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Aptitude Questions: Quadratic Equations Set 19

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Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions inQuadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link To solve Quadratic Equations with the help of Number Line

Bank PO Level Questions :-

  1. x2 – 1 = 0, y2 + 4y + 3 = 0
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    C. X ≥ Y
    Explanation:

    x2 = 1
    x = ± 1
    y2 + 4y + 3 = 0
    y2 + y + 3y + 3 = 0
    y = -1, -3
    Put on number line
    -3 -1 -1 1

  2. x2 – 10x + 24 = 0, y2 – 14y + 48 = 0
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    D. X ≤ Y
    Explanation:

    x2 – 10x + 24 = 0
    x2 – 6x – 4x + 24 = 0
    x = 4, 6
    y2 – 14y + 48 = 0
    y2 – 6y – 8y + 48 = 0
    y = 6, 8
    Put on number line
    4 6 6 8

  3. 2x2 – 13x + 20 = 0, 2y2 – 7y + 6 = 0
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    A. X > Y
    Explanation:

    2x2 – 13x + 20 = 0
    2x2 – 8x – 5x + 20 = 0
    x = 2.5, 4
    2y2 – 7y + 6 = 0
    2y2 – 3y – 4y + 6 = 0
    y = 1.5, 2
    Put on number line
    1.5 2 2.5 4

  4. (15/√x) + (9/√x) = 11√x, (√y/4) + (5√y/12)= (1/√y)
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    A. X > Y
    Explanation:

    (15/√x) + (9/√x) = 11√x
    24/√x = 11√x
    x = 24/11 = 2.18
    (√y/4) + (5√y/12)= (1/√y)
    (8√y/12) = (1/√y)
    y = 1.5

  5. x4 – 227 = 398, y2 + 321 = 346
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    E. X = Y or relation cannot be established
    Explanation:

    x4 – 227 = 398
    x4 = 625
    Take square root on both sides
    x2 = 25
    x = 5, -5
    y2 + 321 = 346
    y2 = 25
    y2 = 25
    y = ±5

  6. x2 + x – 20 = 0, y2 + y – 30 = 0
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    E. X = Y or relation cannot be established
    Explanation:

    x2 + x – 20 = 0
    x2 + 5x – 4x + 20 = 0
    x = -5, 4
    y2 + y – 30 = 0
    y2 +6y -5y – 30 = 0
    y = -6, 5
    Put on number line
    -6 -5 4 5

  7. x2 – 365 = 364, y – √324 = √81
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    D. X ≤ Y
    Explanation:

    x2 – 365 = 364
    x2 = 729
    x = ± 27
    y – √324 = √81
    y – 18 = 9
    y = 27
    Put on number line
    -27 27 27

  8. 9x – 15.45 = 54.55 + 4x, √(y+155) – 6 = 7
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    E. X = Y or relation cannot be established
    Explanation:

    9x – 15.45 = 54.55 + 4x
    9x – 4x = 54.55 + 15.45
    5x = 70 => x= 14
    √(y+155) – 6 = 7
    √(y+155) = 13
    Squaring on both sides
    y + 155 = 169
    y = 14

  9. x2 + 11x + 30 = 0, y2 + 7y + 12 = 0
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    B. X < Y
    Explanation:

    x2 + 11x + 30 = 0
    x2 + 6x + 5x + 30 = 0
    x = -6, -5
    y2 + 7y + 12 = 0
    y2 + 4y + 3y + 12 = 0
    y = -4, -3
    Put on number line
    -6 -5 -4 -3

  10. y2 – x2 = 32, y – x = 2
    A. X > Y
    B. X < Y
    C. X ≥ Y
    D. X ≤ Y
    E. X = Y or relation cannot be established
    B. X < Y
    Explanation:

    y2 – x2 = 32
    (y + x)(y – x) = 32
    From equation(2) y – x = 2
    (y + x)2 = 32
    y + x = 16 –(a)
    y – x = 2 —(b)
    2y = 18 => y = 9
    9 – x = 2
    x = 7