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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A shopkeeper sells six items i.e. laptop, TV, Refrigerator, Printer, Mobile and Desktop. The following table gives information about them. Few things are missing in the table. Read it carefully and answer the following questions.**

**Ratio of marked price to selling price of the desktop is 8:7 and the marked price is Rs 3500 more than its selling price. Cost price of the desktop is how much percent less than its marked price (approximately)?**Correct**Answer- 2) 23%**

Explanation-

Marked prize of the desktop = 3500 × 8 = Rs 28000

Selling prize of the desktop = 3500 × 7 = Rs 24500

Cost prize = Rs 21590

Required percentage = (28000 – 21590)/28000 × 100 = 23% (approx.)Incorrect**Answer- 2) 23%**

Explanation-

Marked prize of the desktop = 3500 × 8 = Rs 28000

Selling prize of the desktop = 3500 × 7 = Rs 24500

Cost prize = Rs 21590

Required percentage = (28000 – 21590)/28000 × 100 = 23% (approx.) - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A shopkeeper sells six items i.e. laptop, TV, Refrigerator, Printer, Mobile and Desktop. The following table gives information about them. Few things are missing in the table. Read it carefully and answer the following questions.**

**The cost price of the mobile is half of the cost price of desktop and its marked prize is 110% more than the marked price of printer. If marked price of mobile is Rs 1206.25 more than its selling price, what percent of profit is earned by the shopkeeper on the sale of mobile phone?**Correct**Answer- 2) 25%**

Explanation-

Cost price of mobile = 21590/2 = Rs 10795

Marked price of mobile = 7000 + 110% of 7000 = 7000 + 7700 = Rs 14700

Selling price of mobile = 14700 – 1206.25 = Rs 13493.75

Profit % = (13493.75 – 10795)/10795 × 100 = 269875/10795 = 25%Incorrect**Answer- 2) 25%**

Explanation-

Cost price of mobile = 21590/2 = Rs 10795

Marked price of mobile = 7000 + 110% of 7000 = 7000 + 7700 = Rs 14700

Selling price of mobile = 14700 – 1206.25 = Rs 13493.75

Profit % = (13493.75 – 10795)/10795 × 100 = 269875/10795 = 25% - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A shopkeeper sells six items i.e. laptop, TV, Refrigerator, Printer, Mobile and Desktop. The following table gives information about them. Few things are missing in the table. Read it carefully and answer the following questions.**

**If the selling price of the Laptop is 22% less than its marked price, what is the approximate difference between its marked price and the cost price?**Correct**Answer- 4) Rs 13594.8**

Explanation-

Selling price of the laptop = 78% of 41500 = Rs 32370

Cost price of the laptop = 32370/116 × 100 = Rs 27905.1724

Required difference = 41500 – 27905.1724 = Rs 13594.8 (approx.)Incorrect**Answer- 4) Rs 13594.8**

Explanation-

Selling price of the laptop = 78% of 41500 = Rs 32370

Cost price of the laptop = 32370/116 × 100 = Rs 27905.1724

Required difference = 41500 – 27905.1724 = Rs 13594.8 (approx.) - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**Despite giving a discount of 15% on the printer, shopkeeper earns a profit of 19%. What is the cost price of the printer?**Correct**Answer- 1) Rs 5000**

Explanation-

Selling price of the printer = 85% of 7000 = Rs 5950

Cost price of the printer = 5950/119 × 100 = Rs 5000Incorrect**Answer- 1) Rs 5000**

Explanation-

Selling price of the printer = 85% of 7000 = Rs 5950

Cost price of the printer = 5950/119 × 100 = Rs 5000 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**If the discount given on the TV is Rs 1850, what is the cost price of TV?**Correct**Answer- 3) Rs 2500**

Explanation-

Marked price of TV = 1850/37 × 100 = Rs 5000

Selling price = 5000 – 1850 = Rs 3150

Cost price = 3150 – 650 = Rs 2500Incorrect**Answer- 3) Rs 2500**

Explanation-

Marked price of TV = 1850/37 × 100 = Rs 5000

Selling price = 5000 – 1850 = Rs 3150

Cost price = 3150 – 650 = Rs 2500 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The pie charts given below shows the distance travelled by boat from Monday to Sunday downstream and upstream respectively. The speeds of both stream and boat keep changing every day. (ignore that there are 24 hrs in a day)**

**On Tuesday, the speed of the boat in still water is 7km/h more than that of stream on the same day. If the time taken to travel upstream on Tuesday is 1614/119 h less than the time taken to travel downstream, what is the speed of the stream on Tuesday?**Correct**Answer- 2) 5 km/h**

Explanation-

Let the speed of stream on Tuesday is x km/h

Speed of boat = x + 7

Distance travelled upstream on Tuesday = 12 % of 1800 = 216 km

Distance travelled downstream on Tuesday = 21% of 1400 = 294 km

We have, according to the question,

216/7 – 294/ (2x + 7) = 1614/119

By solving, we have, x = 5 km/hIncorrect**Answer- 2) 5 km/h**

Explanation-

Let the speed of stream on Tuesday is x km/h

Speed of boat = x + 7

Distance travelled upstream on Tuesday = 12 % of 1800 = 216 km

Distance travelled downstream on Tuesday = 21% of 1400 = 294 km

We have, according to the question,

216/7 – 294/ (2x + 7) = 1614/119

By solving, we have, x = 5 km/h - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The pie charts given below shows the distance travelled by boat from Monday to Sunday downstream and upstream respectively. The speeds of both stream and boat keep changing every day. (ignore that there are 24 hrs in a day)**

**On Friday, the speed of the boat in the still water is double of the speed of stream. If the boat travelled total for 808/21 h on Friday, what is the difference between the speed of boat in still water on Friday and the speed of the stream on the same day?**Correct**Answer- 4) 7 km/h**

Explanation-

Let the speed of stream is x km/h

Then, speed of boat = 2x

Distance travelled upstream on Friday = 9% of 1800 = 162 km

Distance travelled downstream = 23% of 1400 = 322 km

According to question,

162/x + 322/3x = 808/21

By solving, we have, x = 7km/h

2x = 14 km/h

Required difference = 14 – 7 = 7 km/hIncorrect**Answer- 4) 7 km/h**

Explanation-

Let the speed of stream is x km/h

Then, speed of boat = 2x

Distance travelled upstream on Friday = 9% of 1800 = 162 km

Distance travelled downstream = 23% of 1400 = 322 km

According to question,

162/x + 322/3x = 808/21

By solving, we have, x = 7km/h

2x = 14 km/h

Required difference = 14 – 7 = 7 km/h - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10). The pie charts given below shows the distance travelled by boat from Monday to Sunday downstream and upstream respectively. The speeds of both stream and boat keep changing every day. (ignore that there are 24 hrs in a day)**

**If the speed of the stream on Saturday is 3 km/h and that of boat is 12 km/h, what is the total time taken by boat to travel upstream and downstream on Saturday?**Correct**Answer- 1) 92/3 hrs**

Explanation-

Distance travelled upstream on Saturday = 13% of 1800 = 234 km

Distance travelled downstream on Saturday = 5% of 1400 = 70 km

Total time taken = 234/9 + 70/15 = 92/3 hrsIncorrect**Answer- 1) 92/3 hrs**

Explanation-

Distance travelled upstream on Saturday = 13% of 1800 = 234 km

Distance travelled downstream on Saturday = 5% of 1400 = 70 km

Total time taken = 234/9 + 70/15 = 92/3 hrs - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

**What is the difference between the total distance travelled upstream on Monday, Wednesday and Thursday together and the total distance travelled downstream on the same days together?**Correct**Answer- 3) 446 km**

Explanation-

Total distance travelled upstream on these days = (18 + 24 + 10) % of 1800 = 52% of 1800 = 936 km

Total distance travelled downstream on these days = (8 + 17 + 10) % of 1400 = 490 km

Required difference = 936 – 490 = 446 kmIncorrect**Answer- 3) 446 km**

Explanation-

Total distance travelled upstream on these days = (18 + 24 + 10) % of 1800 = 52% of 1800 = 936 km

Total distance travelled downstream on these days = (8 + 17 + 10) % of 1400 = 490 km

Required difference = 936 – 490 = 446 km - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

**If the time taken to go upstream on Sunday is 21 hrs and to go downstream is 112/9 hrs, the speed of the boat in still water is how much more than the speed of stream on the same day?**Correct**Answer-5) 12 km/h**

Let the speed of boat upstream on Sunday is x km/h and downstream is y km/h.

Distance travelled upstream on Sunday = 14% of 1800 = 252 km

Distance travelled downstream on Sunday = 16% of 1400 = 224 km

We have,

252/x = 21, x = 12 km/h

Also, 224/y = 112/9, y = 18 km/h

Speed of stream = (18 – 12)/2 = 3 km/h

Speed of boat in still water = (18 + 12)/2 = 15 km/h

Required difference = 15 – 3 = 12 km/hIncorrect**Answer-5) 12 km/h**

Let the speed of boat upstream on Sunday is x km/h and downstream is y km/h.

Distance travelled upstream on Sunday = 14% of 1800 = 252 km

Distance travelled downstream on Sunday = 16% of 1400 = 224 km

We have,

252/x = 21, x = 12 km/h

Also, 224/y = 112/9, y = 18 km/h

Speed of stream = (18 – 12)/2 = 3 km/h

Speed of boat in still water = (18 + 12)/2 = 15 km/h

Required difference = 15 – 3 = 12 km/h

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