Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Prelims Exam.

**Stratus – IBPS Clerk Course 2015 **

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** Directions (1-5): Study the following table and answer the questions that follow: **

**In which period the percentage increase in the total internet owners is least to that over the earlier period?**

A) 2009-2010

B) 2010-2011

C) 2011-2012

D) 2013-2014

E) None of these**D) 2013-2014**

**Explanation:**

In this first you will have to calculate total owners in each fiscal year, and then find the percentage increase for adjacent years.

Like for yr 2012-13, total owners are 15,10,000

For yr 2013-2014, total owners are 25,00,000.

So % increase = 25,00,000-15,10,000/ 15,10,000 * 100 = 65.56%**What is the total number of fresh internet owners in the period 2013-14?**

A) 54900

B) 549000

C) 990000

D) 99000

E) None of these**C) 990000**

**Explanation:**

For yr 2012-13, total owners are 15,10,000

For yr 2013-2014, total owners are 25,00,000.

So fresh owners are 25,00,000-15,10,000 = 99,0000**What is the proportion of Government internet owners to the Private internet owners in the period 2011-12?**

A) 13 : 4

B) 13 : 3

C) 3 : 13

D) 4 : 13

E) None of these**B) 13 : 3**

**Explanation:**

520000 : 120000

13 : 3**What is the approximate percentage increase in the Private internet owners in the period 2013-14 over that in the period 2010-11?**

A) 5000

B) 6000

C) 8000

D) 4000

E) None of these**C) 8000**

**Explanation:**

For yr 2010-11, private owners are 12,000

For yr 2013-2014, private owners are 9,50,000.

% increase = (9,50,000 -12,000) / 12,000 * 100 = 7816.67 ≈ 8000**What is the approximate percentage of Private internet owners in the total internet owners in 2010-11?**

A) 20

B) 5

C) 10

D) 15

E) None of these**B) 5**

**Explanation:**

Total owners in 2010-11 = 12,000 + 2,30,000 = 2,42,000

So required % = 12000/242000 * 100 = 4.9 ≈ 5**18 men can do a piece of work in 26 days. 20 women can do the same piece of work in 33 days. 13 men start the work and do 1/3rd of the work. Now they are replaced by 22 women. In how many days the total work will be completed?**

A) 32

B) 40

C) 4

D) 56

E) None of these**A) 32**

**Explanation:**

18 m – 26 days, so 13 men do in 18*26/13 = 36 days. They complete 1/3rd of work. So number of days required by 13 men to complete that work is 36* 1/3= 12 days.

Now:

20 w – 33 days, so 22 w do in 20*33/22 = 30 days. They complete 2/3rd of work. So number of days required by 22 women to complete that work is 30* 2/3 = 20 days.

So total 12 +20 = 32 days**There is a profit of Rs 1200 on an article when 1/3rd of it is sold at 9% profit and remaining at 3% loss. Find the cost price of the aricle.**

A) Rs 1,80,000

B) Rs 1,50,000

C) Rs 1,60,000

D) Rs 1,20,000

E) None of these**D) Rs 1,20,000**

**Explanation:**

It can be calculated as:

CP = 1200 *100 / [1/3 *9 + 2/3 * (-3)] = 1,20,000

* 1/3rd sold at 9% profit, 2/3rd sold at 3% loss**There are 3 white balls, 4 yellow, and 5 green balls. 3 balls are drawn at random. What is the probability of all white or all green balls?**

A) 9/150

B) 5/186

C) 11/220

D) 11/240

E) 13/220**C) 11/220**

**Explanation:**

Probability of all white =^{3}C_{3}/^{12}C_{3}= 1/220

Probability of all green =^{5}C_{3}/^{12}C_{3}= 10/220

So probability of all white or all green = 1/220 + 10/220 = 11/220**The compound interest on a certain sum of money for 2 years at 20% per annum is Rs 3,520. Find the simple interest at the same rate and for the same time.**

A) Rs 3000

B) Rs 3200

C) Rs 3635

D) Rs 3400

E) Rs 3440**B) Rs 3200**

**Explanation:**

If P is the principal, SI for 2 yrs = P*20*2/100 = 2P/5

So, SI for 1 yr = P/5

CI for 2 yrs = P/5 + (P/5 + 20/100 * P/5) = 2P/5 + P/25 = 11P/25

Now, 11P/25 = 3520, so P = 8,000

So SI = 2*8000/5 = 3200**A person travels at a speed of 50 km/hr for 5 hours and at 60 km/hr for 3 hours. After this he could cover only 2/5th of the distance of his journey. At what speed should he travel now, so as to complete his remaining journey in 15 hours?**

A) 40 km/hr

B) 45 km/hr

C) 42 km/hr

D) 43 km/hr

E) None of these**D) 43 km/hr**

**Explanation:**

Distance travelled when 2/5th of journey is completed = 50*5 + 60*3 = 430 km.

This means 2/5 of total distance = 430. So total distance = 1075 km

Now he has to cover 3/5 * 1075 = 645 km in 5 hours.

So speed = 645/15 = 43 km/hr

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