient.
Statement II
In scheme Q money grows at (1 +9/100)2 .i.e. the investment becomes 1.09 times every half year. But nothing is mentioned about scheme P, hence II alone is sufficient.
From I and II together, we can answer the question as the rates in both schemes is known.

Incorrect

Answer – 3) If the question can be answered using I and II together but not using I or II alone
Explanation
Statement I
In scheme P money grows at (1 + 4/100)2 = (1.04)2 = 1.0816
i.e the investment becomes 1.0816 times ever half year. But nothing is mentioned about Scheme Q. Hence I alone is not sufficient.
Statement II
In scheme Q money grows at (1 +9/100)2 .i.e. the investment becomes 1.09 times every half year. But nothing is mentioned about scheme P, hence II alone is sufficient.
From I and II together, we can answer the question as the rates in both schemes is known.

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Solve the two statements to get quantities and then compare the two quantities.

Quantity I: Rohan sold two shirts, each for Rs 500. One is sold at a profit of 25% and another at a loss of 20%. What is overall percentage of profit/loss made by Rohan. Quantity II: Ramesh sold a watch at Rs 1000 and made a profit of 25% whereas he sold table for Rs 1500 at a loss of 20%. What is his overall percentage of profit/loss.

Correct

Answer – 1) Quantity I < Quantity II
Explanation
Quantity I
Total S.P of the two shirts =Rs 1000
C.P of one shirt with 25% profit = Rs 500/1.25 = Rs400
C.P of second shirt = Rs 500/.8 = Rs 625
Total C.P of both the shirts = Rs (400 + 625) = Rs 1025
Therefore loss % = (1025-1000)/1025 x 100 = 2.44%
Quantity II
C.P of the watch = Rs 1000/1.25 = Rs 800
C.P of the table = Rs 1500/.8 = Rs 1875
Total C.P of both the items = Rs (800 + 1875) = Rs 2675
S.P of both the items = Rs (1000 +1500) = Rs 2500
Hence Loss % = (2675-2500)/2675 x 100 = 6.54%

Incorrect

Answer – 1) Quantity I < Quantity II
Explanation
Quantity I
Total S.P of the two shirts =Rs 1000
C.P of one shirt with 25% profit = Rs 500/1.25 = Rs400
C.P of second shirt = Rs 500/.8 = Rs 625
Total C.P of both the shirts = Rs (400 + 625) = Rs 1025
Therefore loss % = (1025-1000)/1025 x 100 = 2.44%
Quantity II
C.P of the watch = Rs 1000/1.25 = Rs 800
C.P of the table = Rs 1500/.8 = Rs 1875
Total C.P of both the items = Rs (800 + 1875) = Rs 2675
S.P of both the items = Rs (1000 +1500) = Rs 2500
Hence Loss % = (2675-2500)/2675 x 100 = 6.54%

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