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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A private tutor Rajan can teach three subjects i.e. Physics, Mathematics and Chemistry. He works five days a week. He takes different number of classes every day of each subject as shown by the table below. Few values are missing in the table. He is paid differently for each subject which is also shown by a table.**

**Total money earned by Rajan on Monday is Rs 8400. No of Chemistry classes taken by him on Monday are:**Correct**Answer- 2) 1**

Explanation-

Let the number of Chemistry classes taken by him on Monday are x.

Then, according to question,

2 × 1500 + 3 × 1250 + 1650x = 8400

1650x = 8400 – 3000 – 3750 = 1650

x = 1Incorrect**Answer- 2) 1**

Explanation-

Let the number of Chemistry classes taken by him on Monday are x.

Then, according to question,

2 × 1500 + 3 × 1250 + 1650x = 8400

1650x = 8400 – 3000 – 3750 = 1650

x = 1 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A private tutor Rajan can teach three subjects i.e. Physics, Mathematics and Chemistry. He works five days a week. He takes different number of classes every day of each subject as shown by the table below. Few values are missing in the table. He is paid differently for each subject which is also shown by a table.**

**The amount of money earned by Rajan by teaching Chemistry on Thursday is how much more than the money earned by him by teaching Mathematics on Wednesday?**Correct**Answer- 5) Rs 5750**

Explanation-

Money earned by Rajan by teaching Chemistry on Thursday = 1650 × 5 = Rs 8250

Money earned by Rajan by teaching Mathematics on Wednesday = 1250 × 2 = Rs 2500

Required difference = 8250 – 2500 = Rs 5750Incorrect**Answer- 5) Rs 5750**

Explanation-

Money earned by Rajan by teaching Chemistry on Thursday = 1650 × 5 = Rs 8250

Money earned by Rajan by teaching Mathematics on Wednesday = 1250 × 2 = Rs 2500

Required difference = 8250 – 2500 = Rs 5750 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). A private tutor Rajan can teach three subjects i.e. Physics, Mathematics and Chemistry. He works five days a week. He takes different number of classes every day of each subject as shown by the table below. Few values are missing in the table. He is paid differently for each subject which is also shown by a table.**

**The total money earned by Rajan on Friday is Rs 7250 and the number of Physics classes taken by him on Friday are 3 more than that of Mathematics. Total number of classes taken by him on Friday are:**Correct**Answer- 1) 5**

Explanation-

Let the number of Mathematics classes taken by him on Friday are x.

Then, the number of Physics classes taken by him = x + 3

According to question, we have,

1500(x + 3) + 1250x = 7250

1500x + 4500 + 1250x = 7250

2750x = 2750

x = 1

Number of Physics classes taken on Friday = 1 + 3 = 4

Total number of classes taken = 4 + 1 = 5Incorrect**Answer- 1) 5**

Explanation-

Let the number of Mathematics classes taken by him on Friday are x.

Then, the number of Physics classes taken by him = x + 3

According to question, we have,

1500(x + 3) + 1250x = 7250

1500x + 4500 + 1250x = 7250

2750x = 2750

x = 1

Number of Physics classes taken on Friday = 1 + 3 = 4

Total number of classes taken = 4 + 1 = 5 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**Total number of classes taken by Rajan on Wednesday are 6 and the total money earned on Wednesday is Rs 9100. The number of Chemistry classes taken by him on Wednesday are how much percent more or less that of Mathematics classes?**Correct**Answer- 2) 100%**

Explanation-

Let the number of Chemistry classes taken by him on Wednesday are x.

Then, the number of Physics classes taken = 6 – 2 – x = 4 – x

According to question,

1500x + 1250 × 2 + 1650 × (4 – x) = 9100

1500x + 2500 + 6600 – 1650x = 9100

150x = 0, x = 0

Number of Physics classes taken = 4 – 0 = 4

Required percentage = (4 – 2)/2 × 100 = 100%Incorrect**Answer- 2) 100%**

Explanation-

Let the number of Chemistry classes taken by him on Wednesday are x.

Then, the number of Physics classes taken = 6 – 2 – x = 4 – x

According to question,

1500x + 1250 × 2 + 1650 × (4 – x) = 9100

1500x + 2500 + 6600 – 1650x = 9100

150x = 0, x = 0

Number of Physics classes taken = 4 – 0 = 4

Required percentage = (4 – 2)/2 × 100 = 100% - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**Total number of Chemistry classes taken by him in a week if the total money earned by him teaching Chemistry is Rs 19800?**Correct**Answer- 4) 12**

Explanation-

Let the number of Chemistry classes taken by him in a week are x.

Then, according to question,

1650x = 19800, x = 12Incorrect**Answer- 4) 12**

Explanation-

Let the number of Chemistry classes taken by him in a week are x.

Then, according to question,

1650x = 19800, x = 12 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10).**In a day, shopkeeper sold five type of products i.e. A, B, C, D and E. Number of C products sold are 25% more than that of B products. Number of D products sold are 80% more than that of E products. Total number of A products and D products sold together are 16. Total number of C products and E products sold together are 20. Number of A products sold are 2 more than that of E products.

Selling price of each B product is 40% more than that of each A product. Selling price of each D product is equal to the average selling price of each A product and each B product. Selling price of each C product is 15% less than that of each B product and selling price of each E product is 3/2 of each D product. Total selling price of each A product and each D product together is Rs 2750.**Total amount of sale of B products is:**Correct**Answer- 2) Rs 21000**

Explanation:

Let the number of A products sold are x.

Number of E products = x – 2

Number of C products = 20 – x + 2 = 22 – x

Number of D products = 180% of (x – 2) = 1.8x – 3.6

Number of B products = (22 – x)/125 × 100 = (88 – 4x)/5

We have,

x + 1.8x – 3.6 = 16

2.8x = 19.6, x = 7

Therefore,

Number of A products sold = 7

Number of B products sold = (88 – 28)/5 = 60/5 = 12

Number of C products sold = 22 – 7 = 15

Number of D products sold = 1.8 × 7 – 3.6 = 12.6 – 3.6 = 9

Number of E products sold = 7 – 2 = 5Let the selling price of each A product is Rs 100y

Selling price of each B product = 140% of 100y = Rs 140y

Selling price of each D product = (100y + 140y)/2 = Rs 120y

Selling price of each C product = 85% of 140y = Rs 119y

Selling price of each E product = 3/2 × 120y = Rs 180y

We have,

100y + 120y = 2750

220y = 2750, y = Rs 12.5

Selling price of each A product = 12.5 × 100 = Rs 1250

Selling price of each B product = 1250/100 × 140 = Rs 1750

Selling price of each C product = 119/100 × 1250 = Rs 1487.5

Selling price of each D product = 120/100 × 1250 = Rs 1500

Selling price of each E product = 180/100 × 1250 = Rs 2250Total sale of B products = 12 × 1750 = Rs 21000

Incorrect**Answer- 2) Rs 21000**

Explanation:

Let the number of A products sold are x.

Number of E products = x – 2

Number of C products = 20 – x + 2 = 22 – x

Number of D products = 180% of (x – 2) = 1.8x – 3.6

Number of B products = (22 – x)/125 × 100 = (88 – 4x)/5

We have,

x + 1.8x – 3.6 = 16

2.8x = 19.6, x = 7

Therefore,

Number of A products sold = 7

Number of B products sold = (88 – 28)/5 = 60/5 = 12

Number of C products sold = 22 – 7 = 15

Number of D products sold = 1.8 × 7 – 3.6 = 12.6 – 3.6 = 9

Number of E products sold = 7 – 2 = 5Let the selling price of each A product is Rs 100y

Selling price of each B product = 140% of 100y = Rs 140y

Selling price of each D product = (100y + 140y)/2 = Rs 120y

Selling price of each C product = 85% of 140y = Rs 119y

Selling price of each E product = 3/2 × 120y = Rs 180y

We have,

100y + 120y = 2750

220y = 2750, y = Rs 12.5

Selling price of each A product = 12.5 × 100 = Rs 1250

Selling price of each B product = 1250/100 × 140 = Rs 1750

Selling price of each C product = 119/100 × 1250 = Rs 1487.5

Selling price of each D product = 120/100 × 1250 = Rs 1500

Selling price of each E product = 180/100 × 1250 = Rs 2250Total sale of B products = 12 × 1750 = Rs 21000

- Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10).**In a day, shopkeeper sold five type of products i.e. A, B, C, D and E. Number of C products sold are 25% more than that of B products. Number of D products sold are 80% more than that of E products. Total number of A products and D products sold together are 16. Total number of C products and E products sold together are 20. Number of A products sold are 2 more than that of E products.

Selling price of each B product is 40% more than that of each A product. Selling price of each D product is equal to the average selling price of each A product and each B product. Selling price of each C product is 15% less than that of each B product and selling price of each E product is 3/2 of each D product. Total selling price of each A product and each D product together is Rs 2750.**Total number of A products, C products and E products sold together are:**Correct**Answer- 5) 27**

Explanation-

Required number = 7 + 15 + 5 = 27 (see the solution of Q6)Incorrect**Answer- 5) 27**

Explanation-

Required number = 7 + 15 + 5 = 27 (see the solution of Q6) - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10).**In a day, shopkeeper sold five type of products i.e. A, B, C, D and E. Number of C products sold are 25% more than that of B products. Number of D products sold are 80% more than that of E products. Total number of A products and D products sold together are 16. Total number of C products and E products sold together are 20. Number of A products sold are 2 more than that of E products.

Selling price of each B product is 40% more than that of each A product. Selling price of each D product is equal to the average selling price of each A product and each B product. Selling price of each C product is 15% less than that of each B product and selling price of each E product is 3/2 of each D product. Total selling price of each A product and each D product together is Rs 2750.**Total amount of sale of D products is how much more than the total amount of sale of A products?**Correct**Answer- 3) Rs 4750**

Explanation-

Total sale of D products = 9 × 1500 = Rs 13500

Total sale of A products = 7 × 1250 = Rs 8750

Required difference = 13500 – 8750 = Rs 4750Incorrect**Answer- 3) Rs 4750**

Explanation-

Total sale of D products = 9 × 1500 = Rs 13500

Total sale of A products = 7 × 1250 = Rs 8750

Required difference = 13500 – 8750 = Rs 4750 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10).**In a day, shopkeeper sold five type of products i.e. A, B, C, D and E. Number of C products sold are 25% more than that of B products. Number of D products sold are 80% more than that of E products. Total number of A products and D products sold together are 16. Total number of C products and E products sold together are 20. Number of A products sold are 2 more than that of E products.

Selling price of each B product is 40% more than that of each A product. Selling price of each D product is equal to the average selling price of each A product and each B product. Selling price of each C product is 15% less than that of each B product and selling price of each E product is 3/2 of each D product. Total selling price of each A product and each D product together is Rs 2750.**Amount of sale of which of the products is highest?**Correct**Answer- 1) C**

Explanation-

Amount of sale of product A = 7 × 1250 = Rs 8750

Amount of sale of product B = 12 × 1750 = Rs 21000

Amount of sale of product C = 15 × 1487.5 = Rs 22312.5

Amount of sale of product D = 9 × 1500 = Rs 13500

Amount of sale of product E = 5 × 2250 = Rs 11250

Therefore, amount of sale of product C is the highest.Incorrect**Answer- 1) C**

Explanation-

Amount of sale of product A = 7 × 1250 = Rs 8750

Amount of sale of product B = 12 × 1750 = Rs 21000

Amount of sale of product C = 15 × 1487.5 = Rs 22312.5

Amount of sale of product D = 9 × 1500 = Rs 13500

Amount of sale of product E = 5 × 2250 = Rs 11250

Therefore, amount of sale of product C is the highest. - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q6-10).**In a day, shopkeeper sold five type of products i.e. A, B, C, D and E. Number of C products sold are 25% more than that of B products. Number of D products sold are 80% more than that of E products. Total number of A products and D products sold together are 16. Total number of C products and E products sold together are 20. Number of A products sold are 2 more than that of E products.

Selling price of each B product is 40% more than that of each A product. Selling price of each D product is equal to the average selling price of each A product and each B product. Selling price of each C product is 15% less than that of each B product and selling price of each E product is 3/2 of each D product. Total selling price of each A product and each D product together is Rs 2750.**There are another type of products sold by shopkeeper called F. Number of F products sold are 10 more than that of C products. Price of each F product is half the price of each A product. Amount of sale of F products are:**Correct**Answer- 2) Rs 15625**

Explanation-

Total number of F products sold = 15 + 10 = 25

Price of each F product = 1250/2 = Rs 625

Total sale of F products = 625 × 25 = Rs 15625Incorrect**Answer- 2) Rs 15625**

Explanation-

Total number of F products sold = 15 + 10 = 25

Price of each F product = 1250/2 = Rs 625

Total sale of F products = 625 × 25 = Rs 15625

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