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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Ramu and Raju started the work A and completed 1/4th of the work in 2 days. Now Ravi joined to the work and they completed the remaining work. If the ratio of number of days in which Ramu and Ravi can complete the work A alone is 5:2 then in how many days does Raju alone can complete the work A?

Correct

Answer :4. 40/3 days
Solution:
2/Ramu + 2/Raju = 1/4
5/ Ramu + 4 / Ravi = 3/4
Ramu : Ravi = 5:2
5/5x + 4/2x = 3/4
x =4 Ramu = 20 days
2/20 + 2/ Raju = 1/4
Raju = 40/3 days

Incorrect

Answer :4. 40/3 days
Solution:
2/Ramu + 2/Raju = 1/4
5/ Ramu + 4 / Ravi = 3/4
Ramu : Ravi = 5:2
5/5x + 4/2x = 3/4
x =4 Ramu = 20 days
2/20 + 2/ Raju = 1/4
Raju = 40/3 days

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Ramu, Raju and Ravi worked on Work B such that on first day Ramu and Raju worked, second day Raju and Ravi worked, and on third day Ravi and Ramu worked from then they repeated the cycle by this the work B is completed in a total of 15 days. If Ramu and Raju can complete the Work B alone in 20 and 30 days respectively, then in how many days Ravi alone can complete the work?

Correct

Answer :1.60 days
Solution:
For every 3 days each person works 2 days
for 15 days each worked for 10 days
10/ Ramu + 10/ Raju + 10/ Ravi =1
10/20 + 10/30 + 10/Ravi =1
Ravi = 60 days

Incorrect

Answer :1.60 days
Solution:
For every 3 days each person works 2 days
for 15 days each worked for 10 days
10/ Ramu + 10/ Raju + 10/ Ravi =1
10/20 + 10/30 + 10/Ravi =1
Ravi = 60 days

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

If Raju and Ravi can complete the whole Work C in 6 days, and if Ramu is 20% more efficient than Ravi and 40% less efficient that of Raju. Then how many days does Ravi worked in Work C if Ramu and Raju worked as per table to complete the whole work C?

Correct

Answer :1.6 days
Solution:
Then Ramu: Raju: Ravi in days = 5:3:6
1/Raju + 1/Ravi = 1/6
1/3x + 1/6x = 1/6
x =3
Days = 15, 9 and 18 days
5/15 + 3/9 + x/18 =1
x =6 days

Incorrect

Answer :1.6 days
Solution:
Then Ramu: Raju: Ravi in days = 5:3:6
1/Raju + 1/Ravi = 1/6
1/3x + 1/6x = 1/6
x =3
Days = 15, 9 and 18 days
5/15 + 3/9 + x/18 =1
x =6 days

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

If Ramu and Raju worked for same number of days in Work D and If the ratio of number of days in which Ramu, Raju, Ravi can complete the work D alone is 1:2:3. Then how many does Ramu worked?

Correct

Answer :5.Cannot be determined

Incorrect

Answer :5.Cannot be determined

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

If Ramu, Raju, and Ravi can complete work E alone in 12, 20, and 14 days respectively. If they work in days as per table to complete the whole work C. Then how many does Raju work?

The average speed of a train in the onward journey is 25% more than that in the return journey. The train halts for 2 h on reaching the destination. The total time taken to complete to and fro journey is 31 h, covering a total distance of 3480 km. Find the speed of the train in the onward journey?

Correct

Answer :3.135 km/hr
Solution:
Let on ward journey speed = 5x
return journey speed = 4x
train halts for 2 hrs then train travelled =31-2 =29 hrs
29 = 1740/5x + 1740/4x
x = 27
speed = 27*5 =135

Incorrect

Answer :3.135 km/hr
Solution:
Let on ward journey speed = 5x
return journey speed = 4x
train halts for 2 hrs then train travelled =31-2 =29 hrs
29 = 1740/5x + 1740/4x
x = 27
speed = 27*5 =135

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Shyam completes a work in 8 days whereas Dheeraj completes the work in 12 days. Rajesh work 1.5 times as fast as Shyam. How many days it will take for the three together to complete the work?

Correct

Answer :2.48/19 days
Solution:
Rajesh takes 8*2/3 = 16/3 days
1/8 +1/12+3/16 = 19/48

Incorrect

Answer :2.48/19 days
Solution:
Rajesh takes 8*2/3 = 16/3 days
1/8 +1/12+3/16 = 19/48

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

The current of a stream runs at 1 km/hr. A motor boat goes 70 km upstream and back again to the starting point in 24 hours. The speed of motor boat in still water is?

A mixture of 150 liters of Petrol and Diesel contains 20% Diesel. If some quantity of Diesel is added then Diesel becomes 33 1/3 % of the new mixture. Then what is the total quantity of new mixture?

Correct

Answer :1.180 liters
Solution:
P+D = 150
D =20% = 30 P = 120
(30+D)/ (150+D) = 1/3
D =30total = 150+30 =180

Incorrect

Answer :1.180 liters
Solution:
P+D = 150
D =20% = 30 P = 120
(30+D)/ (150+D) = 1/3
D =30total = 150+30 =180

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

I.99X²-49√7 X +42 = 0
II.99Y² +13√7 Y -14 =0

Correct

Answer :1. X >Y
Solution:
X = 2√7/9 , 3√7/11
Y = -2√7/9, √7/11

Incorrect

Answer :1. X >Y
Solution:
X = 2√7/9 , 3√7/11
Y = -2√7/9, √7/11

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