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Aptitude Questions : Ages Set 5

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Hello Aspirants. Welcome to Online Maths in AffairsCloud.com. Here we are creating question sample in Ages, which is common for competitive exams. We have included some questions that are repeatedly asked in exams !!

  1. Four years ago, the ratio of the ages of A and B was 5 : 9. 8 years hence the ratio will be 2 : 3 respectively. Find the present age of B?
    A) 25
    B) 20
    C) 40
    D) 60
    E) 24
    C) 40
    Explanation:

    Let 4 years ago A’s age = 5x, B’s age = 9x
    Then 4+8 = 12 years after – (5x+12)/(9x+12) = 2/3
    Solve, x = 4
    B’s present age = 9x+4 = 40

  2. Eight years ago, A was 4 times as old as B. After 8 years A will be twice as old as B. What are their ages respectively?
    A) 45, 18
    B) 40, 10
    C) 42, 18
    D) 40, 16
    E) 42, 16
    D) 40, 16
    Explanation:

    Let B’s age 8 yrs ago = x, then A’s age = 4x
    After (8+8) = 16 years:
    (4x+16) = 2 * (x+8)
    Solve, x = 8
    A’s present age = 4x+8 = 40
    B’s present age = x+8 = 16

  3. Present age of B is twice that of A. 4 years hence B’s age will be 4 less than twice the age of A. Find the difference in their ages?
    A) 8
    B) 10
    C) 4
    D) 5
    E) Cannot be determined
    E) Cannot be determined
    Explanation:

    Let A’s present age = x, Then B’s present age = 2x
    After 4 years, (2x+4) = 2(x+4) – 4
    0 = 0

  4. After 6 years, A’s age will be 3/7th of B’s age. Also 10 years ago, ratio of ages of A and B was 1 : 5. What is A’s present age?
    A) 20
    B) 25
    C) 24
    D) 18
    E) 50
    D) 18
    Explanation:

    Let 10 years ago, A’s age = x, B’s age = 5x
    After (10+6) = 16 years, (x+16) = (3/7) (5x+16)
    Solve, x = 8
    So A’s present age = x+10 = 18

  5. B is twice older than C and A is 2 years older than B. If the total of all of their ages is 27, what will be total of the ages of A and C 6 years hence?
    A) 17
    B) 29
    C) 28
    D) 23
    E) 18
    B) 29
    Explanation:

    Let C’s present age = x, then B’s = 2x, and A’s = 2x+2
    Given: x+2x+(2x+2) = 27
    Solve, x = 5
    A’s present age = 2x+2 = 12
    C’s present age = x = 5
    6 years after A+C)’s age = 12+5+6+6 = 29

  6. The sum of the present ages of A and B is 50. After 2 years B’s age will be 2 more than C’s age then. If A is younger than C by 4 years, find the age of B 8 years ago.
    A) 20
    B) 40
    C) 28
    D) 26
    E) 22
    A) 20
    Explanation:

    The difference between B and C’s age will remain same
    Let C’s present age = x, so B’s present age = (x+2)
    sum of the present ages of A and B is 50, so A’s age becomes = 50-(x+2) =48-x
    now A is younger than C by 4 years, so 48-x = x – 4
    Solve, x = 26
    B’s present age = x+2 = 28
    Before 8 years, B’s age = 28-8 = 20

  7. After 10 years, A’s age will be twice that of B’s age. A’s present age is 6 times that of C. If B’s eighth birthday was celebrated 2 years ago, then what is C’s present age?
    A) 8
    B) 5
    C) 10
    D) 15
    E) 12
    B) 5
    Explanation:

    Let C’s present age = x, then A’s present age = 6x
    Let B’s present age is y.
    Then after 10 years, (6x+10) = 2 (y+10)
    Solve, y = 3x-5 = B’s present age
    B’s eighth birthday was celebrated 2 years ago, so B’s present age = 10, and also 3x-5 = 10
    Solve, x = 5

  8. The ratio of the present ages of A to B is 5 : 3. The ratio of A’s age 4 years ago to B’s age 4 years hence is 1 : 1. What is the ratio of A’s age 4 years hence to B’s age 4 years ago?
    A) 3 : 2
    B) 5 : 2
    C) 3 : 1
    D) 2 : 3
    E) 1 : 3
    C) 3 : 1
    Explanation:

    Let A’s present age = 5x, and B’s = 3x
    Ratio of A’s age 4 years ago to B’s age 4 years hence is 1 : 1. So
    (5x-4)/(3x+4) = 1/1
    Solve x = 4
    So A’s present age = 20, and B’s = 12
    Required ratio = (20+4) : (12-4)

  9. Present age of a father is three times more than his son. 8 years hence, father’s age will be 2 and a half times of his son’s age. After 8 more years, how many times would father be his son’s age?
    A) 3 n half times
    B) 4 times
    C) 1 n half times
    D) 2 times
    E) 3 times
    D) 2 times
    Explanation:

    three times more than
    Let present age of son = x, then of father = x+3x = 4x
    After 8 years, (4x+8) = (5/2) (x+8)
    Solve, x = 8
    Required ratio = (4x+16) : (x+16) = 2 : 1

  10. Age of A is three times the sum of ages of B and C. 5 years hence, A’s age will be twice the sum of ages of B and C. The total of their present ages is
    A) 45
    B) 60
    C) 30
    D) Cannot be determined
    E) None of these
    B) 60
    Explanation:

    Let (B+C)’s present age= x
    Then A’s present age = 3x
    After 5 years, (3x+5) = 2*(x+5+5)
    Solve, x = 15
    Sum = x+3x = 4x = 60