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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .
Pie Charts shows Model wise distribution of total sales of Hyundai in different years
The given table represents the Total sales value( in crores) in different years.
How many ‘Hyundai Cars’ were sold in the year 2014?Correct
Answer:3. 128
Solution:
Since total numbers of cars sold, different models sold and selling price all are integers. Then
number of Model verna cars = (x cr*5/100)/5 Lakh = must be integer
number of Model Creta cars= (x cr*10/100)/6 Lakh = must be integer
the only possible value for total sales in that range which is divisible by both 5 and 6 will be 3 cr.
total number of cars sold = (3 cr*10/100)/1 Lakh + (3 cr*40/100)/2 Lakh + (3 cr*15/100)/3 Lakh + (3 cr*20/100)/4 Lakh + (3 cr*5/100)/5 Lakh + (3 cr*10/100)/6 Lakh
= 128 carsIncorrect
Answer:3. 128
Solution:
Since total numbers of cars sold, different models sold and selling price all are integers. Then
number of Model verna cars = (x cr*5/100)/5 Lakh = must be integer
number of Model Creta cars= (x cr*10/100)/6 Lakh = must be integer
the only possible value for total sales in that range which is divisible by both 5 and 6 will be 3 cr.
total number of cars sold = (3 cr*10/100)/1 Lakh + (3 cr*40/100)/2 Lakh + (3 cr*15/100)/3 Lakh + (3 cr*20/100)/4 Lakh + (3 cr*5/100)/5 Lakh + (3 cr*10/100)/6 Lakh
= 128 cars 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .
Pie Charts shows Model wise distribution of total sales of Hyundai in different years
The given table represents the Total sales value( in crores) in different years.
What is the total sales value (in crore) in the year 2015?Correct
Answer:4. Either 2.4 cr or 3.2 cr
Solution:
number of cars sold must be integers
then Eon Model car x’cr *25/100/ 4 lakh = must be integer
Verna car x cr*12.5/100/5 Lakh = must be integer
possible values will be 2.4 cr or 3.2 crIncorrect
Answer:4. Either 2.4 cr or 3.2 cr
Solution:
number of cars sold must be integers
then Eon Model car x’cr *25/100/ 4 lakh = must be integer
Verna car x cr*12.5/100/5 Lakh = must be integer
possible values will be 2.4 cr or 3.2 cr 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .
Pie Charts shows Model wise distribution of total sales of Hyundai in different years
The given table represents the Total sales value( in crores) in different years.
The total sales growth of the company from 2014 to 2016 is?Correct
Answer:3. 100%
Solution:
In 2016:
then xcent Model car x’cr *10/100/ 5 lakh = must be integer
Verna car x cr*10/100/6 Lakh = must be integer
Creta car x cr*20/100/8 Lakh = must be integer
x cr must be divided by 5,6,4
then it must be 6 cr
% increase = (600300)/300 *100 = 100%Incorrect
Answer:3. 100%
Solution:
In 2016:
then xcent Model car x’cr *10/100/ 5 lakh = must be integer
Verna car x cr*10/100/6 Lakh = must be integer
Creta car x cr*20/100/8 Lakh = must be integer
x cr must be divided by 5,6,4
then it must be 6 cr
% increase = (600300)/300 *100 = 100% 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .
Pie Charts shows Model wise distribution of total sales of Hyundai in different years
The given table represents the Total sales value( in crores) in different years.
What is the number of Creta Model cars sold by the company over the period 201416 if total sale value of Hyundai cars in the year 2015 is 2.4 cr?Correct
Answer:5. 29
Solution:
In 2014: 3 cr* 10/100 / 6 Lakh = 5
In 2015: 2.4 cr*30/100 / 8 lakh = 9
In 2016: 6 cr* 20/100 / 8 lakh = 15
total = 29Incorrect
Answer:5. 29
Solution:
In 2014: 3 cr* 10/100 / 6 Lakh = 5
In 2015: 2.4 cr*30/100 / 8 lakh = 9
In 2016: 6 cr* 20/100 / 8 lakh = 15
total = 29 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeQ (15) Study the given tables and pie charts to answer the following questions
Table shows different cars of Hyundai company and their prices (in Laks) in different years .
Pie Charts shows Model wise distribution of total sales of Hyundai in different years
The given table represents the Total sales value( in crores) in different years.
Which Model cars were sold in maximum in the year 2015?Correct
Answer:1. i20
Solution:
In 2015 total sale value is 2.4 cr or 3.2 cr but maximum can be known by Percentage share/ Unit price value
For i20 model it is = 17.5/2 = 8.75 (maximum) than other valuesIncorrect
Answer:1. i20
Solution:
In 2015 total sale value is 2.4 cr or 3.2 cr but maximum can be known by Percentage share/ Unit price value
For i20 model it is = 17.5/2 = 8.75 (maximum) than other values 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThere are 63 cards (numbered 01, 02, 03, ….63). Two cards are picked at random.
Quantity I: Probability that both cards show 2 digit numbers which increase by 36 when its digits are reversed.
Quantity II: Probability that both cards show a number divisible by 7 but not 14.Correct
Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
04,15,26,37,48,59 possible cases
(denominator will be same)
probability = 6*5 (numerator)
Quantity II:
07,21,35,42,49,63
probability =6*5Incorrect
Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
04,15,26,37,48,59 possible cases
(denominator will be same)
probability = 6*5 (numerator)
Quantity II:
07,21,35,42,49,63
probability =6*5 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThere are 7 couples who sits in 14 vacant seats
Quantity I: Number of ways in which men and women sit at alternate positions
Quantity II: Number of ways in which all men sit together and all women sit together.Correct
Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
If Man sits at first seat then 7!*7!
If Woman sits at first seat then 7!*7!
total = 2*7!*7!
Quantity II:
Ways for all men together =7!
Ways for all women together = 7!
Men and women as group = 2!
total = 7!*7!*2!Incorrect
Answer:5. Quantity I = Quantity II or relationship cannot be determined
Solution:
Quantity I:
If Man sits at first seat then 7!*7!
If Woman sits at first seat then 7!*7!
total = 2*7!*7!
Quantity II:
Ways for all men together =7!
Ways for all women together = 7!
Men and women as group = 2!
total = 7!*7!*2! 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeSix married couples are seating in a circular table of 12 vacant seats
Quantity I: If men and women sit alternately
Quantity II: If Spouses sit opposite each otherCorrect
Answer:Quantity I > Quantity II
Incorrect
Answer:Quantity I > Quantity II

Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeFour married couples are seating in a circular table of 8 vacant seats
Quantity I: If each husband must sit besides his wife
Quantity II: If Men and Women sit alternateCorrect
Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
4 couple groups can be arranged in (41)! ways
two persons in each group can be arranged in 2! ways similarly 4 groups = (2!)^4
total ways = (41)!* (2!)^4 = 96
Quantity II:
3!*4! = 144Incorrect
Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
4 couple groups can be arranged in (41)! ways
two persons in each group can be arranged in 2! ways similarly 4 groups = (2!)^4
total ways = (41)!* (2!)^4 = 96
Quantity II:
3!*4! = 144 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThree varieties of rice Rs. 38, Rs. 44 and Rs, 49 mixed to from 19 kg rice
Quantity I: They are mixed in the ratio of 9:5:4 respectively
Quantity II: They are mixed in the ratio of 8:6:5 respectivelyCorrect
Answer:2.Quantity I < Quantity II
Solution:
Quantity I:
(38*9+44*5+49*4) =758
Quantity II:
(38*8+44*6+49*5) = 813Incorrect
Answer:2.Quantity I < Quantity II
Solution:
Quantity I:
(38*9+44*5+49*4) =758
Quantity II:
(38*8+44*6+49*5) = 813
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