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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Which is the least fraction out of 2/5, 4/7, 3/8 and 1/4?

Correct

Explanation:
Do by finding their decimal values
OR
Compare each
First – 2/5 and 4/7
2*7 = 14 and 4*5 = 20
So 2/5 is small than 4/7
Next – 2/5 and 3/8
2*8 = 16 and 3*5 = 15
So 3/8 is small than 2/5
Next – 3/8 and 1/4
3*4 = 14 and 1*8 = 8
So 1/4 is smallest

Incorrect

Explanation:
Do by finding their decimal values
OR
Compare each
First – 2/5 and 4/7
2*7 = 14 and 4*5 = 20
So 2/5 is small than 4/7
Next – 2/5 and 3/8
2*8 = 16 and 3*5 = 15
So 3/8 is small than 2/5
Next – 3/8 and 1/4
3*4 = 14 and 1*8 = 8
So 1/4 is smallest

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

A and B started a business by investing Rs 1200 and Rs 1500 respectively. After 4 months, A added Rs 200 an B added Rs 100 to their investments for 8 and 6 months respectively. After a year from the start of business, they got a total profit of Rs 11,850. What is the share of A in the profit?

Correct

Explanation:
A : B
1200*4 + 1400*8 : 1500*4 + 1600*6
12*4 + 14*8 : 15*4 + 16*6
12 + 14*2 : 15 + 8*3
40 : 39
So A got 40/79 * 11850 = 6000

Incorrect

Explanation:
A : B
1200*4 + 1400*8 : 1500*4 + 1600*6
12*4 + 14*8 : 15*4 + 16*6
12 + 14*2 : 15 + 8*3
40 : 39
So A got 40/79 * 11850 = 6000

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions (3–6): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.

If the monthly salary of the person is Rs 6,000, for how many items he has spent more than Rs 1,000 per month?

Correct

Explanation:
Shortcut-
(x/100)*6000 = 1000, gives x = 16.67%
So the ones having more expense % than 16.67% which is A and C

Incorrect

Explanation:
Shortcut-
(x/100)*6000 = 1000, gives x = 16.67%
So the ones having more expense % than 16.67% which is A and C

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions (3–6): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.

What is the angle made at the centre of the pie chart by the sector representing the expenses on item F?

Correct

Explanation:
(15/100)*360 = 54

Incorrect

Explanation:
(15/100)*360 = 54

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions (3–6): Study the pie chart and answer the questions that follow:
The pie chart shows the monthly expenses of a person done on various items.

Expenses on item D are approximately how much percent more than on item B, if the monthly salary of the person is Rs 12,000?

Correct

Explanation:
Required % = (15-7)/7 * 100

Incorrect

Explanation:
Required % = (15-7)/7 * 100

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

If the person spends Rs 500 per month on item E, what will be his monthly salary?

Correct

Explanation:
(10/100)*x = 500

Incorrect

Explanation:
(10/100)*x = 500

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

B is 3 years older than C and A is thrice older than B. If the ratio of ages of A and C is 4 : 1, what will be total of the ages of A and C, 4 years hence?

Correct

Explanation:
Let C’s present age = x, then B’s = x+3, and A’s = 3(x+3) = 3x+9
Now (3x+9)/x = 4/1
Solve, x = 9
A’s present age = 3x+9 = 36
C’s present age = x = 9
4 years after (A+C)’s age = 36+9+4+4

Incorrect

Explanation:
Let C’s present age = x, then B’s = x+3, and A’s = 3(x+3) = 3x+9
Now (3x+9)/x = 4/1
Solve, x = 9
A’s present age = 3x+9 = 36
C’s present age = x = 9
4 years after (A+C)’s age = 36+9+4+4

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Find the distance between two chords of a circle with diameter 30 cm, given the length of chords respectively are 18 cm and 24 cm.

Correct

Explanation:

OA = OC = 15 cm
AB = 18 cm, so AP = PB = 9 cm
CD = 24 cm, so CQ = QD = 12 cm
In ∆OCQ,
OQ = √(15^{2} – 9^{2}) = 12
In ∆OAP,
OP = √(5^{2} – 3^{2}) = 9
So PQ = OP+OQ = 9+12

Incorrect

Explanation:

OA = OC = 15 cm
AB = 18 cm, so AP = PB = 9 cm
CD = 24 cm, so CQ = QD = 12 cm
In ∆OCQ,
OQ = √(15^{2} – 9^{2}) = 12
In ∆OAP,
OP = √(5^{2} – 3^{2}) = 9
So PQ = OP+OQ = 9+12

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Find the volume of sphere whose total surface area of a hemisphere is 75ᴨ sq. cm.

Correct

Explanation:
2ᴨr^{2} + ᴨr^{2} = 75ᴨ
3ᴨr^{2} = 75ᴨ
So r^{2} = 25
So r = 5
So volume = (2/3)*ᴨr^{3} = (2/3)*(22/7)*5*5*5

Incorrect

Explanation:
2ᴨr^{2} + ᴨr^{2} = 75ᴨ
3ᴨr^{2} = 75ᴨ
So r^{2} = 25
So r = 5
So volume = (2/3)*ᴨr^{3} = (2/3)*(22/7)*5*5*5

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Find the length of diagonal BD of a rhombus ABCD whose side AB is 10 cm and angle A measures 60 degree

Correct

Explanation:

Diagonals of rhombus intersect at right angle. Also the diagonals bisect the angle and themselves also. Angle A = angle C = 60 degree
So angle B = angle D = 120 degree
In rt angled ∆AOB
Angle AOB = 90
Angle OAB = 60/2 = 30 and angle ABO = 120/2 = 60
Sin 30 = perpendicular/hypotenuse = OB/AB = OB/10
So 1/2 = OB/10 , so OB = 5cm
So BD = 5*2 = 10 cm

Incorrect

Explanation:

Diagonals of rhombus intersect at right angle. Also the diagonals bisect the angle and themselves also. Angle A = angle C = 60 degree
So angle B = angle D = 120 degree
In rt angled ∆AOB
Angle AOB = 90
Angle OAB = 60/2 = 30 and angle ABO = 120/2 = 60
Sin 30 = perpendicular/hypotenuse = OB/AB = OB/10
So 1/2 = OB/10 , so OB = 5cm
So BD = 5*2 = 10 cm