# Aptitude Questions : Ages Set 5

AffairsCloud YouTube Channel - Click Here

AffairsCloud APP Click Here

Hello Aspirants. Welcome to Online Maths in AffairsCloud.com. Here we are creating question sample in Ages, which is common for competitive exams. We have included some questions that are repeatedly asked in exams !!

1. Four years ago, the ratio of the ages of A and B was 5 : 9. 8 years hence the ratio will be 2 : 3 respectively. Find the present age of B?
A) 25
B) 20
C) 40
D) 60
E) 24
C) 40
Explanation:

Let 4 years ago Aâ€™s age = 5x, Bâ€™s age = 9x
Then 4+8 = 12 years after â€“ (5x+12)/(9x+12) = 2/3
Solve, x = 4
Bâ€™s present age = 9x+4 = 40

2. Eight years ago, A was 4 times as old as B. After 8 years A will be twice as old as B. What are their ages respectively?
A) 45, 18
B) 40, 10
C) 42, 18
D) 40, 16
E) 42, 16
D) 40, 16
Explanation:

Let Bâ€™s age 8 yrs ago = x, then Aâ€™s age = 4x
After (8+8) = 16 years:
(4x+16) = 2 * (x+8)
Solve, x = 8
Aâ€™s present age = 4x+8 = 40
Bâ€™s present age = x+8 = 16

3. Present age of B is twice that of A. 4 years hence Bâ€™s age will be 4 less than twice the age of A. Find the difference in their ages?
A) 8
B) 10
C) 4
D) 5
E) Cannot be determined
E) Cannot be determined
Explanation:

Let Aâ€™s present age = x, Then Bâ€™s present age = 2x
After 4 years, (2x+4) = 2(x+4) â€“ 4
0 = 0

4. After 6 years, Aâ€™s age will be 3/7th of Bâ€™s age. Also 10 years ago, ratio of ages of A and B was 1 : 5. What is Aâ€™s present age?
A) 20
B) 25
C) 24
D) 18
E) 50
D) 18
Explanation:

Let 10 years ago, Aâ€™s age = x, Bâ€™s age = 5x
After (10+6) = 16 years, (x+16) = (3/7) (5x+16)
Solve, x = 8
So Aâ€™s present age = x+10 = 18

5. B is twiceÂ older than C and A is 2 yearsÂ older than B. If the total of all of their ages is 27, what will be total of the ages of A and C 6 years hence?
A) 17
B) 29
C) 28
D) 23
E) 18
B) 29
Explanation:

Let Câ€™s present age = x, then Bâ€™s = 2x, and Aâ€™s = 2x+2
Given: x+2x+(2x+2) = 27
Solve, x = 5
Aâ€™s present age = 2x+2 = 12
Câ€™s present age = x = 5
6 years after A+C)â€™s age = 12+5+6+6 = 29

6. The sum of the present ages of A and B is 50. After 2 years Bâ€™s age will be 2 more than Câ€™s age then. If A is younger than C by 4 years, find the age of B 8 years ago.
A) 20
B) 40
C) 28
D) 26
E) 22
A) 20
Explanation:

The difference between B and Câ€™s age will remain same
Let Câ€™s present age = x, so Bâ€™s present age = (x+2)
sum of the present ages of A and B is 50, so Aâ€™s age becomes = 50-(x+2) =48-x
now A is younger than C by 4 years, so 48-x = x â€“ 4
Solve, x = 26
Bâ€™s present age = x+2 = 28
Before 8 years, Bâ€™s age = 28-8 = 20

7. After 10 years, Aâ€™s age will be twice that of Bâ€™s age. Aâ€™s present age is 6 times that of C. If Bâ€™s eighth birthday was celebrated 2 years ago, then what is Câ€™s present age?
A) 8
B) 5
C) 10
D) 15
E) 12
B) 5
Explanation:

Let Câ€™s present age = x, then Aâ€™s present age = 6x
Let Bâ€™s present age is y.
Then after 10 years, (6x+10) = 2 (y+10)
Solve, y = 3x-5 = Bâ€™s present age
Bâ€™s eighth birthday was celebrated 2 years ago, so Bâ€™s present age = 10, and also 3x-5 = 10
Solve, x = 5

8. The ratio of the present ages of A to B is 5 : 3. The ratio of Aâ€™s age 4 years ago to Bâ€™s age 4 years hence is 1 : 1. What is the ratio of Aâ€™s age 4 years hence to Bâ€™s age 4 years ago?
A) 3 : 2
B) 5 : 2
C) 3 : 1
D) 2 : 3
E) 1 : 3
C) 3 : 1
Explanation:

Let Aâ€™s present age = 5x, and Bâ€™s = 3x
Ratio of Aâ€™s age 4 years ago to Bâ€™s age 4 years hence is 1 : 1. So
(5x-4)/(3x+4) = 1/1
Solve x = 4
So Aâ€™s present age = 20, and Bâ€™s = 12
Required ratio = (20+4) : (12-4)

9. Present age of a father is three times more than his son. 8 years hence, fatherâ€™s age will be 2 and a half times of his sonâ€™s age. After 8 more years, how many times would father be his sonâ€™s age?
A) 3 n half times
B) 4 times
C) 1 n half times
D) 2 times
E) 3 times
D) 2 times
Explanation:

three times more than
Let present age of son = x, then of father = x+3x = 4x
After 8 years, (4x+8) = (5/2) (x+8)
Solve, x = 8
Required ratio = (4x+16) : (x+16) = 2 : 1

10. Age of A is three times the sum of ages of B and C. 5 years hence, Aâ€™s age will be twice the sum of ages of B and C. The total of their present ages is
A) 45
B) 60
C) 30
D) Cannot be determined
E) None of these
B) 60
Explanation:

Let (B+C)â€™s present age= x
Then Aâ€™s present age = 3x
After 5 years, (3x+5) = 2*(x+5+5)
Solve, x = 15
Sum = x+3x = 4x = 60

AffairsCloud Recommends Oliveboard Mock Test

AffairsCloud Ebook - Support Us to Grow