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Aptitude Questions: Data Interpretation Set 27

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Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample FromData Intrepretation that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams !!

I.Study the following information carefully to answer the given questions

Percentage of students enrolled in different activities in a School

Total no of students 4000

Pie chart

Percentage of no of boys involved in these activities out of total no of boys(2800)

Pie chart

  1. What is the approximate % of Girls in the School ?
    A.20%
    B.30%
    C.34%
    D.27%
    E.None of these
    Answer – B. 30%
    Solution:
    % = [4000 – 2800/4000]*100
    = 1200*100/4000 = 30%

  2. What is the ratio of the number of boys enrolled in singing to that of girls enrolled in Singing. If % of boys enrolled in Singing is 4% less than the no of boys enrolled in Craft ?
    A.7:18
    B.3:17
    C.14:11
    D.21:4
    E.None of these
    Answer –C. 14:11
    Solution:
    No of students enrolled in singing = 20*4000/100 = 800
    No of boys in singing = 16*2800/100 = 448
    No of girls in singing = 800 – 448 = 352
    448:352 = 56 : 44 = 14 : 11

  3. How many boys are enrolled in dancing and singing together, if the % of boys students enrolled in dancing is twice the % of total no of students enrolled in dancing?
    A.1400
    B.1278
    C.1370
    D.1460
    E.None of these
    Answer –A. 1400
    Solution:
    No of boys in dancing = 34*2800/100 = 952
    No of boys in singing = 448
    Total = 952 + 448 = 1400

  4. What is the difference between the total no students enrolled in swimming to the no of girls enrolled in swimming, if the no of students enrolled in swimming is 10% more than the no of students enrolled in drawing ?
    A.432
    B.378
    C.624
    D.336
    E.None of these
    Answer –D. 336
    Solution:
    No of students in swimming = 24% = 24*4000/100 = 960
    No of girls in swimming = 960 – [2800*12/100] = 960-336 = 624
    Diff = 960-624 = 336

  5. What is the total number of girls enrolled in drawing and craft together, If % of total no of students enrolled in Craft is twice the % of students enrolled in Drawing ?
    A.616
    B.345
    C.564
    D.712
    E.None of these
    Answer –A. 616
    Solution:
    Girls in drawing & Craft = 560-504 + 1120 – 560 = 56 + 560 = 616

II.Study the following information carefully to answer the given questions.
 In a class of 50 students 26% students play only cricket, 18% students play only Badminton. 10% students play only football, 20% students play only badminton and cricket, 12% students play only cricket and football and 8% students play only football and badminton. 6% students play all three games.

  1. Total how many students play Badminton ?
    A.26
    B.32
    C.28
    D.35
    E.None of these
    Answer – A. 26
    Solution:DI
    B = 10+3+4+9 = 26

  2. How many student play both Badminton and Football ?
    A.14
    B.6
    C.4
    D.7
    E.None of these
    Answer – C. 4

  3. Find the total number no of students play only Cricket and Football ?
    A.18
    B.13
    C.15
    D.23
    E.None of these
    Answer – A. 18
    Solution:
    13+5 = 18

  4. Total number of students play cricket is how much % less than the total no of students ?
    A.33%
    B.25%
    C.43%
    D.36%
    E.None of these
    Answer – D. 36%
    Solution:
    C total = 13+10+3+6 = 32
    % = [50-32/32]*100 = 18*100/50 = 36%

  5. Find the ratio of total no of students play only badminton, football , both football and badminton together to the no of student play only cricket, football and badminton ?
    A.2:1
    B.3:2
    C.2:3
    D.1:3
    E.None of these
    Answer – C. 2:3
    Solution:
    9+4+5 : 13+9+5 = 18:27 = 2:3