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The average age of 100 nurses in a nursing home in 2002 was 50 years. In 2004, 20 nurses retired from their job, whose average age was 60 years. After a gap, in 2007, 40 nurses were employed whose average age was 38 years. The average age of all the nurses in 2010 was?

Correct

Answer:3. 51 years
Solution:
In 2002: 100*50 =5000
In 2004: 5000+2*100-20*60 = 4000
In 2007: 4000+80*3+40*38 = 5760
In 2009: 5760+120*3 = 6120
Average = 6120/120 =51
Solution:
In 2002: 100*50 =5000
In 2004: 5000+2*100-20*60 = 4000
In 2007: 4000+80*3+40*38 = 5760
In 2009: 5760+120*3 = 6120
Average = 6120/120 =51

Incorrect

Answer:3. 51 years
Solution:
In 2002: 100*50 =5000
In 2004: 5000+2*100-20*60 = 4000
In 2007: 4000+80*3+40*38 = 5760
In 2009: 5760+120*3 = 6120
Average = 6120/120 =51
Solution:
In 2002: 100*50 =5000
In 2004: 5000+2*100-20*60 = 4000
In 2007: 4000+80*3+40*38 = 5760
In 2009: 5760+120*3 = 6120
Average = 6120/120 =51

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Equal amounts of each Rs. 54,612 is lend to two persons for 3 years. One at the rate of 30% SI per annum and second at the rate of 30% CI annually. By how much per cent the C.I. is greater than the simple interest received in this 3 years duration?

The sum of the ages of a mother and a daughter is 52 years. Also, 6 years ago, the mother’s age was 9 times of the age of her daughter. The ages of the mother and the daughter after 5 years respectively are?

Correct

Answer :4. 47 years, 15 years
Solution:
M+D =52
M-6 = 9(D-6)
M= 42, D=10
After 5 years; M=47, D=15

Incorrect

Answer :4. 47 years, 15 years
Solution:
M+D =52
M-6 = 9(D-6)
M= 42, D=10
After 5 years; M=47, D=15

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

In Ryan International school, there are 800 students. 65% of the students are boys, 30% of whom play hockey and the girls don’t play hockey, 65% of girls play badminton. There are only two games to be played. The number of students who don’t play any game is?

Correct

Answer :5. Cannot be determined

Incorrect

Answer :5. Cannot be determined

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Priya, Swati and Meena are three sisters Priya and Swati are twins. The sum of the ages of Priya and Swati is same as that of Meena alone. Three years earlier the ratio of age of Priya and Meena was 3:7.What will be the age of Swati 4 years hence?

Correct

Answer :2. 16 years
Solution:
Priya =Swati =x
Meena = 2x
x-3/2x-3 = 3/7
x =12
x+4 =16

Incorrect

Answer :2. 16 years
Solution:
Priya =Swati =x
Meena = 2x
x-3/2x-3 = 3/7
x =12
x+4 =16

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A car mechanic purchased five old cars for Rs. 2 lakh. He spent total 1 lakh in the maintenance and repairing of these five cars. What is the average sale price of the rest four cars to get 20% total profit if he has already sold one of the five cars at Rs. 1.2 lakh?

The difference between downstream and upstream speed is 3kmph and the total time taken during upstream and downstream is 3 hours. What is the downstream speed, if the downstream and upstream distance are 6 km each?

Correct

Answer :5. 6 Kmph
Solution:
R =1.5 kmph
3 = 6/s-1.5 + 6/s+1.5
s = 4.5 kmph
D = 4.5+1.5 =6 Kmph

Incorrect

Answer :5. 6 Kmph
Solution:
R =1.5 kmph
3 = 6/s-1.5 + 6/s+1.5
s = 4.5 kmph
D = 4.5+1.5 =6 Kmph

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

In reaching a mountain Suraj took half as long again to climb the second third as he did to climb the first third and a quarter as long again for the last third as for the second third. He took altogether 2 hr 55 minutes. Find the time he spent on the first third of the journey?

Correct

Answer :2. 40 min
Solution:
First 1/3 rd = x min
Second 1/3 rd = x+x/2 = 3x/2
Third 1/3 rd = 3x/2+3x/8 =15x/8
Total = x+3x/2+15x/8 = 175 min
x =40 min

Incorrect

Answer :2. 40 min
Solution:
First 1/3 rd = x min
Second 1/3 rd = x+x/2 = 3x/2
Third 1/3 rd = 3x/2+3x/8 =15x/8
Total = x+3x/2+15x/8 = 175 min
x =40 min

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