**Hello Aspirants,**

Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Main Exam.

**Stratus – IBPS Clerk Course 2015 **

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** Directions (1-5): What will come in place of (?) in the following series? **

**6, 4, 5, 11, 39, 189, ?**

A) 1039

B) 1127

C) 1150

D) 1129

E) 1189

**B) 1127**

Explanation:

6*1 – 2, 4*2 – 3, 5*3 – 4, 11*4 – 5, 39*5 – 6, 189*6 – 7

**0, 6, 60, 210, 504, ?**

A) 950

B) 840

C) 990

D) 1010

E) None of these

**C) 990**

Explanation:

0^3 – 0, 2^3 – 2, 4^3 – 4, 6^3 – 6, 8^3 – 8, 10^3 – 10

**120, 80, 48, 24, ?**

A) 8

B) 12

C) 10

D) 16

E) 2

**A) 8**

Explanation:

11^2 – 1, 9^2 – 1, 7^2 – 1, 5^2 – 1, 3^2 – 1**7, 11, 25, 47, ?**

A) 120

B) 78

C) 115

D) 97

E) 102

**D) 97**

Explanation:

7, 7*2 – 3, 11*2 + 3, 25*2 – 3, 47*2 + 3**12, 17, 30, 51, 80, ?**

A) 122

B) 102

C) 115

D) 136

E) None of these

**E) None of these**

Explanation:

17-12 = 5, 30-17 = 13, 51-30 = 21, 80-51 = 29

13-5 = 8, 21-13 = 8, 29-21 = 8

So next number is 80+29+8 = 117

**A milk vendor purchased pure milk at Rs 40 per litre. He diluted the milk with water and sold at Rs 40 per litre and in this he gains 60% profit. In diluted milk what is the amount of pure milk taken?**

A) 375 ml

B) 500 ml

C) 625 ml

D) 600 ml

E) 525 ml

**C) 625 ml**

Explanation:

Since the diluted milk is sold at same price at which pure milk was bought,

Profit% = [(difference in actual weight and given)/(given weight)] * 100

Let from 1000 ml, x ml of pure milk is taken

Then [(1000-x)/x] * 100 = 60

**5 kgs of wheat costing Rs 15 per kg is mixed with 10 kgs of wheat costing Rs 12 per kg. The mixture is then sold at 20% profit. Find the selling price of the mixture in Rs/kg.**

A) 14

B) 15.60

C) 16

D) 14.40

E) None of these

**B) 15.60**

Explanation:

Let x is the cost price, then by method of allegation:

Wheat(5 kg) wheat(10 kg)

15 12

. x

x-12 15-x

so [(x-12)/(15-x)] = 5/10

solve, x = 13

so at profit 20%, SP = (120/100) * 13**An old advisor of a company was replaced by a young man. As a result, the average age of the board of ten advisors of the company was the same as it was 4 years ago. How much younger is the young man who replaced the old advisor?**

A) 42 years

B) 40 years

C) 36 years

D) 32 years

E) Cannot be determined

**C) 36 years**

Explanation:

The difference of 4 years has come in the age of each of 9 remaining advisors, and since the average is the same, there is the difference of (4*9) = 36 years in the age of old and the young man.**A and B alone can complete a work in 40 and 60 days respectively. A works on the work for some days and then B joins him and together they complete the work in 10 days less than the number of days A takes alone to complete the work. After how many days did B joined A?**

A) 15 days

B) 12 days

C) 20 days

D) 10 days

E) 16 days

**A) 15 days**

Explanation:

Let A works for x days, now B joins and together they complete work in 30 days, this means A and B have together worked for (30-x) days.

So (1/40) * x + (1/40 + 1/60) * (30-x) = 1

Solve, x = 15

**A is one and a half times more efficient than B. A alone can do a work in 20 days. What portion of total work can both of them together complete in 10 days?**

A) 2/5

B) 7/10

C) 3/10

D) 4/5

E) 9/10

**B) 7/10**

Explanation:

Let efficiency of B is x, then of A is 1 + 1(1/2) = 5x/2

Ratio of efficiencies of A : B = 5x/2 : x= 5 : 2

So ratio of number of days of A : B = 2 : 5

A completes work in 20 days, so 2x = 20, x = 10

So B alone completes work in 5x days = 50 days

(A+B)’s 1 day’s work = 1/20 + 1/50 = 7/100

So in 10 days, pat of work completed is 10 * (7/100) = 7/10

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