Hello Aspirants. Welcome to Online Quants Section in AffairsCloud.com.We are Starting Stratus –IBPS Clerk course 2016 and we are creating question sample in Quatitative Aptitude section, Which will be asked in IBPS Main Prelims Exam.
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Question 1 of 10
1. Question
1 points
Category: Quantitative Aptitude
Directions (1-5): Study the following table and answer the questions that follow:
Year
No. of Students in
Government
Schools
Private
Schools
2007-2008
3900
0
2008-2009
29400
0
2009-2010
90000
0
2010-2011
230000
12000
2011-2012
520000
120000
2012-2013
1060000
450000
2013-2014
1550000
950000
In which period the percentage increase in the total students is least to that over the earlier period?
Correct
Explanation:
In this first you will have to calculate total students in each fiscal year, and then find the percentage increase for adjacent years.
Like for year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So % increase in 2013-2014= (25,00,000 – 15,10,000)/15,10,000 * 100 = 65.56%
Incorrect
Explanation:
In this first you will have to calculate total students in each fiscal year, and then find the percentage increase for adjacent years.
Like for year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So % increase in 2013-2014= (25,00,000 – 15,10,000)/15,10,000 * 100 = 65.56%
Question 2 of 10
2. Question
1 points
Category: Quantitative Aptitude
Directions (1-5): Study the following table and answer the questions that follow:
Year
No. of Students in
Government
Schools
Private
Schools
2007-2008
3900
0
2008-2009
29400
0
2009-2010
90000
0
2010-2011
230000
12000
2011-2012
520000
120000
2012-2013
1060000
450000
2013-2014
1550000
950000
What is the total number of new students in the period 2013-14?
Correct
Explanation:
For year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So new students are 25,00,000 – 15,10,000 = 99,0000
Incorrect
Explanation:
For year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So new students are 25,00,000 – 15,10,000 = 99,0000
Question 3 of 10
3. Question
1 points
Category: Quantitative Aptitude
Directions (1-5): Study the following table and answer the questions that follow:
Year
No. of Students in
Government
Schools
Private
Schools
2007-2008
3900
0
2008-2009
29400
0
2009-2010
90000
0
2010-2011
230000
12000
2011-2012
520000
120000
2012-2013
1060000
450000
2013-2014
1550000
950000
What is the proportion of students in Government schools to the Private schools in the period 2011-12?
Correct
Explanation:
520000 : 120000
13 : 3
Incorrect
Explanation:
520000 : 120000
13 : 3
Question 4 of 10
4. Question
1 points
Category: Quantitative Aptitude
Directions (1-5): Study the following table and answer the questions that follow:
Year
No. of Students in
Government
Schools
Private
Schools
2007-2008
3900
0
2008-2009
29400
0
2009-2010
90000
0
2010-2011
230000
12000
2011-2012
520000
120000
2012-2013
1060000
450000
2013-2014
1550000
950000
What is the approximate percentage increase in the students in Private schools in the period 2013-14 over that in the period 2010-11?
Correct
Explanation:
For year 2010-11, students in Private schools are 12,000
For year 2013-2014, students in Private schools are 9,50,000.
% increase = (9,50,000 -12,000) / 12,000 * 100 = 7816.67 ≈ 8000
Incorrect
Explanation:
For year 2010-11, students in Private schools are 12,000
For year 2013-2014, students in Private schools are 9,50,000.
% increase = (9,50,000 -12,000) / 12,000 * 100 = 7816.67 ≈ 8000
Question 5 of 10
5. Question
1 points
Category: Quantitative Aptitude
Directions (1-5): Study the following table and answer the questions that follow:
Year
No. of Students in
Government
Schools
Private
Schools
2007-2008
3900
0
2008-2009
29400
0
2009-2010
90000
0
2010-2011
230000
12000
2011-2012
520000
120000
2012-2013
1060000
450000
2013-2014
1550000
950000
What is the approximate percentage of students in Private schools in the total students in 2010-11?
Correct
Explanation:
Total students in 2010-11 = 12,000 + 2,30,000 = 2,42,000
So required % = 12000/242000 * 100 = 4.9 ≈ 5
Incorrect
Explanation:
Total students in 2010-11 = 12,000 + 2,30,000 = 2,42,000
So required % = 12000/242000 * 100 = 4.9 ≈ 5
Question 6 of 10
6. Question
1 points
Category: Quantitative Aptitude
A work which can be completed by 18 men in 26 days can also be done by 20 women in 33 days. 13 men start doing the work and complete one-third of the work. If they are now replaced by 22 women, in how many days the total work will be completed?
Correct
Explanation:
18 m in 26 days, so 13 men do in 18*26/13 = 36 days. They complete 1/3rd of work. So number of days required by 13 men to complete that work is 36* 1/3= 12 days.
Now:
20 w in 33 days, so 22 w do in 20*33/22 = 30 days. They complete 2/3rd of work. So number of days required by 22 women to complete that work is 30* 2/3 = 20 days.
So total 12 +20 = 32 days
Incorrect
Explanation:
18 m in 26 days, so 13 men do in 18*26/13 = 36 days. They complete 1/3rd of work. So number of days required by 13 men to complete that work is 36* 1/3= 12 days.
Now:
20 w in 33 days, so 22 w do in 20*33/22 = 30 days. They complete 2/3rd of work. So number of days required by 22 women to complete that work is 30* 2/3 = 20 days.
So total 12 +20 = 32 days
Question 7 of 10
7. Question
1 points
Category: Quantitative Aptitude
A profit of Rs 1200 is made by selling an article if one-third of it is sold at 9% profit and the remaining at 3% loss. What is the cost price of the article?
Correct
Explanation:
It can be calculated as:
CP = 1200 *100 / [1/3 *9 + 2/3 * (-3)] = 1,20,000
* 1/3rd sold at 9% profit, 2/3rd sold at 3% loss
Incorrect
Explanation:
It can be calculated as:
CP = 1200 *100 / [1/3 *9 + 2/3 * (-3)] = 1,20,000
* 1/3rd sold at 9% profit, 2/3rd sold at 3% loss
Question 8 of 10
8. Question
1 points
Category: Quantitative Aptitude
There are 3 blue balls, 4 red, and 5 green balls. 3 balls are drawn at random. What is the probability of all blue or all green balls?
Correct
Explanation:
Probability of all blue = 3C3 / 12C3 = 1/220
Probability of all green = 5C3 / 12C3 = 10/220
So probability of all blue or all green = 1/220 + 10/220 = 11/220
Incorrect
Explanation:
Probability of all blue = 3C3 / 12C3 = 1/220
Probability of all green = 5C3 / 12C3 = 10/220
So probability of all blue or all green = 1/220 + 10/220 = 11/220
Question 9 of 10
9. Question
1 points
Category: Quantitative Aptitude
On a certain sum of money, compound interest obtained is Rs 3,520 after 2 years at 20% per annum. What will be the simple interest obtained at the same rate and for the same time.
Correct
Explanation:
If P is the principal, SI for 2 years = P*20*2/100 = 2P/5
So, SI for 1 year = P/5
CI for 2 years = P/5 + (P/5 + 20/100 * P/5) = 2P/5 + P/25 = 11P/25
Now, 11P/25 = 3520, so P = 8,000
So SI = 2*8000/5 = 3200
Incorrect
Explanation:
If P is the principal, SI for 2 years = P*20*2/100 = 2P/5
So, SI for 1 year = P/5
CI for 2 years = P/5 + (P/5 + 20/100 * P/5) = 2P/5 + P/25 = 11P/25
Now, 11P/25 = 3520, so P = 8,000
So SI = 2*8000/5 = 3200
Question 10 of 10
10. Question
1 points
Category: Quantitative Aptitude
A person whose monthly salary is Rs 10,000 has expenditure of Rs 6,000. In the next month, his salary increases by 10% and so he increases his expenditure by 20%. What is the percentage change in his savings made?
Correct
Explanation:
Savings = 10,000 – 6000 = 4000
Income becomes = (110/100)*10,000 = 11,000
Exp. becomes = (120/100)*6,000 = 7,200
So savings now = 11000 – 7200 = 3800
So % decrease in savings = (4000-3800)/4000 * 100 = 5%
Incorrect
Explanation:
Savings = 10,000 – 6000 = 4000
Income becomes = (110/100)*10,000 = 11,000
Exp. becomes = (120/100)*6,000 = 7,200
So savings now = 11000 – 7200 = 3800
So % decrease in savings = (4000-3800)/4000 * 100 = 5%
