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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

A person bought 21 mangoes and 17 apples. He sells mangoes at Rs.46 each and makes 15% profit. He sells apples at Rs. 20 each and makes 25% profit. If he gets Rs. 1306 after selling all the mangoes and apples, find his (approximate) profit percentage?

Correct

Answer – 2) 17%
Explanation –
Let the C.P. of each mango is M and the C.P. of apple is A
M×115/100 = 46
M = Rs. 40
A × 125/100 = 20
A = Rs. 16
Total profit on all mangoes and apples = 21×6 + 17×4 = 194
Profit percentage = 194/ (1306-194) = 194/1112 = 17% (aprox)

Incorrect

Answer – 2) 17%
Explanation –
Let the C.P. of each mango is M and the C.P. of apple is A
M×115/100 = 46
M = Rs. 40
A × 125/100 = 20
A = Rs. 16
Total profit on all mangoes and apples = 21×6 + 17×4 = 194
Profit percentage = 194/ (1306-194) = 194/1112 = 17% (aprox)

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

In an offer if one buys three pens then fourth pen is sold at a discounted price of Rs. 10 only. Rohit took the offer. He left the shop with 24 pens after paying Rs. 330. What is the marked price of each pen?

Correct

Answer – 2) Rs. 15
Explanation –
Rohit got 24 pens
Every fourth pen is sold at Rs. 10
Total pens got by Rohit at Rs. 10 will be 24/4 = 6
Therefore, rest 18 pens he got at marked price.
Let the marked price of each pen is x, then
18x +6×10 = 330
X = Rs. 15

Incorrect

Answer – 2) Rs. 15
Explanation –
Rohit got 24 pens
Every fourth pen is sold at Rs. 10
Total pens got by Rohit at Rs. 10 will be 24/4 = 6
Therefore, rest 18 pens he got at marked price.
Let the marked price of each pen is x, then
18x +6×10 = 330
X = Rs. 15

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Find the ratio of area of circle to the area of rhombus, if the radius of circle is 10m and the diagonals of a rhombus of side 25m are in the ratio 3:4.

Correct

Answer – 3. 2π/3
Explanation –
Area of circle = π. (10)^{2} = 100π
Since the diagonal of rhombus bisect each other at 90 degree
By applying Pythagoras theorem on rhombus,
(3x)^{2} + (4x)^{2 }= 25^{2}
x = 5
diagonal of rhombus are 3x = 15m and 4x = 20m
Area of rhombus = ½ × diagonal (d1) × diagonal (d2) = 1/2× 15×20 = 150
Ratio = (100π)/150 = 2π/3

Incorrect

Answer – 3. 2π/3
Explanation –
Area of circle = π. (10)^{2} = 100π
Since the diagonal of rhombus bisect each other at 90 degree
By applying Pythagoras theorem on rhombus,
(3x)^{2} + (4x)^{2 }= 25^{2}
x = 5
diagonal of rhombus are 3x = 15m and 4x = 20m
Area of rhombus = ½ × diagonal (d1) × diagonal (d2) = 1/2× 15×20 = 150
Ratio = (100π)/150 = 2π/3

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

The number of males in a company was 15 more than the number of females. In new financial year, a few more females joined the company and the ratio of males to females became 5:6. Find the minimum number of females, who joined in new financial year?

Correct

Answer – 4) 19
Explanation – let the number of females initially is x , no. of males initially will be x +15
Let in new financial year y females joined
(x+15)/ (x + y) = 5/6
Y = (x+90)/5
Here since x has to be minimum 5 ( i.e. 5 females were initially in the company)
Therefore, y = 19

Incorrect

Answer – 4) 19
Explanation – let the number of females initially is x , no. of males initially will be x +15
Let in new financial year y females joined
(x+15)/ (x + y) = 5/6
Y = (x+90)/5
Here since x has to be minimum 5 ( i.e. 5 females were initially in the company)
Therefore, y = 19

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

A milkman has 2 containers, the first container has 30% water and rest milk and the second container has 40% water and rest milk. How many litres of mixture should be taken from each container to get 20 litres of mixture in third container which is empty, such that the ratio of water to milk in third container is 3:5?

Correct

Answer – 3) 5 litres from first and 15 litres from second container
Explanation –
Let’s convert percentage of water into ratio and take water in each case for applying allegation
30% ===== 3/10 = 24/80
40% ======4/10 = 32/80
To get 3/(3+5) = 3/8 = 30/80

So to get 20 litres quantity in third contained
5 litres should be taken from first container
And 15 litres should be taken from second container

Incorrect

Answer – 3) 5 litres from first and 15 litres from second container
Explanation –
Let’s convert percentage of water into ratio and take water in each case for applying allegation
30% ===== 3/10 = 24/80
40% ======4/10 = 32/80
To get 3/(3+5) = 3/8 = 30/80

So to get 20 litres quantity in third contained
5 litres should be taken from first container
And 15 litres should be taken from second container

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

The distance from point P and Q is 198km. Piyush and Nitin start from P at the same time and move towards Q. Piyush takes 4 hours more than Nitin to reach Q. Moreover, Piyush reaches the mid-point of P and Q one hour before Nitin reaches Q. The speed of Nitin in Km/hr, is –

Correct

Answer – 5) 33km/hr
Explanation –
Let the time taken by Nitin to go from P to Q is 2t
Time taken by Piyush to go from P to Q will be 2t + 4
also , time taken by Piyush to reach mid-point of P and Q will be (2t + 4)/2 = t + 2
Moreover, according to question
2t -1 = t+2 (since piyush reaches one hour before Nitin )
t = 3
2t = 6
Speed of Nitin = 198/6 = 33km/hr

Incorrect

Answer – 5) 33km/hr
Explanation –
Let the time taken by Nitin to go from P to Q is 2t
Time taken by Piyush to go from P to Q will be 2t + 4
also , time taken by Piyush to reach mid-point of P and Q will be (2t + 4)/2 = t + 2
Moreover, according to question
2t -1 = t+2 (since piyush reaches one hour before Nitin )
t = 3
2t = 6
Speed of Nitin = 198/6 = 33km/hr

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Efficiency of A is 25% more than B, they both finish the job in 26 days in the following manner: A worked alone till half the job is finished and left the job, then B works alone and does 5% of the job and finally A again joins with B to finish the remaining job in 8 days. In how many days can B alone finish the entire job?

Correct

Answer – 4) 40 days
Explanation –
Let the efficiency of B is 4x
Efficiency of A will be 5x
Total efficiency = 9x ( will be used when both worked together)
45% work finish by both together in 8 days with efficiency 9x
100% work will be finish in (100×8)/45 days with efficiency 9x
Let total work is (100×8)/45 × 9x = 160x
Time taken by B to finish entire work alone = 160x/4x = 40 days

Incorrect

Answer – 4) 40 days
Explanation –
Let the efficiency of B is 4x
Efficiency of A will be 5x
Total efficiency = 9x ( will be used when both worked together)
45% work finish by both together in 8 days with efficiency 9x
100% work will be finish in (100×8)/45 days with efficiency 9x
Let total work is (100×8)/45 × 9x = 160x
Time taken by B to finish entire work alone = 160x/4x = 40 days

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A boy travels two- third of a distance AB at a speed of 2p and remaining at a speed of q. If he goes from B to A and return at a speed 9r in the same time, then

Correct

Answer – 2. 3/q + 3/p = 2/r
Explanation –
Let the total distance is 3x
Distance travelled at speed 2p = 2x
Distance travelled at speed q = x
And distance travelled at speed r = 6x
According to question,
2x/2p + x/q = 6x/9r
1/p + 1/q = 2/3r
3/p + 3/q = 2/r

Incorrect

Answer – 2. 3/q + 3/p = 2/r
Explanation –
Let the total distance is 3x
Distance travelled at speed 2p = 2x
Distance travelled at speed q = x
And distance travelled at speed r = 6x
According to question,
2x/2p + x/q = 6x/9r
1/p + 1/q = 2/3r
3/p + 3/q = 2/r

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

To run a 30 day course in computer, the initial investment of Rs. 100000 on the infrastructure is done entirely by Rahul whereas the other costs (electricity, maintenance etc.) of Rs. 10 per student/day is borne entirely by Niraj. If each student pays Rs. 500 as fees for the course, find the minimum number of enrolment in course required to make the course profitable for Niraj and Rahul?

Correct

Answer – 4) 501
Explanation –
Let the number of students required to make the course profitable is x
Total amount received from students = Rs. 500x
Investment of Niraj in 30days = 10 × 30 × x = Rs. 300x
Investment of Rahul on infrastructure = Rs. 100000
To achieve profit from the course
Rs. 500x > Rs. 100000 + Rs. 300x
200x > 100000
X > 500
Minimum student required = 501

Incorrect

Answer – 4) 501
Explanation –
Let the number of students required to make the course profitable is x
Total amount received from students = Rs. 500x
Investment of Niraj in 30days = 10 × 30 × x = Rs. 300x
Investment of Rahul on infrastructure = Rs. 100000
To achieve profit from the course
Rs. 500x > Rs. 100000 + Rs. 300x
200x > 100000
X > 500
Minimum student required = 501

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

A dice is rolled twice. What is the probability that the number in the second roll will be lower than that in the first ?

Correct

Answer – 1) 5/12
Explanation –
If the number in the first roll is 2, lower values possible is 1
If the number in the first roll is 3, lower values possible are 1, 2,
If the number in the first roll is 4, lower values possible are 1, 2,3
If the number in the first roll is 5, lower values possible are 1, 2, 3, 4,
If the number in the first roll is 6, lower values possible are 1,2,3,4,5
Probability = 15/(6×6) = 5/12

Incorrect

Answer – 1) 5/12
Explanation –
If the number in the first roll is 2, lower values possible is 1
If the number in the first roll is 3, lower values possible are 1, 2,
If the number in the first roll is 4, lower values possible are 1, 2,3
If the number in the first roll is 5, lower values possible are 1, 2, 3, 4,
If the number in the first roll is 6, lower values possible are 1,2,3,4,5
Probability = 15/(6×6) = 5/12

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