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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeIn a mixture of milk and water the proportion of water by weight was 75%. If in the 120 gms mixture 30 gms water was added, what would be the percentage of water in the new mixture?
Correct
Answer :5. 80%
Solution:
In 120 gms mixture water = 90 gms milk = 30 gms
now 30gms water added = water = 120gm s total = 150 gms
% = 120/150 = 80%Incorrect
Answer :5. 80%
Solution:
In 120 gms mixture water = 90 gms milk = 30 gms
now 30gms water added = water = 120gm s total = 150 gms
% = 120/150 = 80% -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeB takes 6 hr more than A to fill a tank. If both tapes fill together it takes 8 hr fewer than B would take to fill the tank. How long it takes if A and B together fill the tank twice as big as 1st one.
Correct
Answer :2. 8 hours
Solution:
1/x + 1/x+6 = 1/x-2
x =6
they fill tank in 4 hours
double tank in 8 hoursIncorrect
Answer :2. 8 hours
Solution:
1/x + 1/x+6 = 1/x-2
x =6
they fill tank in 4 hours
double tank in 8 hours -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA rectangular tank 50 cm long and 40 cm wide contains water to a depth of 10 cm. a metal cube of side 20 cms placed in the tank so that one face of cube rests at the bottom of the tank. Find how many litres of water must be poured into the tank so as to just cover the cube
Correct
Answer :2. 12 liters
Solution:
50*40*10 – 20^3 = 12,000cm ^3 = 12 litersIncorrect
Answer :2. 12 liters
Solution:
50*40*10 – 20^3 = 12,000cm ^3 = 12 liters -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA man sells 3 different articles, first at profit 20%, second at 25% loss and third at 10% loss. During the whole transaction he bears the loss of Rs.120, find the cost price of first article if their SP is same?
Correct
Answer :3. Rs. 360
Solution:
x =A*120/100 = 1.2A
x=B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 120
0.4A+ 0.4A/3 -0.2A =120
A =360Incorrect
Answer :3. Rs. 360
Solution:
x =A*120/100 = 1.2A
x=B*75/100 = 0.75B
x = C*90/100 = 0.9C
Loss = (A+B+C) – (1.2A+0.75B+0.9C) = 120
0.4A+ 0.4A/3 -0.2A =120
A =360 -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA and B are partners in a business. They invest in the ratio 6:7, at the end of 9 months B withdraws. If they receive profits at the end of year in the ratio of 2:3, find how long A’s investment was used?
Correct
Answer :3. 7 months
Solution:
6*x : 9*7 = 2:3
x =7 monthsIncorrect
Answer :3. 7 months
Solution:
6*x : 9*7 = 2:3
x =7 months -
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA person X starts from Pune and another person Y starts from Mumbai to meet each other. Speed of X is 37 km/h, while Y is 41 km/h. If the distance between Pune and Mumbai be 234 km and both X and Y start their journey at the same time, when they will meet?
Correct
Answer :5. None
Solution:
234 = (37+41)*t
t =3Incorrect
Answer :5. None
Solution:
234 = (37+41)*t
t =3 -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA boat takes 14 hours to go from P to R, through a midpoint Q, but it takes 16 hours to go from P to Q and then return from Q to P. How long it would take to go from R to P?
Correct
Answer :3. 18 hr
Solution:
Let distance from P to R be ‘2x’
14 = 2x/S+R
16 = x/S+R + x/S-R
16 = 7 + x/S-R
x/S-R = 9
2x/S-R = 18Incorrect
Answer :3. 18 hr
Solution:
Let distance from P to R be ‘2x’
14 = 2x/S+R
16 = x/S+R + x/S-R
16 = 7 + x/S-R
x/S-R = 9
2x/S-R = 18 -
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeTwo trains Vivek express and Kanchanjunga express simultaneously started on two parallel tracks from Howrah to Guwahati, which are 688 km a part. The ratio of the speed of Vivek express and Kanchanjunga express is 7:9. After how long (in km) travelling. Kanchanjunga express exchanges the speed with Vivek express so that both the trains reach at their destination simultaneously?
Correct
Answer :4. 387 Km
Solution:
For time t1 distance covered by Vivek and Kanchanjunga express are 7xt1 and 9xt1 respectively
After they exchanged speeds suppose they take t2 time to reach destination then the distances covered by Vivek and Kanchanjunga express are 7xt2 and 9xt2 respectively
Then total distance covered by trains
7xt1+9xt2 = 688
9xt1+7xt2 =688
Then t1 = t2 let it be t
16xt = 688
xt = 43
After travelling 9xt = 387 km Kanchanjunga Express exchanges speed with Vivek ExpressIncorrect
Answer :4. 387 Km
Solution:
For time t1 distance covered by Vivek and Kanchanjunga express are 7xt1 and 9xt1 respectively
After they exchanged speeds suppose they take t2 time to reach destination then the distances covered by Vivek and Kanchanjunga express are 7xt2 and 9xt2 respectively
Then total distance covered by trains
7xt1+9xt2 = 688
9xt1+7xt2 =688
Then t1 = t2 let it be t
16xt = 688
xt = 43
After travelling 9xt = 387 km Kanchanjunga Express exchanges speed with Vivek Express -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeSneha is a very expert in bargaining. Once she went to a nearby shop. When Sneha asked the price of watch the shopkeeper told her the price by increasing 18% of the original cost. But Sneha insisted to decrease the price by 18% so the shopkeeper sold it by decreasing the price by 18% what is the loss or profit of shopkeeper and by how much percent?
Correct
Answer :3. 3.24%
Solution:
Loss = x^2/100 = 18^2/100 = 3.24%
10. 450 man-days of work can be
Actual price be Rs. 100
Increased price = 118
Sneha price = 118*82/100 = 96.76 Loss = 100-96.76 = 3.24Incorrect
Answer :3. 3.24%
Solution:
Loss = x^2/100 = 18^2/100 = 3.24%
10. 450 man-days of work can be
Actual price be Rs. 100
Increased price = 118
Sneha price = 118*82/100 = 96.76 Loss = 100-96.76 = 3.24 -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative Aptitude450 man-days of work can be completed by a certain number of men in some days. If the number of men is increased by 27 men, then the number of days required to complete the same work is decreased by 15. Then number of men initially present?
Correct
Answer : 1. 18
Solution:
M*D =450
(M+27)*(D-15) =450
M =18 D =25Incorrect
Answer : 1. 18
Solution:
M*D =450
(M+27)*(D-15) =450
M =18 D =25
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