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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeThe monthly salary of Sharmi and Kiran together is Rs. 28000 the salary of Sharmi and Kiran is increased by 25% and 12.5% respectively then the new salary of Kiran becomes 120% of the new salary of Sharmi the new salary of Sharmi is
Correct
Answer – 1. Rs. 15000
Explanation:
Let initial salary of Sharmi – X and (Kiran – 28000X).
Increased salary of Sharmi = X + 25% of X = 1.25X
Increased Salary of Kiran = (28000 – X) + 12.5% of (28000 – X)
Increased Salary of Kiran = (28000 – X) + 3500 – 0.125X = (31500 – 1.125X)
New Salary of Kiran = 120% of 1.25X
31500 – 1.125X = 1.50X
1.50X + 1.125X = 31500
2.475X = 31500
X = 12000 (Approx)
Initial salary of Sharmi = 12000.
Increased salary = 12000 + 25% of 12000 = Rs. 15000.Incorrect
Answer – 1. Rs. 15000
Explanation:
Let initial salary of Sharmi – X and (Kiran – 28000X).
Increased salary of Sharmi = X + 25% of X = 1.25X
Increased Salary of Kiran = (28000 – X) + 12.5% of (28000 – X)
Increased Salary of Kiran = (28000 – X) + 3500 – 0.125X = (31500 – 1.125X)
New Salary of Kiran = 120% of 1.25X
31500 – 1.125X = 1.50X
1.50X + 1.125X = 31500
2.475X = 31500
X = 12000 (Approx)
Initial salary of Sharmi = 12000.
Increased salary = 12000 + 25% of 12000 = Rs. 15000. 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudePraveen and Sundar invested some amount of money in the ratio of 3 : 5 for the same period in the business. They decided that at the end of the year 20% profit was to be given to an old age home as a donation. Out of the remaining, 75% was to be reinvested and the rest of the profit was to be divided as interest on their capitals. If the difference in there share is Rs. 1200. Find the total profit?
Correct
Answer – 2. 24000
Let the total profit = 100
Amount left after donation = 50
Amount left after reinvestment = 20
Now, 5y/8 – 3y/8 = 1200
y – the amount left after reinvestment
2x/8 = 1200
x = 4800
Total profit = 4800 x 5 = 24000Incorrect
Answer – 2. 24000
Let the total profit = 100
Amount left after donation = 50
Amount left after reinvestment = 20
Now, 5y/8 – 3y/8 = 1200
y – the amount left after reinvestment
2x/8 = 1200
x = 4800
Total profit = 4800 x 5 = 24000 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeOut of an amount of Rs. 700 a part was lent at 5% SI and the other at 10% SI. If the interest on the first part after 2 years equal to the interest on the second part after 4 years, then the second sum (in Rs.) is ?
Correct
Answer – 4. 140
Explanation :
P1*5*2/100 = P2*10*4/100
P1:P2 = 4:1
P2 = 700 * ⅕ = 140Incorrect
Answer – 4. 140
Explanation :
P1*5*2/100 = P2*10*4/100
P1:P2 = 4:1
P2 = 700 * ⅕ = 140 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudePradeep borrowed a sum of money and returned it in three equal quarterly instalments of Rs. 17576 each. Find the sum borrowed, if the rate of interest charged was 16% per annum compounded quarterly. Find also the total interest charged.
Correct
Answer – 2. 48775 and 3953
Rate of Interest = 16% annum
Actual rate of Interest = 4% per Quarter
Principal of all three installments
= [ 17576 (25/26) + (25/26)^2 + (25/26)^3]
= [17576*25*1951/26*676] = 48775
Total amount paid = Rs.17576 *3 = 52728
Interest charged = 52728 – 48775 = 3953Incorrect
Answer – 2. 48775 and 3953
Rate of Interest = 16% annum
Actual rate of Interest = 4% per Quarter
Principal of all three installments
= [ 17576 (25/26) + (25/26)^2 + (25/26)^3]
= [17576*25*1951/26*676] = 48775
Total amount paid = Rs.17576 *3 = 52728
Interest charged = 52728 – 48775 = 3953 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeArun started some business with Rs. 26,000. After 3 months Bala joined him with Rs. 16,000. After some more time Chitra joined them with Rs. 25,000. At the end of the year, out of a total profit of Rs. 15,453, Chitra gets Rs. 3825 as his share. For how many months after Bala joined the business did Chitra join?
Correct
Answer – 2. 3
Explanation :
Ratio of Profits = 26000 * 12 : 16000 * 9 : 25000 * C
= 312: 144 : 25C
Chitra’s Share 25C/456 + 25C = 3825/15453
C = 6.
9 – 6 = 3Incorrect
Answer – 2. 3
Explanation :
Ratio of Profits = 26000 * 12 : 16000 * 9 : 25000 * C
= 312: 144 : 25C
Chitra’s Share 25C/456 + 25C = 3825/15453
C = 6.
9 – 6 = 3 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudePrince can do a piece of work in 45 days, but Bala can do the same work in 5 days less, than Prince, when working alone. Prince and Bala both started the work together but Bala left after some days and Prince finished the remaining work in 56 days with half of his efficiency but he did the work with Bala with his complete efficiency. For how many days they had worked together?
Correct
Answer – 2. 8
Explanation:
Prince did the work in 56 days = 56×1/(45×2) = 28/45
Prince and Bala do the work in one day = 1/45+1/40=17/360
Therefore, Rest work 17/45 was done by Prince and Bala = (17/45)/(17/360) = 8 daysIncorrect
Answer – 2. 8
Explanation:
Prince did the work in 56 days = 56×1/(45×2) = 28/45
Prince and Bala do the work in one day = 1/45+1/40=17/360
Therefore, Rest work 17/45 was done by Prince and Bala = (17/45)/(17/360) = 8 days 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeHarish takes 3 hours more than Ajay, who drives his car 5 km/h faster than Harish drives, to cover 180 km distance. What is the speed of Harish?
Correct
Answer – 5. 15
Explanation:
S2 = S1 + 5
S1*S2 = Distance * (Difference in Speed/Difference in Time)
= 180 * 5/3
= 300
S1(S1 + 5) = 300
S1 = 15kmphIncorrect
Answer – 5. 15
Explanation:
S2 = S1 + 5
S1*S2 = Distance * (Difference in Speed/Difference in Time)
= 180 * 5/3
= 300
S1(S1 + 5) = 300
S1 = 15kmph 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeMahesh can row 40 km upstream and 55 km downstream in 13 h and 30 km upstream and 44 km downstream in 10 hours. What is the speed of Mahesh in still water?
Correct
Answer – 4. 8 km/h
Explanation:
40/(BS) + 55(B+S) = 13
30/(BS) + 44(B+S) = 10
Go through options.Incorrect
Answer – 4. 8 km/h
Explanation:
40/(BS) + 55(B+S) = 13
30/(BS) + 44(B+S) = 10
Go through options. 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA fast moving superfast express crosses another pasenger train in 20 seconds. The speed of faster train is 82 km/hr and speeds of slower train is 28 km/h. Also the length of faster train is 100m, then find the length of the slower train if they are moving in the same direction.
Correct
Answer – 4. 200 m
Explanation:
Time = Sum of length of the two train / Difference in speeds
Difference in speeds = 54 * 5/18 = 15m/s
20 = 100 + x / 15
X = 200Incorrect
Answer – 4. 200 m
Explanation:
Time = Sum of length of the two train / Difference in speeds
Difference in speeds = 54 * 5/18 = 15m/s
20 = 100 + x / 15
X = 200 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudePipe M can fill an empty container in 30 hours while N can fill it in 45 hours. Pipe M and N are opened and closed alternatively i.e., first pipe M is opened, then N, again M and then N and so on for 1 hour each time without any time lapse. In how many hours the container will be filled if it was empty, initially?
Correct
Answer – 1. 36
Explanation:
In 2hr, container will be filled by 3 + 2 = 5
90
30 — 3
45 — 2
Total time taken = 90/5 = 18
18 * 2 = 36Incorrect
Answer – 1. 36
Explanation:
In 2hr, container will be filled by 3 + 2 = 5
90
30 — 3
45 — 2
Total time taken = 90/5 = 18
18 * 2 = 36
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