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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDistance between A and B is 640 km. Train P starts from point A at 6 AM towards point B with 70 km/hr. After 2 hours, train Q starts from point B towards A with 80 km/hr. At what time will they meet?
Correct
Explanation:
Let x hrs after 6 Am they meet
So
70*x + 80*(x2) = 640
Solve, x = 5 hrs 20 mins
So 6AM + 5 hrs 20 mins = 11:20 AMIncorrect
Explanation:
Let x hrs after 6 Am they meet
So
70*x + 80*(x2) = 640
Solve, x = 5 hrs 20 mins
So 6AM + 5 hrs 20 mins = 11:20 AM 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeAn article marked at Rs 360 is sold at 33 1/3%. After the discount also, the seller find that he earned a profit of 20%. What was the cost price of article for the seller?
Correct
Explanation:
Use formula
MP = (100+p%)/(100d%) * CP
So CP = (100 – 100/3)/(100+20) * 360Incorrect
Explanation:
Use formula
MP = (100+p%)/(100d%) * CP
So CP = (100 – 100/3)/(100+20) * 360 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA work can be completed in 48 days when 30 men work on it. Due to shortage of workers 20 men were employed. After they worked for 40 days, it was found that there is no hurry to complete the work and there are 40 days more to complete it. So some men were discharged from work. Find what number of men was discharged?
Correct
Explanation:
Let x men were discharged.
So 20 men worked for 40 days, and then (20x) men worked for further 40 days.
So
30*48 = 20*40 + (20x)*40
Solve, x = 4Incorrect
Explanation:
Let x men were discharged.
So 20 men worked for 40 days, and then (20x) men worked for further 40 days.
So
30*48 = 20*40 + (20x)*40
Solve, x = 4 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA work can be completed in 10 days by 7 men and 21 women. The same work gets completed in 8 days when 10 men and 19 women work on it. Find the number of days in which 5 men and 15 women together can complete the work?
Correct
Explanation:
7m + 21w = 10
5m + 15w = ?
We see here the ratio of men and women is same
So 7m + 21w = 10
7 (1m + 3w) = 10
So 1m + 3w = 7*10
So 5 (1m + 3w) = 7*10/5
So 5m + 15w = 14Incorrect
Explanation:
7m + 21w = 10
5m + 15w = ?
We see here the ratio of men and women is same
So 7m + 21w = 10
7 (1m + 3w) = 10
So 1m + 3w = 7*10
So 5 (1m + 3w) = 7*10/5
So 5m + 15w = 14 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (57): Study the pie chart given and answer the questions.
The pie chart shows the expenditure on different items and savings of a girl from her monthly salary.
If she spent Rs 4,060 on entertainment and savings together, what is her salary?
Correct
Explanation:
(36+80)/360 * x = 4060Incorrect
Explanation:
(36+80)/360 * x = 4060 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (57): Study the pie chart given and answer the questions.
The pie chart shows the expenditure on different items and savings of a girl from her monthly salary.
If her salary is Rs 9000, then how much she spent on cosmetics?
Correct
Explanation:
95/360 * 9000Incorrect
Explanation:
95/360 * 9000 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (57): Study the pie chart given and answer the questions.
The pie chart shows the expenditure on different items and savings of a girl from her monthly salary.
If she saved Rs 2800 in a month, then how much she spent on her clothes?
Correct
Explanation:
80/360 * x = 2800
So spent on clothes = 104/360 *x = 104/360 * 360/80 * 2800Incorrect
Explanation:
80/360 * x = 2800
So spent on clothes = 104/360 *x = 104/360 * 360/80 * 2800 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeTwo medians AD and BE of ∆ABC intersect at O at right angles. If AD = 27 cm and BE = 18 cm, then the length of BD in cm is
Correct
Explanation:
GD = (1/3)*AD = (1/3)*27 = 9 cm
BG = (2/3)*BE = (2/3)*18 = 12 cm
In rt angled ∆BOD
So BD = √(9^2 + 12^2) = 15Incorrect
Explanation:
GD = (1/3)*AD = (1/3)*27 = 9 cm
BG = (2/3)*BE = (2/3)*18 = 12 cm
In rt angled ∆BOD
So BD = √(9^2 + 12^2) = 15 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThe length of each side of an equilateral triangle is 14√3 cm. What is the area of the incircle?
Correct
Explanation:
BD = DC = 7√3 cm
In rt. angled ∆ADB
AD = √[(AB)^2 – (BD)^2] = √[(14√3)^2 – (7√3)^2]
AD = = √[(14√3 – 7√3) (14√3 + 7√3)] = √[(7√3) (21√3)] = 21
Radius of circle = OD = (1/3)*21 = 7 cm
So area = (22/7)*7*7Incorrect
Explanation:
BD = DC = 7√3 cm
In rt. angled ∆ADB
AD = √[(AB)^2 – (BD)^2] = √[(14√3)^2 – (7√3)^2]
AD = = √[(14√3 – 7√3) (14√3 + 7√3)] = √[(7√3) (21√3)] = 21
Radius of circle = OD = (1/3)*21 = 7 cm
So area = (22/7)*7*7 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIf 4x^{2} + 9y^{2} + 1/x^{2} + 1/y^{2} = 10, then 4x^{2} + 9y^{2} equals
Correct
Explanation:
4x^{2} + 9y^{2} + 1/x^{2} + 1/y^{2} = 10
so [4x^{2} + 1/x^{2} 4] + [9y^{2} + 1/y^{2} 6] = 0
(2x – 1/x)^{2} + (3y – 1/y)^{2} = 0
So (2x – 1/x)^{2} = 0,
Solve x= 1/√2
Similarly, y = 1/√3
So 4x^{2} + 9y^{2} = 4*(1/2) + 9*(1/3) = 5Incorrect
Explanation:
4x^{2} + 9y^{2} + 1/x^{2} + 1/y^{2} = 10
so [4x^{2} + 1/x^{2} 4] + [9y^{2} + 1/y^{2} 6] = 0
(2x – 1/x)^{2} + (3y – 1/y)^{2} = 0
So (2x – 1/x)^{2} = 0,
Solve x= 1/√2
Similarly, y = 1/√3
So 4x^{2} + 9y^{2} = 4*(1/2) + 9*(1/3) = 5
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