Hello Aspirants. Welcome to Online Maths in AffairsCloud.com. Here we are creating question sample in **Chain Rule**, which are common for competitive exams. We have included Some questions that are repeatedly asked in exams !!

**If 4 people can do a piece of work in 16 days working 5 hours each day. In how many the same work will be completed by 20 people working 4 hours each day?**

A) 10

B) 8

C) 4

D) 6

E) 7

**C) 4**

Explanation:

M1*H1*D1 = M2*H2*D2

4*5*16 = 20*4*D2

Solve D2 = 4**If 20 people can complete 2/5th of a work in 6 days working 4 hours each day, then how much work will be completed by 30 people in 2 days working 8 hours each day?**

A) 1

B) 4/5

C) 3/5

D) 2/5

E) 2/3

**D) 2/5**

Explanation:

M1*D1*H1*W2 = M2*D2*H2*W1

20*6*4*W2 = 30*2*8*(2/5)

Solve W2 = 2/5**10 people complete 2/5th of work in 8 days working 5 hours each day. How many additional men are needed to complete the work in a total of 14 days working same number of hours each day as earlier?**

A) 12

B) 10

C) 30

D) 20

E) 15

**B) 10**

Explanation:

Total work to be completed in 14 days, so (additional men+10 men already employed) will have to complete remaining work (1 – 2/5 ) = 3/5 of work in (14-8) = 6 days.. let x is additional men

M1*D1*H1*W2 = M2*D2*H2*W1

10*8*5*(3/5) = (10+x)*6*5*(2/5)

Solve x = 10

**A certain number of answer sheets can be checked in 12 days working 5 hours each day by 9 examiners. For how many hours a day should 4 examiners work to check twice the number of answer sheets in 30 days?**

A) 4 hours

B) 8 hours

C) 7 hours

D) 9 hours

E) 6 hours

**D) 9 hours**

Explanation:

Answer sheets are work here. So

M1*D1*H1*W2 = M2*D2*H2*W1

9*12*5*2 = 4*30*H2*1

Solve, H2 = 9

**A camp can provide food to 150 men for 45 days. After 10 days, 25 left the camp. What is the number of days for which the remaining food will last now?**

A) 42

B) 48

C) 40

D) 30

E) 36

**A) 42**

Explanation:

After 10 days, there is (45-10) = 35 days food for 150 men. But 25 men left, so there are 125 men left, and let now the same food is for x days for 125 men. So

M1*D1 = M2*D2

150*35 = 125*x

Solve, x = 42

**A certain piece of work was to be completed in 50 days for which 200 men were employed. After working for 40 days, additional 100 men were employed to complete the work on time. Had additional men were not employed, how many days behind schedule the work would be finished?**

A) 12

B) 8

C) 10

D) 5

E) None of these

**D) 5**

Explanation:

Let 200 men complete x work in 40 days after which (200+100) = 300 men complete the remaining (1-x) work in remaining 10 days [Total work to be completed in 50 days]

So, M1*D1*W2 = M2*D2*W1

200*40*(1-x) = 300*10*x

Solve, x= 8/11

This means that initially employed 200 men can finish 8/11th of work in 40 days, so let they will complete 1 whole work in x days.

M1*D1*W2 = M2*D2*W1

200*40*1 = 200*x*(8/11)

Solve, x = 55

This means extra (55-50) = 5 days will be required if additional men are not employed after 40 days.**20 men can complete 2/5th of work in 10 days working 6 hours each day. In how many days the remaining work will be completed by 20 women working 4 hours each day such that 4 women do as much work as is done by 2 men?**

A) 20

B) 42

C) 35

D) 45

E) 20

**D) 45**

Explanation:

4 w = 2m, so 1w = 1/2 m

And then 20 w = 10 m, so we have to find the number of days for 10 men to complete remaining work (1 – 2/5) = 3/5th .

M1*D1*H1*W2 = M2*D2*H2*W1

20*10*6*(3/5) = 10*D2*4*(2/5)

Solve, D2 = 45 days

**100 books can be bind by 50 students in 4 hours. How many books will be bind by 150 students in 2 hours?**

A) 150

B) 250

C) 200

D) 180

E) 120

**A) 150**

Explanation:

Binding books is a work, so

W2*S1*H1 = W1*S2*H2

W2*50*4 = 100*150*2

Solve W2 = 150 books

**2 men or 3 boys can do a piece of work in 14 days working 6 hours each day. In how many days 6 men and 9 boys will complete a work twice as large working together 2 hours each day?**

A) 12 days

B) 14 days

C) 16 days

D) 15 days

E) 10 days

**B) 14 days**

Explanation:

2 m = 3 b

So 1m = 3/2 b

6m + 8b = 6 * (3/2) b + 9b = 18 b

So we have to find the number of days for 18 boys

3 boys do 1 work in 14 days working 6 hours, let 18 boys do twice work in x days working 2 hrs each day, then

B1*D1*H1*W2 = B2*D2*H2*W1

3*14*6*2 = 18*x*2*1

Solve x = 14 days**20 people can eat 100 burgers in 2 hours. In how many hours 200 burgers will be eaten by 10 people?**

A) 5 hours

B) 8 hours

C) 7 hours

D) 4 hours

E) 6 hours

**B) 8 hours**

Explanation:

Eating burgers will be considered as a work. So

M1*H1*W2 = M2*H2*W1

20*2*200 = 10*H2*100

Solve H2 = 8

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