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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude2, 2, 2, ?, 92, 1155
Correct
Answer :2. 12
Solution:
2*0.5*1+1 =2
2*1*22 =2
2*1.5*3 +3 =12
12*2*44 =92
92*2.5*5+5 = 1155Incorrect
Answer :2. 12
Solution:
2*0.5*1+1 =2
2*1*22 =2
2*1.5*3 +3 =12
12*2*44 =92
92*2.5*5+5 = 1155 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude2, 1, 2, 9, 72,?
Correct
Answer :5. None
Solution:
2*0.5*1 =1
1*1*2 =2
2*1.5*3 =9
9*2*4 =72
72*2.5*5 =900Incorrect
Answer :5. None
Solution:
2*0.5*1 =1
1*1*2 =2
2*1.5*3 =9
9*2*4 =72
72*2.5*5 =900 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudePipe A basically used as inlet pipe and pipe B is used as outlet pipe. Pipes A and B both are opened simultaneously, all the time. When pipe A fills the tank and B empty the tank, it will take thrice the time than when both the pipe fill the tank. When pipe B is used for filling the tank, its efficiency remains constant. What is the ratio of efficiency of pipe A and pipe B respectively?
Correct
Answer :1.2:1
Solution:
3(1/a1/b) = (1/a+1/b)
a:b =2:1Incorrect
Answer :1.2:1
Solution:
3(1/a1/b) = (1/a+1/b)
a:b =2:1 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThree typists A, B and C working together 8 hours per day can type 1800 pages in 20 days. In a day B types as many pages more than A as C types as many pages more than B. The number of pages typed by A in 4 hours equal to the number of pages typed by C in 1 hour. How many pages C types in each hour?
Correct
Answer :4. 6 pages
Solution:
A+B+C = 1800/(20*8)= 90/8 pages/hr
given
BA = CB
2B = A+C
and also given A= C/4
then B =5C/8
15*C/8 =90/8
C =6Incorrect
Answer :4. 6 pages
Solution:
A+B+C = 1800/(20*8)= 90/8 pages/hr
given
BA = CB
2B = A+C
and also given A= C/4
then B =5C/8
15*C/8 =90/8
C =6 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThe different between downstream speed and upstream speed is 2 kmph and the total time taken during upstream and downstream is 4 hours. What is the upstream speed, if the downstream and upstream distances are 3 km each?
Correct
Answer :1.1 kmph
Solution:
Difference = 2
S+R(SR) = 2
R =1
4 = 3/s1 + 3/s+1
s =2
Up stream speed = 21 =1 kmphIncorrect
Answer :1.1 kmph
Solution:
Difference = 2
S+R(SR) = 2
R =1
4 = 3/s1 + 3/s+1
s =2
Up stream speed = 21 =1 kmph 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA train met with an accident 120 km from station Delhi. It completed the remaining journey at 5/6 of its previous speed and reached 2 hour late at station Jaipur. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?
Correct
Answer :3. 60 Kmph
Solution:
t =d/s
t+2 = 120/s + 6*(d120)/5s
t+1= 420/s + 6*(d120)/5s
solving
s =300/5 =60Incorrect
Answer :3. 60 Kmph
Solution:
t =d/s
t+2 = 120/s + 6*(d120)/5s
t+1= 420/s + 6*(d120)/5s
solving
s =300/5 =60 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThree containers have their volumes in ratio 3:4:5.They are full of milk & water. The mixture contains milk & water in ratio (4:1), (3:1) & (5:1). The contents of all these 3 containers are poured into 4th container. The ratio of milk & water in 4th container is?
Correct
Answer:1. 287:73
Solution:
Milk = 3*4/5 + 4*3/4 +5*5/6
Water = 3*1/5+ 4*1/4 + 5*1/6
ratio = (288+360+500)/(72+120+100)
1148/292 = 287/73Incorrect
Answer:1. 287:73
Solution:
Milk = 3*4/5 + 4*3/4 +5*5/6
Water = 3*1/5+ 4*1/4 + 5*1/6
ratio = (288+360+500)/(72+120+100)
1148/292 = 287/73 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThe speeds of Ram and Shyam are 30 km/h and 40 km/h. Initially Shyam is at a place L and Ram is at a place M. The distance between L and M is 720 km. Ram started his journey 3 hours earlier than Shyam to meet each other. If they meet each other at a place P somewhere between L and M, then the distance between P and M is?
Correct
Answer:3. 360 Km
Solution:
720 = 30(t+3)+40t
t =9
distance = 30*12= 360Incorrect
Answer:3. 360 Km
Solution:
720 = 30(t+3)+40t
t =9
distance = 30*12= 360 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeQuantity I: What is the distance, if a man covers that distance in total 11 hours, such that first half at 36 km/hr and second half at 30 km/hr
Quantity II: What is the distance, if a man covers three equal parts in 26 hours. He covers first part at 10 km/hr, 2nd part at 15 km/hr, and 3rd part at 20 km/hrCorrect
Answer:5. Quantity I = Quantity
Quantity I:
11 =x/2*36 + x/2*30
x =360
Quantity II:
26 = x/3*10 + x/3*15 + x/3*20
x =360Incorrect
Answer:5. Quantity I = Quantity
Quantity I:
11 =x/2*36 + x/2*30
x =360
Quantity II:
26 = x/3*10 + x/3*15 + x/3*20
x =360 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeQuantity I: Surface area of Cuboid having length 20cm, breadth 15cm, height 10 cm
Quantity II: Surface of Cube having side of 15 cmCorrect
Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
2(20*15+15*10+10*20) = 1300
Quantity II:
6*15^2 = 1350Incorrect
Answer:2. Quantity I < Quantity II
Solution:
Quantity I:
2(20*15+15*10+10*20) = 1300
Quantity II:
6*15^2 = 1350
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