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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Distance between A and B is 640 km. Train P starts from point A at 6 AM towards point B with 70 km/hr. After 2 hours, train Q starts from point B towards A with 80 km/hr. At what time will they meet?

Correct

Explanation:
Let x hrs after 6 Am they meet
So
70*x + 80*(x-2) = 640
Solve, x = 5 hrs 20 mins
So 6AM + 5 hrs 20 mins = 11:20 AM

Incorrect

Explanation:
Let x hrs after 6 Am they meet
So
70*x + 80*(x-2) = 640
Solve, x = 5 hrs 20 mins
So 6AM + 5 hrs 20 mins = 11:20 AM

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

An article marked at Rs 360 is sold at 33 1/3%. After the discount also, the seller find that he earned a profit of 20%. What was the cost price of article for the seller?

Correct

Explanation:
Use formula
MP = (100+p%)/(100-d%) * CP
So CP = (100 – 100/3)/(100+20) * 360

Incorrect

Explanation:
Use formula
MP = (100+p%)/(100-d%) * CP
So CP = (100 – 100/3)/(100+20) * 360

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

A work can be completed in 48 days when 30 men work on it. Due to shortage of workers 20 men were employed. After they worked for 40 days, it was found that there is no hurry to complete the work and there are 40 days more to complete it. So some men were discharged from work. Find what number of men was discharged?

Correct

Explanation:
Let x men were discharged.
So 20 men worked for 40 days, and then (20-x) men worked for further 40 days.
So
30*48 = 20*40 + (20-x)*40
Solve, x = 4

Incorrect

Explanation:
Let x men were discharged.
So 20 men worked for 40 days, and then (20-x) men worked for further 40 days.
So
30*48 = 20*40 + (20-x)*40
Solve, x = 4

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

A work can be completed in 10 days by 7 men and 21 women. The same work gets completed in 8 days when 10 men and 19 women work on it. Find the number of days in which 5 men and 15 women together can complete the work?

Correct

Explanation:
7m + 21w = 10
5m + 15w = ?
We see here the ratio of men and women is same
So 7m + 21w = 10
7 (1m + 3w) = 10
So 1m + 3w = 7*10
So 5 (1m + 3w) = 7*10/5
So 5m + 15w = 14

Incorrect

Explanation:
7m + 21w = 10
5m + 15w = ?
We see here the ratio of men and women is same
So 7m + 21w = 10
7 (1m + 3w) = 10
So 1m + 3w = 7*10
So 5 (1m + 3w) = 7*10/5
So 5m + 15w = 14

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions (5-7): Study the pie chart given and answer the questions.
The pie chart shows the expenditure on different items and savings of a girl from her monthly salary.

If she spent Rs 4,060 on entertainment and savings together, what is her salary?

Correct

Explanation:
(36+80)/360 * x = 4060

Incorrect

Explanation:
(36+80)/360 * x = 4060

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Directions (5-7): Study the pie chart given and answer the questions.
The pie chart shows the expenditure on different items and savings of a girl from her monthly salary.

If her salary is Rs 9000, then how much she spent on cosmetics?

Correct

Explanation:
95/360 * 9000

Incorrect

Explanation:
95/360 * 9000

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions (5-7): Study the pie chart given and answer the questions.
The pie chart shows the expenditure on different items and savings of a girl from her monthly salary.

If she saved Rs 2800 in a month, then how much she spent on her clothes?

Correct

Explanation:
80/360 * x = 2800
So spent on clothes = 104/360 *x = 104/360 * 360/80 * 2800

Incorrect

Explanation:
80/360 * x = 2800
So spent on clothes = 104/360 *x = 104/360 * 360/80 * 2800

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Two medians AD and BE of ∆ABC intersect at O at right angles. If AD = 27 cm and BE = 18 cm, then the length of BD in cm is

Correct

Explanation:

GD = (1/3)*AD = (1/3)*27 = 9 cm
BG = (2/3)*BE = (2/3)*18 = 12 cm
In rt angled ∆BOD
So BD = √(9^2 + 12^2) = 15

Incorrect

Explanation:

GD = (1/3)*AD = (1/3)*27 = 9 cm
BG = (2/3)*BE = (2/3)*18 = 12 cm
In rt angled ∆BOD
So BD = √(9^2 + 12^2) = 15

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

The length of each side of an equilateral triangle is 14√3 cm. What is the area of the incircle?

Correct

Explanation:

BD = DC = 7√3 cm
In rt. angled ∆ADB
AD = √[(AB)^2 – (BD)^2] = √[(14√3)^2 – (7√3)^2]
AD = = √[(14√3 – 7√3) (14√3 + 7√3)] = √[(7√3) (21√3)] = 21
Radius of circle = OD = (1/3)*21 = 7 cm
So area = (22/7)*7*7

Incorrect

Explanation:

BD = DC = 7√3 cm
In rt. angled ∆ADB
AD = √[(AB)^2 – (BD)^2] = √[(14√3)^2 – (7√3)^2]
AD = = √[(14√3 – 7√3) (14√3 + 7√3)] = √[(7√3) (21√3)] = 21
Radius of circle = OD = (1/3)*21 = 7 cm
So area = (22/7)*7*7

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

If 4x^{2} + 9y^{2} + 1/x^{2} + 1/y^{2} = 10, then 4x^{2} + 9y^{2} equals