Welcome to Online Quantitative Aptitude Test in AffairsCloud.com. We are starting Cumulus Course for IBPS Clerk 2017 Exam and we are creating sample questions in Aptitude section, this type of Question will be asked in IBPS Clerk Mains !!!

Pipe A basically used as inlet pipe and pipe B is used as outlet pipe. Pipes A and B both are opened simultaneously, all the time. When pipe A fills the tank and B empty the tank, it will take thrice the time than when both the pipe fill the tank. When pipe B is used for filling the tank, its efficiency remains constant. What is the ratio of efficiency of pipe A and pipe B respectively?

Three typists A, B and C working together 8 hours per day can type 1800 pages in 20 days. In a day B types as many pages more than A as C types as many pages more than B. The number of pages typed by A in 4 hours equal to the number of pages typed by C in 1 hour. How many pages C types in each hour?

Correct

Answer :4. 6 pages
Solution:
A+B+C = 1800/(20*8)= 90/8 pages/hr
given
B-A = C-B
2B = A+C
and also given A= C/4
then B =5C/8
15*C/8 =90/8
C =6

Incorrect

Answer :4. 6 pages
Solution:
A+B+C = 1800/(20*8)= 90/8 pages/hr
given
B-A = C-B
2B = A+C
and also given A= C/4
then B =5C/8
15*C/8 =90/8
C =6

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The different between downstream speed and upstream speed is 2 kmph and the total time taken during upstream and downstream is 4 hours. What is the upstream speed, if the downstream and upstream distances are 3 km each?

Correct

Answer :1.1 kmph
Solution:
Difference = 2
S+R-(S-R) = 2
R =1
4 = 3/s-1 + 3/s+1
s =2
Up stream speed = 2-1 =1 kmph

Incorrect

Answer :1.1 kmph
Solution:
Difference = 2
S+R-(S-R) = 2
R =1
4 = 3/s-1 + 3/s+1
s =2
Up stream speed = 2-1 =1 kmph

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

A train met with an accident 120 km from station Delhi. It completed the remaining journey at 5/6 of its previous speed and reached 2 hour late at station Jaipur. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?

Correct

Answer :3. 60 Kmph
Solution:
t =d/s
t+2 = 120/s + 6*(d-120)/5s
t+1= 420/s + 6*(d-120)/5s
solving
s =300/5 =60

Incorrect

Answer :3. 60 Kmph
Solution:
t =d/s
t+2 = 120/s + 6*(d-120)/5s
t+1= 420/s + 6*(d-120)/5s
solving
s =300/5 =60

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Three containers have their volumes in ratio 3:4:5.They are full of milk & water. The mixture contains milk & water in ratio (4:1), (3:1) & (5:1). The contents of all these 3 containers are poured into 4th container. The ratio of milk & water in 4th container is?

The speeds of Ram and Shyam are 30 km/h and 40 km/h. Initially Shyam is at a place L and Ram is at a place M. The distance between L and M is 720 km. Ram started his journey 3 hours earlier than Shyam to meet each other. If they meet each other at a place P somewhere between L and M, then the distance between P and M is?

Correct

Answer:3. 360 Km
Solution:
720 = 30(t+3)+40t
t =9
distance = 30*12= 360

Incorrect

Answer:3. 360 Km
Solution:
720 = 30(t+3)+40t
t =9
distance = 30*12= 360

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Quantity I: What is the distance, if a man covers that distance in total 11 hours, such that first half at 36 km/hr and second half at 30 km/hr Quantity II: What is the distance, if a man covers three equal parts in 26 hours. He covers first part at 10 km/hr, 2nd part at 15 km/hr, and 3rd part at 20 km/hr

Correct

Answer:5. Quantity I = Quantity
Quantity I:
11 =x/2*36 + x/2*30
x =360
Quantity II:
26 = x/3*10 + x/3*15 + x/3*20
x =360

Incorrect

Answer:5. Quantity I = Quantity
Quantity I:
11 =x/2*36 + x/2*30
x =360
Quantity II:
26 = x/3*10 + x/3*15 + x/3*20
x =360

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Quantity I: Surface area of Cuboid having length 20cm, breadth 15cm, height 10 cm Quantity II: Surface of Cube having side of 15 cm

Correct

Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
2(20*15+15*10+10*20) = 1300
Quantity II:
6*15^2 = 1350

Incorrect

Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
2(20*15+15*10+10*20) = 1300
Quantity II:
6*15^2 = 1350

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