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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (15): Study the following table and answer the questions that follow:
Year No. of Students in Government
SchoolsPrivate
Schools20072008 3900 0 20082009 29400 0 20092010 90000 0 20102011 230000 12000 20112012 520000 120000 20122013 1060000 450000 20132014 1550000 950000 In which period the percentage increase in the total students is least to that over the earlier period?
Correct
Explanation:
In this first you will have to calculate total students in each fiscal year, and then find the percentage increase for adjacent years.
Like for year 201213, total students are 15,10,000
For year 20132014, total students are 25,00,000.
So % increase in 20132014= (25,00,000 – 15,10,000)/15,10,000 * 100 = 65.56%Incorrect
Explanation:
In this first you will have to calculate total students in each fiscal year, and then find the percentage increase for adjacent years.
Like for year 201213, total students are 15,10,000
For year 20132014, total students are 25,00,000.
So % increase in 20132014= (25,00,000 – 15,10,000)/15,10,000 * 100 = 65.56% 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (15): Study the following table and answer the questions that follow:
Year No. of Students in Government
SchoolsPrivate
Schools20072008 3900 0 20082009 29400 0 20092010 90000 0 20102011 230000 12000 20112012 520000 120000 20122013 1060000 450000 20132014 1550000 950000 What is the total number of new students in the period 201314?
Correct
Explanation:
For year 201213, total students are 15,10,000
For year 20132014, total students are 25,00,000.
So new students are 25,00,000 – 15,10,000 = 99,0000Incorrect
Explanation:
For year 201213, total students are 15,10,000
For year 20132014, total students are 25,00,000.
So new students are 25,00,000 – 15,10,000 = 99,0000 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (15): Study the following table and answer the questions that follow:
Year No. of Students in Government
SchoolsPrivate
Schools20072008 3900 0 20082009 29400 0 20092010 90000 0 20102011 230000 12000 20112012 520000 120000 20122013 1060000 450000 20132014 1550000 950000 What is the proportion of students in Government schools to the Private schools in the period 201112?
Correct
Explanation:
520000 : 120000
13 : 3Incorrect
Explanation:
520000 : 120000
13 : 3 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (15): Study the following table and answer the questions that follow:
Year No. of Students in Government
SchoolsPrivate
Schools20072008 3900 0 20082009 29400 0 20092010 90000 0 20102011 230000 12000 20112012 520000 120000 20122013 1060000 450000 20132014 1550000 950000 What is the approximate percentage increase in the students in Private schools in the period 201314 over that in the period 201011?
Correct
Explanation:
For year 201011, students in Private schools are 12,000
For year 20132014, students in Private schools are 9,50,000.
% increase = (9,50,000 12,000) / 12,000 * 100 = 7816.67 ≈ 8000Incorrect
Explanation:
For year 201011, students in Private schools are 12,000
For year 20132014, students in Private schools are 9,50,000.
% increase = (9,50,000 12,000) / 12,000 * 100 = 7816.67 ≈ 8000 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (15): Study the following table and answer the questions that follow:
Year No. of Students in Government
SchoolsPrivate
Schools20072008 3900 0 20082009 29400 0 20092010 90000 0 20102011 230000 12000 20112012 520000 120000 20122013 1060000 450000 20132014 1550000 950000 What is the approximate percentage of students in Private schools in the total students in 201011?
Correct
Explanation:
Total students in 201011 = 12,000 + 2,30,000 = 2,42,000
So required % = 12000/242000 * 100 = 4.9 ≈ 5Incorrect
Explanation:
Total students in 201011 = 12,000 + 2,30,000 = 2,42,000
So required % = 12000/242000 * 100 = 4.9 ≈ 5 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA work which can be completed by 18 men in 26 days can also be done by 20 women in 33 days. 13 men start doing the work and complete onethird of the work. If they are now replaced by 22 women, in how many days the total work will be completed?
Correct
Explanation:
18 m in 26 days, so 13 men do in 18*26/13 = 36 days. They complete 1/3rd of work. So number of days required by 13 men to complete that work is 36* 1/3= 12 days.
Now:
20 w in 33 days, so 22 w do in 20*33/22 = 30 days. They complete 2/3rd of work. So number of days required by 22 women to complete that work is 30* 2/3 = 20 days.
So total 12 +20 = 32 daysIncorrect
Explanation:
18 m in 26 days, so 13 men do in 18*26/13 = 36 days. They complete 1/3rd of work. So number of days required by 13 men to complete that work is 36* 1/3= 12 days.
Now:
20 w in 33 days, so 22 w do in 20*33/22 = 30 days. They complete 2/3rd of work. So number of days required by 22 women to complete that work is 30* 2/3 = 20 days.
So total 12 +20 = 32 days 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA profit of Rs 1200 is made by selling an article if onethird of it is sold at 9% profit and the remaining at 3% loss. What is the cost price of the article?
Correct
Explanation:
It can be calculated as:
CP = 1200 *100 / [1/3 *9 + 2/3 * (3)] = 1,20,000
* 1/3rd sold at 9% profit, 2/3rd sold at 3% lossIncorrect
Explanation:
It can be calculated as:
CP = 1200 *100 / [1/3 *9 + 2/3 * (3)] = 1,20,000
* 1/3rd sold at 9% profit, 2/3rd sold at 3% loss 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThere are 3 blue balls, 4 red, and 5 green balls. 3 balls are drawn at random. What is the probability of all blue or all green balls?
Correct
Explanation:
Probability of all blue = ^{3}C_{3} / ^{12}C_{3} = 1/220
Probability of all green = ^{5}C_{3} / ^{12}C_{3} = 10/220
So probability of all blue or all green = 1/220 + 10/220 = 11/220Incorrect
Explanation:
Probability of all blue = ^{3}C_{3} / ^{12}C_{3} = 1/220
Probability of all green = ^{5}C_{3} / ^{12}C_{3} = 10/220
So probability of all blue or all green = 1/220 + 10/220 = 11/220 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeOn a certain sum of money, compound interest obtained is Rs 3,520 after 2 years at 20% per annum. What will be the simple interest obtained at the same rate and for the same time.
Correct
Explanation:
If P is the principal, SI for 2 years = P*20*2/100 = 2P/5
So, SI for 1 year = P/5
CI for 2 years = P/5 + (P/5 + 20/100 * P/5) = 2P/5 + P/25 = 11P/25
Now, 11P/25 = 3520, so P = 8,000
So SI = 2*8000/5 = 3200Incorrect
Explanation:
If P is the principal, SI for 2 years = P*20*2/100 = 2P/5
So, SI for 1 year = P/5
CI for 2 years = P/5 + (P/5 + 20/100 * P/5) = 2P/5 + P/25 = 11P/25
Now, 11P/25 = 3520, so P = 8,000
So SI = 2*8000/5 = 3200 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA person whose monthly salary is Rs 10,000 has expenditure of Rs 6,000. In the next month, his salary increases by 10% and so he increases his expenditure by 20%. What is the percentage change in his savings made?
Correct
Explanation:
Savings = 10,000 – 6000 = 4000
Income becomes = (110/100)*10,000 = 11,000
Exp. becomes = (120/100)*6,000 = 7,200
So savings now = 11000 – 7200 = 3800
So % decrease in savings = (40003800)/4000 * 100 = 5%Incorrect
Explanation:
Savings = 10,000 – 6000 = 4000
Income becomes = (110/100)*10,000 = 11,000
Exp. becomes = (120/100)*6,000 = 7,200
So savings now = 11000 – 7200 = 3800
So % decrease in savings = (40003800)/4000 * 100 = 5%
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