Current Affairs PDF Sales

Aptitude Questions: Quadratic Equations Set 21

AffairsCloud YouTube Channel - Click Here

AffairsCloud APP Click Here

Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in Quadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link To solve Quadratic Equations with the help of Number Line

  1. 5x + 2y = 31
    3x + 7y = 36
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    A. X > Y
    Explanation:

    5x + 2y = 31 —-(1)
    3x + 7y = 36 —-(2)
    By solving eqn(1) and (2)
    x = 5 ; y = 3

  2. x2 – x – √3x + √3= 0
    y2 – 3y + 2 = 0
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    E. X = Y or relation cannot be established
    Explanation:

    x2 – x – √3x + √3= 0
    x (x-1) – √3(x -1) = 0
    (x-1) (x-√3) = 0
    x = 1, 1.732
    y2 – 3y + 2 = 0
    y2 – y – 2y + 2 = 0
    y = 1, 2
    Put on number line
    1, 1, 1.732, 2

  3. [48 / x4/7] – [12 / x4/7] = x10/7
    y³ + 783 = 999
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    D. X ≤ Y
    Explanation:

    (48 – 12) / x4/7 = x10/7
    36 = x(10/7 + 4/7)
    36 = x2
    x =  ± 6
    y3 + 783 = 999
    y3 = 999 – 783
    y3 = 216
    y = 6
    Put on number line
    -6, 6, 6

  4. 172 + 144 ÷ 18 = x
    262 – 18 * 21 = y
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    B. X < Y
    Explanation:

    172 + 144 ÷ 18 = x
    x = 297
    262 – 18 * 21 = y
    y = 676 – 378 = 29

  5. 5/7 – 5/21 = √x/42
    √y/4 + √y/16 = 250/√y
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    B. X < Y
    Explanation:

    5/7 – 5/21 = √x/42
    10/21 = √x/42
    √x = 20
    x = 400
    √y/4 + √y/16 = 250/√y
    5√y/16 = 250/√y
    y = 800

  6. 9/√x + 19/√x = √x
    y5 – [(28)11/2 /√y] = 0
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    E. X = Y or relation cannot be established
    Explanation:

    9/√x + 19/√x = √x
    x = 28
    y5 – [(28)11/2 /√y] = 0
    y11/2 = (28)11/2
    y = 28

  7. 12/√x – 23/√x = 5√x
    √y/12 – 5√y/12 = 1/√y
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    A. X > Y
    Explanation:

    12/√x – 23/√x = 5√x
    -11 = 5x
    x = -2.2
    √y/12 – 5√y/12 = 1/√y
    √y[1/12 – 5/12]= 1/√y
    y = -3

  8. 7x + 6y + 4z = 122
    4x + 5y + 3z = 88
    9x + 2y + z = 78
    A. X < Y = Z
    B. X ≤ Y < Z
    C. X < Y > Z
    D. X = Y > Z
    E. X = Y = Z or relation cannot be established
    A. X < Y = Z
    Explanation:

    7x + 6y + 4z = 122 —(1)
    4x + 5y + 3z = 88 —(2)
    9x + 2y + z = 78 —(3)
    From (1) and (2) => 5x – 2y =4 —(a)
    From (2) and (3) => 23x + y = 146 —(b)
    From (a) and (b) => x = 6, y = 8. Put values in eqn (3) => z = 8

  9. (x+y)³ = 1331
    x – y + z = 0
    xy = 28
    A. X < Y = Z
    B. X ≤ Y < Z
    C. X < Y > Z
    D. X = Y > Z
    E. X = Y = Z or relation cannot be established
    E. X = Y or relation cannot be established
    Explanation:

    (x + y)³ = 1331
    x + y = 11 —(a)
    (x + y)2 = 121
    (a + b)2 – (a – b)2 = 4ab
    (x – y)2 + 4xy = 121
    x – y = 3 —(b)
    From eqn (a) and (b)
    x = 7; y = 4 Put values in eqn (2) => z = -3

  10. 7x + 6y = 110
    4x + 3y = 59
    x + z = 15
    A. X < Y = Z
    B. X ≤ Y < Z
    C. X < Y > Z
    D. X = Y > Z
    E. X = Y = Z or relation cannot be established
    C. X < Y > Z
    Explanation:

    7x + 6y = 110 —(1)
    4x + 3y = 59 —(2)
    x + z = 15 —(3)
    From eqn(1) and (2)
    x = 8; y = 9 Put values in eqn (3) => z = 7