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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Directions (1-5): Study the following table and answer the questions that follow:

Year

No. of Students in

Government
Schools

Private
Schools

2007-2008

3900

0

2008-2009

29400

0

2009-2010

90000

0

2010-2011

230000

12000

2011-2012

520000

120000

2012-2013

1060000

450000

2013-2014

1550000

950000

In which period the percentage increase in the total students is least to that over the earlier period?

Correct

Explanation:
In this first you will have to calculate total students in each fiscal year, and then find the percentage increase for adjacent years.
Like for year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So % increase in 2013-2014= (25,00,000 – 15,10,000)/15,10,000 * 100 = 65.56%

Incorrect

Explanation:
In this first you will have to calculate total students in each fiscal year, and then find the percentage increase for adjacent years.
Like for year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So % increase in 2013-2014= (25,00,000 – 15,10,000)/15,10,000 * 100 = 65.56%

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Directions (1-5): Study the following table and answer the questions that follow:

Year

No. of Students in

Government
Schools

Private
Schools

2007-2008

3900

0

2008-2009

29400

0

2009-2010

90000

0

2010-2011

230000

12000

2011-2012

520000

120000

2012-2013

1060000

450000

2013-2014

1550000

950000

What is the total number of new students in the period 2013-14?

Correct

Explanation:
For year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So new students are 25,00,000 – 15,10,000 = 99,0000

Incorrect

Explanation:
For year 2012-13, total students are 15,10,000
For year 2013-2014, total students are 25,00,000.
So new students are 25,00,000 – 15,10,000 = 99,0000

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions (1-5): Study the following table and answer the questions that follow:

Year

No. of Students in

Government
Schools

Private
Schools

2007-2008

3900

0

2008-2009

29400

0

2009-2010

90000

0

2010-2011

230000

12000

2011-2012

520000

120000

2012-2013

1060000

450000

2013-2014

1550000

950000

What is the proportion of students in Government schools to the Private schools in the period 2011-12?

Correct

Explanation:
520000 : 120000
13 : 3

Incorrect

Explanation:
520000 : 120000
13 : 3

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions (1-5): Study the following table and answer the questions that follow:

Year

No. of Students in

Government
Schools

Private
Schools

2007-2008

3900

0

2008-2009

29400

0

2009-2010

90000

0

2010-2011

230000

12000

2011-2012

520000

120000

2012-2013

1060000

450000

2013-2014

1550000

950000

What is the approximate percentage increase in the students in Private schools in the period 2013-14 over that in the period 2010-11?

Correct

Explanation:
For year 2010-11, students in Private schools are 12,000
For year 2013-2014, students in Private schools are 9,50,000.
% increase = (9,50,000 -12,000) / 12,000 * 100 = 7816.67 ≈ 8000

Incorrect

Explanation:
For year 2010-11, students in Private schools are 12,000
For year 2013-2014, students in Private schools are 9,50,000.
% increase = (9,50,000 -12,000) / 12,000 * 100 = 7816.67 ≈ 8000

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions (1-5): Study the following table and answer the questions that follow:

Year

No. of Students in

Government
Schools

Private
Schools

2007-2008

3900

0

2008-2009

29400

0

2009-2010

90000

0

2010-2011

230000

12000

2011-2012

520000

120000

2012-2013

1060000

450000

2013-2014

1550000

950000

What is the approximate percentage of students in Private schools in the total students in 2010-11?

Correct

Explanation:
Total students in 2010-11 = 12,000 + 2,30,000 = 2,42,000
So required % = 12000/242000 * 100 = 4.9 ≈ 5

Incorrect

Explanation:
Total students in 2010-11 = 12,000 + 2,30,000 = 2,42,000
So required % = 12000/242000 * 100 = 4.9 ≈ 5

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

A work which can be completed by 18 men in 26 days can also be done by 20 women in 33 days. 13 men start doing the work and complete one-third of the work. If they are now replaced by 22 women, in how many days the total work will be completed?

Correct

Explanation:
18 m in 26 days, so 13 men do in 18*26/13 = 36 days. They complete 1/3rd of work. So number of days required by 13 men to complete that work is 36* 1/3= 12 days.
Now:
20 w in 33 days, so 22 w do in 20*33/22 = 30 days. They complete 2/3rd of work. So number of days required by 22 women to complete that work is 30* 2/3 = 20 days.
So total 12 +20 = 32 days

Incorrect

Explanation:
18 m in 26 days, so 13 men do in 18*26/13 = 36 days. They complete 1/3rd of work. So number of days required by 13 men to complete that work is 36* 1/3= 12 days.
Now:
20 w in 33 days, so 22 w do in 20*33/22 = 30 days. They complete 2/3rd of work. So number of days required by 22 women to complete that work is 30* 2/3 = 20 days.
So total 12 +20 = 32 days

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

A profit of Rs 1200 is made by selling an article if one-third of it is sold at 9% profit and the remaining at 3% loss. What is the cost price of the article?

Correct

Explanation:
It can be calculated as:
CP = 1200 *100 / [1/3 *9 + 2/3 * (-3)] = 1,20,000
* 1/3rd sold at 9% profit, 2/3rd sold at 3% loss

Incorrect

Explanation:
It can be calculated as:
CP = 1200 *100 / [1/3 *9 + 2/3 * (-3)] = 1,20,000
* 1/3rd sold at 9% profit, 2/3rd sold at 3% loss

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

There are 3 blue balls, 4 red, and 5 green balls. 3 balls are drawn at random. What is the probability of all blue or all green balls?

Correct

Explanation:
Probability of all blue = ^{3}C_{3} / ^{12}C_{3} = 1/220
Probability of all green = ^{5}C_{3} / ^{12}C_{3} = 10/220
So probability of all blue or all green = 1/220 + 10/220 = 11/220

Incorrect

Explanation:
Probability of all blue = ^{3}C_{3} / ^{12}C_{3} = 1/220
Probability of all green = ^{5}C_{3} / ^{12}C_{3} = 10/220
So probability of all blue or all green = 1/220 + 10/220 = 11/220

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

On a certain sum of money, compound interest obtained is Rs 3,520 after 2 years at 20% per annum. What will be the simple interest obtained at the same rate and for the same time.

Correct

Explanation:
If P is the principal, SI for 2 years = P*20*2/100 = 2P/5
So, SI for 1 year = P/5
CI for 2 years = P/5 + (P/5 + 20/100 * P/5) = 2P/5 + P/25 = 11P/25
Now, 11P/25 = 3520, so P = 8,000
So SI = 2*8000/5 = 3200

Incorrect

Explanation:
If P is the principal, SI for 2 years = P*20*2/100 = 2P/5
So, SI for 1 year = P/5
CI for 2 years = P/5 + (P/5 + 20/100 * P/5) = 2P/5 + P/25 = 11P/25
Now, 11P/25 = 3520, so P = 8,000
So SI = 2*8000/5 = 3200

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

A person whose monthly salary is Rs 10,000 has expenditure of Rs 6,000. In the next month, his salary increases by 10% and so he increases his expenditure by 20%. What is the percentage change in his savings made?

Correct

Explanation:
Savings = 10,000 – 6000 = 4000
Income becomes = (110/100)*10,000 = 11,000
Exp. becomes = (120/100)*6,000 = 7,200
So savings now = 11000 – 7200 = 3800
So % decrease in savings = (4000-3800)/4000 * 100 = 5%

Incorrect

Explanation:
Savings = 10,000 – 6000 = 4000
Income becomes = (110/100)*10,000 = 11,000
Exp. becomes = (120/100)*6,000 = 7,200
So savings now = 11000 – 7200 = 3800
So % decrease in savings = (4000-3800)/4000 * 100 = 5%