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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Q (1-5) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .

Pie Charts shows Model wise distribution of total sales of Hyundai in different years

The given table represents the Total sales value( in crores) in different years.

How many ‘Hyundai Cars’ were sold in the year 2014?

Correct

Answer:3. 128
Solution:
Since total numbers of cars sold, different models sold and selling price all are integers. Then
number of Model verna cars = (x cr*5/100)/5 Lakh = must be integer
number of Model Creta cars= (x cr*10/100)/6 Lakh = must be integer
the only possible value for total sales in that range which is divisible by both 5 and 6 will be 3 cr.
total number of cars sold = (3 cr*10/100)/1 Lakh + (3 cr*40/100)/2 Lakh + (3 cr*15/100)/3 Lakh + (3 cr*20/100)/4 Lakh + (3 cr*5/100)/5 Lakh + (3 cr*10/100)/6 Lakh
= 128 cars

Incorrect

Answer:3. 128
Solution:
Since total numbers of cars sold, different models sold and selling price all are integers. Then
number of Model verna cars = (x cr*5/100)/5 Lakh = must be integer
number of Model Creta cars= (x cr*10/100)/6 Lakh = must be integer
the only possible value for total sales in that range which is divisible by both 5 and 6 will be 3 cr.
total number of cars sold = (3 cr*10/100)/1 Lakh + (3 cr*40/100)/2 Lakh + (3 cr*15/100)/3 Lakh + (3 cr*20/100)/4 Lakh + (3 cr*5/100)/5 Lakh + (3 cr*10/100)/6 Lakh
= 128 cars

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Q (1-5) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .

Pie Charts shows Model wise distribution of total sales of Hyundai in different years

The given table represents the Total sales value( in crores) in different years.

What is the total sales value (in crore) in the year 2015?

Correct

Answer:4. Either 2.4 cr or 3.2 cr
Solution:
number of cars sold must be integers
then Eon Model car x’cr *25/100/ 4 lakh = must be integer
Verna car x cr*12.5/100/5 Lakh = must be integer
possible values will be 2.4 cr or 3.2 cr

Incorrect

Answer:4. Either 2.4 cr or 3.2 cr
Solution:
number of cars sold must be integers
then Eon Model car x’cr *25/100/ 4 lakh = must be integer
Verna car x cr*12.5/100/5 Lakh = must be integer
possible values will be 2.4 cr or 3.2 cr

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Q (1-5) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .

Pie Charts shows Model wise distribution of total sales of Hyundai in different years

The given table represents the Total sales value( in crores) in different years.

The total sales growth of the company from 2014 to 2016 is?

Correct

Answer:3. 100%
Solution:
In 2016:
then xcent Model car x’cr *10/100/ 5 lakh = must be integer
Verna car x cr*10/100/6 Lakh = must be integer
Creta car x cr*20/100/8 Lakh = must be integer
x cr must be divided by 5,6,4
then it must be 6 cr
% increase = (600-300)/300 *100 = 100%

Incorrect

Answer:3. 100%
Solution:
In 2016:
then xcent Model car x’cr *10/100/ 5 lakh = must be integer
Verna car x cr*10/100/6 Lakh = must be integer
Creta car x cr*20/100/8 Lakh = must be integer
x cr must be divided by 5,6,4
then it must be 6 cr
% increase = (600-300)/300 *100 = 100%

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Q (1-5) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .

Pie Charts shows Model wise distribution of total sales of Hyundai in different years

The given table represents the Total sales value( in crores) in different years.

What is the number of Creta Model cars sold by the company over the period 2014-16 if total sale value of Hyundai cars in the year 2015 is 2.4 cr?

Correct

Answer:5. 29
Solution:
In 2014: 3 cr* 10/100 / 6 Lakh = 5
In 2015: 2.4 cr*30/100 / 8 lakh = 9
In 2016: 6 cr* 20/100 / 8 lakh = 15
total = 29

Incorrect

Answer:5. 29
Solution:
In 2014: 3 cr* 10/100 / 6 Lakh = 5
In 2015: 2.4 cr*30/100 / 8 lakh = 9
In 2016: 6 cr* 20/100 / 8 lakh = 15
total = 29

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Q (1-5) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .

Pie Charts shows Model wise distribution of total sales of Hyundai in different years

The given table represents the Total sales value( in crores) in different years.

Which Model cars were sold in maximum in the year 2015?

Correct

Answer:1. i20
Solution:
In 2015 total sale value is 2.4 cr or 3.2 cr but maximum can be known by Percentage share/ Unit price value
For i20 model it is = 17.5/2 = 8.75 (maximum) than other values

Incorrect

Answer:1. i20
Solution:
In 2015 total sale value is 2.4 cr or 3.2 cr but maximum can be known by Percentage share/ Unit price value
For i20 model it is = 17.5/2 = 8.75 (maximum) than other values

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

There are 63 cards (numbered 01, 02, 03, ….63). Two cards are picked at random. Quantity I: Probability that both cards show 2 digit numbers which increase by 36 when its digits are reversed. Quantity II: Probability that both cards show a number divisible by 7 but not 14.

Correct

Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
04,15,26,37,48,59 possible cases
(denominator will be same)
probability = 6*5 (numerator)
Quantity II:
07,21,35,42,49,63
probability =6*5

Incorrect

Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
04,15,26,37,48,59 possible cases
(denominator will be same)
probability = 6*5 (numerator)
Quantity II:
07,21,35,42,49,63
probability =6*5

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

There are 7 couples who sits in 14 vacant seats Quantity I: Number of ways in which men and women sit at alternate positions Quantity II: Number of ways in which all men sit together and all women sit together.

Correct

Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
If Man sits at first seat then 7!*7!
If Woman sits at first seat then 7!*7!
total = 2*7!*7!
Quantity II:
Ways for all men together =7!
Ways for all women together = 7!
Men and women as group = 2!
total = 7!*7!*2!

Incorrect

Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
If Man sits at first seat then 7!*7!
If Woman sits at first seat then 7!*7!
total = 2*7!*7!
Quantity II:
Ways for all men together =7!
Ways for all women together = 7!
Men and women as group = 2!
total = 7!*7!*2!

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Six married couples are seating in a circular table of 12 vacant seats Quantity I: If men and women sit alternately Quantity II: If Spouses sit opposite each other

Correct

Answer:Quantity I > Quantity II

Incorrect

Answer:Quantity I > Quantity II

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Four married couples are seating in a circular table of 8 vacant seats Quantity I: If each husband must sit besides his wife Quantity II: If Men and Women sit alternate

Correct

Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
4 couple groups can be arranged in (4-1)! ways
two persons in each group can be arranged in 2! ways similarly 4 groups = (2!)^4
total ways = (4-1)!* (2!)^4 = 96
Quantity II:
3!*4! = 144

Incorrect

Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
4 couple groups can be arranged in (4-1)! ways
two persons in each group can be arranged in 2! ways similarly 4 groups = (2!)^4
total ways = (4-1)!* (2!)^4 = 96
Quantity II:
3!*4! = 144

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Three varieties of rice Rs. 38, Rs. 44 and Rs, 49 mixed to from 19 kg rice Quantity I: They are mixed in the ratio of 9:5:4 respectively Quantity II: They are mixed in the ratio of 8:6:5 respectively

Correct

Answer:2.Quantity I < Quantity II
Solution:
Quantity I:
(38*9+44*5+49*4) =758
Quantity II:
(38*8+44*6+49*5) = 813

Incorrect

Answer:2.Quantity I < Quantity II
Solution:
Quantity I:
(38*9+44*5+49*4) =758
Quantity II:
(38*8+44*6+49*5) = 813

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