Hello Aspirants. Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Prelims Exam.

**Stratus – IBPS Clerk Course 2015 **

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** Directions (1-5): Study the following pie-charts and answer the questions that follow: There are 5 sections in a class with given information in the pie-char **

**Find the ratio of the total number of students in sections C and D to number of males in the same sections.**A) 336 : 169 B) 313 : 169 C) 360 : 147 D) 336 : 149 E) None of these**A) 336 : 169**Explanation: Students in C and D = (15+13)/100 * 2400 = 672 No of males in C and D = (6+20)/100 * 1300 = 338 So ratio = 672 : 338 = 336 : 169**What is the average number of females in sections A and C?**A) 370.5 B) 334 C) 384.5 D) 390.5 E) 357**B) 370.5**Explanation: Students in A and C = (37+15)/100 * 2400 = 1248 No of males in A and C = (33+6)/100 * 1300 = 507 So females in A and C = 1248 – 507 = 741, so average = 741/2 = 370.5**Find the angle subtended by C section in the total number of students diagram.**A) 72^{o}B) 55^{o}C) 60^{o}D) 54^{o}E) 57^{o}**D) 54**Explanation: 15/100 * 360 = 54^{o}^{o}**Find the ratio of the number of males in D section to the females in section E.**A) 260 : 191 B) 260 : 137 C) 460 : 19 D) 260 : 21 E) 260 : 19**E) 260 : 19**Explanation: Males in D = 20/100 * 1300 = 260 Students in E = 10/100 * 2400 = 240, males in E = 17/100 * 1300 = 221, so females in E = 240 – 221 = 19 Ratio = 260 : 19**What is the number of females in sections A and B?**A) 740 B) 747 C) 737 D) 741 E) 742**B) 747**Explanation: Students in A and B = (37+25)/100 * 2400 = 1488 Males in A and B = (33+24)/100 * 1300 = 741 So females = 1488 – 741 = 747**A mixture contains A and B in the ratio of 5 : 3. 16 litres of this mixture is taken out and 5 litres of A is poured in. the new mixture has ratio of A to b as 11 : 6. Find the total original quantity of mixture.**A) 80 litres B) 96 litres C) 98 litres D) 84 litres E) 92 litres**B) 96 litres**Explanation: A = 5x, B = 3x After taking out 16 l of mixture, A = 5x – 5(5+3) * 16 = 5x – 10 B = 3x – 3(5+3) * 16 = 3x – 6 After pouring 5 l of A, A = 5x – 10 + 5 = 5x – 5 So now, 5x-5/3x-6 = 11/6 Solve, x = 12 Total original quantity = 5x+3x = 8x = 8*12 = 96 litres**A bag contains 3 white balls, 5 black balls and 4 yellow balls. 3 balls are drawn at random. What is the probability that atmost 1 ball is black in color?**A. 5/22 B. 2/9 C. 8/11 D. 7/11 E) None of these**D. 7/11**Explanation: Atmost 1 black means 0 black or 1 black Case 1 : none is black None is black means 3 balls from 7 balls (3 w + 4 y), ways are^{7}C_{3}= 7*6*5/3*2*1 = 35 Case 2: 1 ball black and other 2 white or yellow Ways are^{5}C_{1}×^{7}C_{2}= 5 * 7*6/2*1 = 105 There are a total of 12 balls. Ways for drawing 3 balls is^{12}C_{3}= 12*11*10/3*2*1 = 220 So required prob. = 35+105/220 = 140/220 = 7/11**A man reaches at 10 AM from P to Q when his average speed is 15 km/hr and reaches at 12 noon when the average speed is 10 km/hr. What should be the average speed to reach at 9 AM?**A. 18 km/hr B. 20 km/hr C. 22 km/hr D. 25 km/hrB. 20 km/hr Explanation: Let distance from P to Q is ‘d’ and time taken to reach at 9 AM is ‘t’ Then with 10 AM, time becomes ‘t+1’, so d/(t+1) = 15 With 12 noon, time becomes ‘t+3’, so d/(t+3) = 10 Solve the equations, t = 3 hrs, d = 60 km So speed to reach at 9 AM = 60/3 = 20 km/hr**A and B started a business by investing Rs 6400 and Rs 4600 respectively. After 4 months both withdraw Rs 400 and C joined them with Rs 8000. At the end of year, what will be the ratio of their profits?**A) 92 : 55 : 80 B) 92 : 65 : 80 C) 72 : 25 : 56 D) 80 : 57 : 44 E) None of these**B) 92 : 65 : 80**Explanation: A’s share : B’s share : C’s share 6400*4 + 6000*8 : 4600*4 + 4200*8 : 8000*8 Two 0’s get cancelled, we are left with 64*4 + 60*8 : 46*4 + 42*8 : 80*8 We can see that 8 gets cancelled from each term, now left with 32 + 60 : 23 + 42 : 80 92 : 65 : 80**A’s age 8 years ago was four less than B’s age that time. Ratio of A’s age 8 years after and B’s age that time will be 6 : 7. Find the ratio of A’s age after 4 years to that of B’s age at that time.**A) 2 : 5 B) 3 : 4 C) 5 : 7 D) 6 : 5 E) 5 : 6**E) 5 : 6**Explanation: Let the present ages of A and B are x and y respectively. 8 years ago, x-8 = (y-8) – 4. This gives x – y = -4 After 8 years, x+8/ y+8 = 6/7. This gives 7x – 6y = -8 Solve both equations, x = 16, y = 20 So required ratio = (16+4) : (20+4) = 20 : 24 = 5 : 6

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