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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA and B can complete a work in 40 and 60 days respectively. They started a work which is to be completed in 20 days. But it was found that they will not be able to complete work on time, so a third person C was appointed after 12 days. In how many days C can alone complete the work?
Correct
Explanation:
A and B worked for 20 days. In 1 day they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days because he joined after 12 days and up to 20 days.
So he can do 1 work in 48 daysIncorrect
Explanation:
A and B worked for 20 days. In 1 day they could have completed work (1/40 + 1/60) = 1/24
So in 20 days, they did (1/24)*20 = 5/6
This means C did 1 – 5/6 = 1/6 of work in 8 days because he joined after 12 days and up to 20 days.
So he can do 1 work in 48 days 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the areas of the circumcircle and the incircle of an equilateral triangle is
Correct
Explanation:
For equi. Triangle
Inradius = a/2√3
Circumradius = a/√3
So ratio is
ᴨ (a/√3)^2 : ᴨ (a/2√3)^2
= 4 : 1Incorrect
Explanation:
For equi. Triangle
Inradius = a/2√3
Circumradius = a/√3
So ratio is
ᴨ (a/√3)^2 : ᴨ (a/2√3)^2
= 4 : 1 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeHow many kg of wheat costing Rs 10 per kg must be mixed with 16 Kg of wheat costing Rs 15 per Kg, so that there may be gain of 30% by selling the mixture of Rs 15.6 per Kg?
Correct
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Solve, x = 24Incorrect
Explanation:
With 30% gain and SP = 15.6, CP = (100/130)*15.6 = 12
By method of allegation:
1st wheat (x kg)…………..2nd wheat (16 kg)
10……………………………..…….15
.,…………………..12
3………………………………………2
3 : 2
So x/16 = 3/2
Solve, x = 24 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeABC is a triangle with base AB. D is a point on AB such that AB = 7 and DB = 4. What is the ratio of the area of triangle ADC to the area of triangle ABC?
Correct
Explanation:
AB = 7, DB = 4
So AD = 74 = 3
Both ADC and ABC have same height and area of triangle is (1/2)*base*height
So required ratio is (1/2)*AD*h : (1/2)*AB*h
= AD : AB = 3 : 7Incorrect
Explanation:
AB = 7, DB = 4
So AD = 74 = 3
Both ADC and ABC have same height and area of triangle is (1/2)*base*height
So required ratio is (1/2)*AD*h : (1/2)*AB*h
= AD : AB = 3 : 7 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThere are 2 vertical posts, one of each side of a road, opposite to each other. From the top of one of the post having height 96 m, the angle of depression of the top and foot of the other post are 30 degree and 60 degree respectively. The height of the above post in m is
Correct
Explanation:
AB = 108, let CD = x
In ∆ABC, tan 30 = AB/BC so √3 = 96/BC
So BC = 32√3
In ∆AED, tan 30 = AE/ED so 1/√3 = (96x)/32√3
Solve, x = 64 mIncorrect
Explanation:
AB = 108, let CD = x
In ∆ABC, tan 30 = AB/BC so √3 = 96/BC
So BC = 32√3
In ∆AED, tan 30 = AE/ED so 1/√3 = (96x)/32√3
Solve, x = 64 m 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe value of cot 10^{o} . cot 20^{o} . cot 60^{o} . cot 70^{o} . cot 80^{o} is
Correct
Explanation:
Tan (90 – ɸ) = cot ɸ, and tanɸ.cotɸ = 1
So cot 10^{o} . cot 20^{o} . cot 60^{o} . tan 20^{o} . tan 10^{o}
= cot 60^{o} = √3Incorrect
Explanation:
Tan (90 – ɸ) = cot ɸ, and tanɸ.cotɸ = 1
So cot 10^{o} . cot 20^{o} . cot 60^{o} . tan 20^{o} . tan 10^{o}
= cot 60^{o} = √3 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (7–10): Study the following pie chart and answer the questions that follow:
Total employees in company is 750. Pie chart shows percentage of employees in 5 departments of a company in a year.
What is the total number of employees in departments B and E together in that year?
Correct
Explanation:
(14+26)/100 * 750 = 300Incorrect
Explanation:
(14+26)/100 * 750 = 300 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (7–10): Study the following pie chart and answer the questions that follow:
Total employees in company is 750. Pie chart shows percentage of employees in 5 departments of a company in a year.
In next year, if there is an increase of 2 % in the number of employees of department C, then how many employees are in department C in next year?
Correct
Explanation:
(102/100) * (20/100) * 750Incorrect
Explanation:
(102/100) * (20/100) * 750 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (7–10): Study the following pie chart and answer the questions that follow:
Total employees in company is 750. Pie chart shows percentage of employees in 5 departments of a company in a year.
In given year, the female employees in department E were 5/13 of total employees in that department. 4 females of E leave next year and equal males join that department, then what is the number of male employees in department E the next year?
Correct
Explanation:
In 2014, total employees in E = (26/100) * 750 = 195
So females are (5/13) * 195 = 75, so males were = 195 – 75 = 120
In 2015, 4 males joined, so males become 120+4Incorrect
Explanation:
In 2014, total employees in E = (26/100) * 750 = 195
So females are (5/13) * 195 = 75, so males were = 195 – 75 = 120
In 2015, 4 males joined, so males become 120+4 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (7–10): Study the following pie chart and answer the questions that follow:
Total employees in company is 750. Pie chart shows percentage of employees in 5 departments of a company in a year.
In given year, 20% of employees in department A were post graduates which gets shifted to department D in the next year. If in department D 40% were post graduates in given year, then what is the number of post graduate employees in department D the next year?
Correct
Explanation:
Post grads in department A = (20/100) * (22/100) * 750 = 33
Post grads in department D = (40/100) * (18/100) * 750 = 54
So in 2015, in department D post grads becomes 54+33Incorrect
Explanation:
Post grads in department A = (20/100) * (22/100) * 750 = 33
Post grads in department D = (40/100) * (18/100) * 750 = 54
So in 2015, in department D post grads becomes 54+33
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