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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeQ(15)Choose your answer
1)x>y
2)x<y
3)x≥y
4)y≥x
5)No relationshipEquation I: x^{4} – 32x^{2} + 256 = 0
Equation II: y^{4 }–7y^{2} + 12 = 0Correct
Explanation:
x^{4} – 32x^{2} + 256 = 0
Let x^{2 }= a. Then,
a^{2} – 32a + 256= 0
⇒ (a –16)^{2} = 0
⇒ a = 16
So, x= ±4
y^{4 }–7y^{2} + 12 = 0
Let y^{2} = b, then
⇒ b^{2} –7b+12 = 0
⇒ (b –4) (b – 3) = 0
⇒ b = 4,3
So, y = ±√3, ±2Comparing the values of x and y, we notice that some values of x are greater than m, some are smaller. So, relation cannot be determined.
Incorrect
Explanation:
x^{4} – 32x^{2} + 256 = 0
Let x^{2 }= a. Then,
a^{2} – 32a + 256= 0
⇒ (a –16)^{2} = 0
⇒ a = 16
So, x= ±4
y^{4 }–7y^{2} + 12 = 0
Let y^{2} = b, then
⇒ b^{2} –7b+12 = 0
⇒ (b –4) (b – 3) = 0
⇒ b = 4,3
So, y = ±√3, ±2Comparing the values of x and y, we notice that some values of x are greater than m, some are smaller. So, relation cannot be determined.

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeQ(15)Choose your answer
1)x>y
2)x<y
3)x≥y
4)y≥x
5)No relationshipEquation I: 12x^{2}80x+132=0,
Equation II: 42y^{2}174y+180=0Correct
Explanation:
I)Take 4 as common
3x^{2}20x+33=0
3x^{2}9x11x+33=0
3x(x3)11(x3)=0
X=+3,+11/3 Take 6 as common
7y^{2}29y+30=0,
7y^{2}14y15y+30=0,
7y(y2)15(y2)=0
Y= +2,15/7
So, x>yIncorrect
Explanation:
I)Take 4 as common
3x^{2}20x+33=0
3x^{2}9x11x+33=0
3x(x3)11(x3)=0
X=+3,+11/3 Take 6 as common
7y^{2}29y+30=0,
7y^{2}14y15y+30=0,
7y(y2)15(y2)=0
Y= +2,15/7
So, x>y 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeQ(15)Choose your answer
1)x>y
2)x<y
3)x≥y
4)y≥x
5)No relationshipEquation I: 27x^{2} –258x + 608 = 0
Equation II: 42y^{2}174y+180=0Correct
Explanation:
I.27x^{2} –258x + 608 = 0
27x^{2} – 144x 114x + 608 = 0
9x(3x16) – 38(3x16)=0
(3x16)(9x38)=0
x=38/9, 16/3II.72y^{2} –475y +722 = 0
72y^{2} –304y – 171y +722 = 0
8y(9y–38)19(9y38) = 0
(8y19)(9y38) = 0
y=19/8, 38/9
x>yIncorrect

Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeQ(15)Choose your answer
1)x>y
2)x<y
3)x≥y
4)y≥x
5)No relationshipEquation I: x^{2} –x + 240 = 0
Equation II: y=√256Correct
Explanation :
I.x^{2} – 16x + 15x 240 = 0< x(x16) + 15(x16) = 0 (x+15)(x16)=0 x=15, 16 II.y =√256 y=16 y≥xIncorrect

Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeQ(15)Choose your answer
1)x>y
2)x<y
3)x≥y
4)y≥x
5)No relationshipEquation I: x2 + 55x + 516 = 0
Equation II: y2 – 50y + 481 = 0Correct
Explanation:
I. x2 + 55x + 516 = 0
x2 + 43x +12x +516 = 0
x(x+43)+12(x+43)= 0
(x+43)(x+12)=0
x= 12, 43
II.y2 – 50y + 481 = 0
y2 – 13y – 37y + 444 = 0
y(y13) 37(y13)=0
(y13)(y37)=0
y=13, 37
y>xIncorrect

Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirection : Q(67)
The average age of Ram, Shyam and Ghanshyam is 26years. 3 year ago, average age of Ram and Shyam was 21yrs. 4 years hence the average age of Shyam and Ghanshyam will be 28 years. Find the present age of Shyam?
Correct
Explanation:
average age of all three = 26
∴ total age of all three= 26×3 = 78
3yrs ago, average age of Ram and Shyam = 21
3yrs ago, total age of Ram and Shyam =21*2= 42
∴ present total age of Ram and Shyam = 42+6=48
∴ present age of Ghanshyam=7848=30
Similarly present age of Ram=30
hence,Present age of shyam is =783030=18 yearsIncorrect
Explanation:
average age of all three = 26
∴ total age of all three= 26×3 = 78
3yrs ago, average age of Ram and Shyam = 21
3yrs ago, total age of Ram and Shyam =21*2= 42
∴ present total age of Ram and Shyam = 42+6=48
∴ present age of Ghanshyam=7848=30
Similarly present age of Ram=30
hence,Present age of shyam is =783030=18 years 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirection : Q(67)
If another guy Danpat joins in who is 2 year younger than Esha and the average of Esha and Raman was 27,two years ago.Also it is given that average of Raman and Ram 4 year hence will be 25.So what is average of present age of Danpat,Raman and Esha?
Correct
Explanation:
Ram age 4 year hence will be 34
Average of Ram and Raman 4 year hence=25
Total age of Ram and Raman 4 year hence=50
Therefore Raman age 4 year hence will be=16
Raman present age=12
Raman age 2 year ago=10
Therefore esha age 2 year ago was=5410=44
Esha current age=46
Danpat current age=44
Average of all three=(46+44+12)/3=34Incorrect
Explanation:
Ram age 4 year hence will be 34
Average of Ram and Raman 4 year hence=25
Total age of Ram and Raman 4 year hence=50
Therefore Raman age 4 year hence will be=16
Raman present age=12
Raman age 2 year ago=10
Therefore esha age 2 year ago was=5410=44
Esha current age=46
Danpat current age=44
Average of all three=(46+44+12)/3=34 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitude36 women can do a work in X days and 30 men can do the same work in (X 4 ) days. The ratio of work done by 10 men and 12 women in the same time is 2:1. What is the value of X?
Correct
Explanation:
M1D1T1/W1=M2D2T2/W2 [men1*day1*time1/work1= men2*day2*time2/work2]
10M/2=12W/1
5M=12W…………………(i)Also 36W*X=30M*(X4)
From (i)
15M*X=30M*(X4)
X=8Incorrect
Explanation:
M1D1T1/W1=M2D2T2/W2 [men1*day1*time1/work1= men2*day2*time2/work2]
10M/2=12W/1
5M=12W…………………(i)Also 36W*X=30M*(X4)
From (i)
15M*X=30M*(X4)
X=8 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeCertain amount of money is divided amongst A, B and C in the ratio of 10 : 11 : 12. Another amount is divided amongst D and E in the respective ratio of 8 : 1. If C got Rs. 2500 more than D, what is the amount received by A?
Correct
Explanation:
No detail is givenIncorrect
Explanation:
No detail is given 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA boat travelling at a speed of 60 kmph started at 3 p.m. when there was no current from point X for point Y which is 240 km apart. After some amount of time current started which delayed the entire journey by 15 minutes.Find the time at which current started if the speed of boat is 6 times to the speed of current?
Correct
Explanation:
As time is increased boat will be travelling against the current
t1+t2=17/4 [t1=time till no current,t2=time after current]
60t1+50t2=240
On solving t1=11/4 hour
Hence current started at 3+11/4=5:45 p.mIncorrect
Explanation:
As time is increased boat will be travelling against the current
t1+t2=17/4 [t1=time till no current,t2=time after current]
60t1+50t2=240
On solving t1=11/4 hour
Hence current started at 3+11/4=5:45 p.m
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