Hello Aspirants. Welcome to Online Quantitative Aptitude Section with explanation in AffairsCloud.com. Here we are creating question sample in **Ages **which is common for all competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Questions Penned by Yogit

**A said to B – seven years ago I was seven times as old as you were and three year hence I will be three times as old as you will be. The ages of A and B**

a) 52, 12

b) 42, 12

c) 32, 12

d) 54, 14

e) None of theseAnswer –**b) 42, 12**

**Explanation :**

A – 7 = 7*(B – 7)…….(1)

A + 3 = 3*(B + 3)…….. (2)

Solve both equations to get A and B**The ratio of the ages of priya and riya is 2:5. After 8 years, their ages will be in the ratio of 2:3. Then the sum of their present ages**

a) 12 years

b) 14 years

c) 16 years

d) 18 years

e) None of theseAnswer –**b) 14 years**

**Explanation :**

Let priya age = 2x and riya age = 5x.

So, (2x + 8)/(5x + 8) = 2/3, we get x = 2. So sum of priya and riya = 14**The sum of the age of mother and daughter is 100 years. 5 years ago their age were in the ratio of 2:1. The ratio of the age of daughter and mother after 10 years**

a) 2:5

b) 3:4

c) 3:5

d) 4:5

e) None of theseAnswer –**c) 3:5**

**Explanation :**

M + D = 100 and (M – 5)/(D -5) = 2/1

we get D = 35 and M = 65. So after 10 years ratio = 45/75 = 3/5**The ratio of the ages of two persons are in the ratio of 5:7 and the difference between their ages is 18 years. Find the sum of the ages of the person after 5 years,**

a) 112 years

b) 115 years

c) 117 years

d) 119 years

e) None of theseAnswer –**e) None of these**

**Explanation :**7x – 5x = 18…data inadequate**If 6 is subtracted from the present age of neha and the remainder is divided by 6, then the present age of mia is obtained. If Mia is 4 years younger to raj whose age is 12 years, then find the age of neha**

a) 50

b) 52

c) 54

d) 58

e) None of theseAnswer –**c) 54**

**Explanation :**

(N – 6)/6 = M = 12 – 4 = 8. We will get N = 54**If P age is twice the average age of P, Q and R age’s. Q’s age is one half the average of P, Q and R’s age. If the age of R is 5 years, then find the sum of ages of P, Q and R.**

a) 20

b) 25

c) 30

d) 35

e) None of theseAnswer –**c) 30**

**Explanation :**

P = 2*(P + Q+ R)/3

Q = (1/2)*(P + Q+ R)/3 and R = 5 solve these equations, we will get P = 20, Q = 5 and R = 5**The ratio between the A and B age is 7: 9. If the difference between the present ages of Q and P’s age after 4 years is 2 then what is the total of the present ages of P and Q?**

a) 42

b) 44

c) 46

d) 48

e) None of theseAnswer –**d) 48**

**Explanation :**

let age of B is 9x and that of A is 7x. So

9x – (7x +4) = 2, x = 3

So sum will be = 27 + 21 = 48**Ritu married 6 years ago. Today her age is 5/4 times her age at the time of her marriage. Her daughter age is 1/5 of her age. What is the ratio of ritu age to her daughter age after 6 years?**

a) 2:1

b) 3:1

c) 4:3

d) 5:2

e) None of theseAnswer –**b) 3:1**

**Explanation :**

R = (5/4)*(R – 6)

R = 30 years and daughter age = 30/5 = 6 years.

After 6 years ratio will be = 36/12 = 3:1**6 years ago Ram was twice as old as Shyam. If the ratio of their present ages is 9:5 respectively, what is the difference between their present ages in year?**

a) 20 year

b) 22 year

c) 24 year

d) 26 year

e) None of theseAnswer –**c) 24 year**

**Explanation :**

R – 6 = 2*(S – 6)

put R = 9x and S = 5x, we will get x = 6

so difference between ages is 4*6 = 24 years**The sum of the ages of a mother and her son is 45 years. Five years ago, the product of their ages was 3 times the mother age at that time, then the present age of the son,**

a) 8

b) 10

c) 12

d) 14

e) None of theseAnswer –**a) 8**

**Explanation :**

M + S = 45

(M -5)*(S – 5) = 3*(M – 5) so, S = 8 years

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