# IBPS PO 2017 Practice Test – Quant Day 5

Hello Aspirants.

Welcome to Online Reasoning Section with explanation in AffairsCloud.com. Here we are creating Best question samples for IBPS PO 2017. We have included Some questions that are repeatedly asked in bank exams !!!

IBPS PO 2017 : Reasoning Test– 6 PM Every Day
IBPS PO 2017 : Quants Test– 7 PM Every Day

Q(1-5) Find the missing number in the  series

1. 6, 7, 30, ?, 1274
A. 168
B. 172
C. 174
D. 175
E. None
Solution:
6*1 + 1² = 7
7 * 3 + 3² = 30
30 * 5 + 5² = 175
175 * 7 + 7² = 1274

2. 10, 12, 15, 25, 40, 66, ?
A. 100
B. 101
C. 102
D. 103
E. None
Solution:
10 + (1² + 1) = 12
12 + (2² – 1) = 15
15 + (3² + 1) = 25
25 + (4² – 1) = 40
40 + (5² + 1) = 66
66 + (6² – 1) = 101

3. 8, ?, 18, 44, 92, 174
A. 9
B. 10
C. 11
D. 12
E. None
Solution:
8+ (1² + 1) = 10
10+ (3² – 1) = 18
18+ (5² + 1) =44
44+ (7² – 1) = 92
92 + (9² + 1) = 174

4. 10, 15, 38, 123, ?, 2505
A. 400
B. 500
C. 550
D. 600
E. None
Solution:
10*1 + (1*5) =15
15 *2 + (2*4) =38
38 *3 + (3*3) = 123
123*4 + (4*2) =500
500*5 + (5*1) = 2505

5. 516 , ? , 505, 538, 494, 549
A. 525
B. 526
C. 527
D. 528
E. None
Solution:
516+11 = 527
527-22 =505
505+33 = 538
538-44 = 494
494+55 =549

Q(6-10) In the following questions two equations numbered I & II are given. You have to solve both equations and mark the option.

1. I. 2X²-10√2X+24 = 0
II. 2Y²-14√2Y+48 = 0
A. X > Y
B. X <Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be established
Solution:
X= 4/√2 , 6/√2
Y = 6/√2, 8/√2

2. I. 50X² -25√3X + 6 = 0
II. 50Y² -20√3Y + 6 = 0
A. X > Y
B. X <Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be established
Answer –E. X = Y or relationship cannot be established
Solution:
X = √3/10, 2√3/5
Y = √3/5, 2√3/10

3. I. X²- 85X + 1806 = 0
II. Y²- 89Y + 1980 = 0
A. X > Y
B. X <Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be established
Solution:
X = 42, 43
Y = 44, 45

4. I. 5X² -26X + 21 = 0
II. 2Y² -17Y + 21 = 0
A. X > Y
B. X <Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be established
Answer –E. X = Y or relationship cannot be established
Solution:
X= 4.2, 1
Y = 7, 1.5

5. I. X² + 25X + 156 = 0
II. Y² + 23Y + 132= 0
A. X > Y
B. X <Y
C. X ≥ Y
D. X ≤ Y
E. X = Y or relationship cannot be established