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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirection:Q (15) – Answer these questions on the basis of the information given below.
In a survey, a group of 50 persons were asked about their hobbies. Each person had at least one hobby among Cricket, Painting and Football. No person had a hobby other than these three hobbies. The following chart provides the number of people with exactly one, exactly two and exactly three hobbies:
Further, it is also known that
(i) At least 18 people have Football as their hobby.
(ii) At most 11 people have Painting and Cricket as their hobby.If the number of persons who have Cricket and Painting as their hobby is the same as the number of persons who have only Football as their hobby, what is the maximum number of persons who have Cricket as their hobby?
Correct
Explanation:
a+b+c=28
d+e+f=18
g=4
From (i), e+g+f+c>18
E+f+c>14
From (ii),d+g<11
D<7
Hence 11<e+f<18
Given d+g=c
D+4=c
D=c4
c>4
To maximize cricket as hobby
sum of a,d,g and e should be maximum
g=4
d+e+f=18
To maximize d+e,we can take f=0
D+e=18
For a to be maximum, c must be minimum.
Hence if c=4 and b=0,a=24
The number of people having cricket as their hobby=24+18+4=46
Incorrect
Explanation:
a+b+c=28
d+e+f=18
g=4
From (i), e+g+f+c>18
E+f+c>14
From (ii),d+g<11
D<7
Hence 11<e+f<18
Given d+g=c
D+4=c
D=c4
c>4
To maximize cricket as hobby
sum of a,d,g and e should be maximum
g=4
d+e+f=18
To maximize d+e,we can take f=0
D+e=18
For a to be maximum, c must be minimum.
Hence if c=4 and b=0,a=24
The number of people having cricket as their hobby=24+18+4=46

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirection:Q (15) – Answer these questions on the basis of the information given below.
In a survey, a group of 50 persons were asked about their hobbies. Each person had at least one hobby among Cricket, Painting and Football. No person had a hobby other than these three hobbies. The following chart provides the number of people with exactly one, exactly two and exactly three hobbies:
Further, it is also known that
(i) At least 18 people have Football as their hobby.
(ii) At most 11 people have Painting and Cricket as their hobby.If at least 13 people have Cricket as their hobby, then the number of people who have Painting as their hobby is at most
Correct
Explanation:
A+d+g+e>13
A+d+e>9
D can be maximu of 7,
A+e must be atleast 2.
Since e+c+f>14 (i.e 18g)
E can be taken as 2,f can be atleast 9.hence c has to be atleast 3.The b can be at most 283=25
The maximum of people having painting as their hobby=b+(d+f)+g=25+16+4=45Incorrect
Explanation:
A+d+g+e>13
A+d+e>9
D can be maximu of 7,
A+e must be atleast 2.
Since e+c+f>14 (i.e 18g)
E can be taken as 2,f can be atleast 9.hence c has to be atleast 3.The b can be at most 283=25
The maximum of people having painting as their hobby=b+(d+f)+g=25+16+4=45 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirection:Q (15) – Answer these questions on the basis of the information given below.
In a survey, a group of 50 persons were asked about their hobbies. Each person had at least one hobby among Cricket, Painting and Football. No person had a hobby other than these three hobbies. The following chart provides the number of people with exactly one, exactly two and exactly three hobbies:
Further, it is also known that
(i) At least 18 people have Football as their hobby.
(ii) At most 11 people have Painting and Cricket as their hobby.If the number of persons who have only Painting as their hobby is the same as the number of persons who have exactly two hobbies, which of the following can be the number of persons who have only Cricket as their hobby?
Correct
Explanation:
Given that b=18
Hence a+c=10
Therfore a<10,from the given options answer is 7Incorrect
Explanation:
Given that b=18
Hence a+c=10
Therfore a<10,from the given options answer is 7 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirection:Q (15) – Answer these questions on the basis of the information given below.
In a survey, a group of 50 persons were asked about their hobbies. Each person had at least one hobby among Cricket, Painting and Football. No person had a hobby other than these three hobbies. The following chart provides the number of people with exactly one, exactly two and exactly three hobbies:
Further, it is also known that
(i) At least 18 people have Football as their hobby.
(ii) At most 11 people have Painting and Cricket as their hobby.If the number of persons who have only Cricket as their hobby is the same as the number of persons who have exactly two hobbies, which of the following can be the number of persons who have only Football as their hobby?
Correct
Explanation:
Given that a=18
Hence b+c=10
Therfore c<10,from the given options answer is 7Incorrect
Explanation:
Given that a=18
Hence b+c=10
Therfore c<10,from the given options answer is 7 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirection:Q (15) – Answer these questions on the basis of the information given below.
In a survey, a group of 50 persons were asked about their hobbies. Each person had at least one hobby among Cricket, Painting and Football. No person had a hobby other than these three hobbies. The following chart provides the number of people with exactly one, exactly two and exactly three hobbies:
Further, it is also known that
(i) At least 18 people have Football as their hobby.
(ii) At most 11 people have Painting and Cricket as their hobby.If the number of persons who have only Football as their hobby is the same as the number of persons who have exactly three hobbies, which of the following can be the number of persons who have only Painting as their hobby?
Correct
Explanation:
Given that c=4
Hence a+b=24
Therefore b<24Incorrect
Explanation:
Given that c=4
Hence a+b=24
Therefore b<24 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeI.x^{2} – 49x + 598 = 0
II. y^{3} = 17576Correct
Explanation:
I.x^{2} – 49x + 598 = 0
x^{2} – 26x – 23x + 598 = 0
x(x26)23(x26)= 0
(x23)(x26)=0
x=23, 26
II.y^{3} = 17576
y=26
y≥xIncorrect
Explanation:
I.x^{2} – 49x + 598 = 0
x^{2} – 26x – 23x + 598 = 0
x(x26)23(x26)= 0
(x23)(x26)=0
x=23, 26
II.y^{3} = 17576
y=26
y≥x 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeI.13x^{2} – 33x + 14 = 0
II.2y^{2} – 39y + 70 = 0Correct
Explanation:
I.13x^{2} – 33x + 14 = 0
13x^{2 }– 26x – 7x + 14 = 0
13x(x2)7(x2)= 0
(13x7)(x2)=0
x=7/13, 2
II.2y^{2} – 39y + 70 = 0
2y^{2} – 4y – 35y + 70 = 0
2y(y2) – 35(y2) = 0
(2y35)(y2)=0
y=2, 35/2
x ≤ yIncorrect
Explanation:
I.13x^{2} – 33x + 14 = 0
13x^{2 }– 26x – 7x + 14 = 0
13x(x2)7(x2)= 0
(13x7)(x2)=0
x=7/13, 2
II.2y^{2} – 39y + 70 = 0
2y^{2} – 4y – 35y + 70 = 0
2y(y2) – 35(y2) = 0
(2y35)(y2)=0
y=2, 35/2
x ≤ y 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeI.x^{2} + 14x – 1887 = 0
II.y^{2} – 45y + 374 = 0Correct
Explanation:
I.x^{2} + 14x – 1887 = 0
x^{2} + 51x – 37x – 1887 = 0
x(x+51)37(x+51)= 0
(x37)(x+51)=0
x= 51, 37
II.y^{2} – 45y + 374 = 0
y^{2} – 11y – 34y + 374 = 0
y(y11) 34(y11)=0
(y11)(y34)=0
y=11, 34
No relation can be established.Incorrect
Explanation:
I.x^{2} + 14x – 1887 = 0
x^{2} + 51x – 37x – 1887 = 0
x(x+51)37(x+51)= 0
(x37)(x+51)=0
x= 51, 37
II.y^{2} – 45y + 374 = 0
y^{2} – 11y – 34y + 374 = 0
y(y11) 34(y11)=0
(y11)(y34)=0
y=11, 34
No relation can be established. 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeI.x^{2} – 32x + 255 = 0
II.y^{2} – 27y +182= 0Correct
Explanation:
I.x^{2} – 32x + 255 = 0
x^{2} – 15x – 17x + 255 = 0
x(x15)17(x15)=0
(x15)(x17)=0
x=15,17
II.y^{2} – 27y + 182 = 0
y^{2} – 14y – 13y + 182 = 0
y(y14)13(y14)=0
(y14)(y13)=0
y=13, 14
x>yIncorrect
Explanation:
I.x^{2} – 32x + 255 = 0
x^{2} – 15x – 17x + 255 = 0
x(x15)17(x15)=0
(x15)(x17)=0
x=15,17
II.y^{2} – 27y + 182 = 0
y^{2} – 14y – 13y + 182 = 0
y(y14)13(y14)=0
(y14)(y13)=0
y=13, 14
x>y 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeI.2x^{2} – 39x + 145 = 0
II.y^{2} + 2y – 48 = 0Correct
Explanation:
I.2x^{2 }– 39x + 145 = 0
2x^{2} – 29x – 10x + 145 = 0
x(2x29)5(2x29)= 0
(x5)(2x29)=0
x=5, 29/2
II.y^{2} + 2y – 48 = 0
y^{2} + 8y – 6y – 48 = 0
y (y+ 8) – 6(y + 8) = 0
(y6)(y+8)=0
y = 8, 6Incorrect
Explanation:
I.2x^{2 }– 39x + 145 = 0
2x^{2} – 29x – 10x + 145 = 0
x(2x29)5(2x29)= 0
(x5)(2x29)=0
x=5, 29/2
II.y^{2} + 2y – 48 = 0
y^{2} + 8y – 6y – 48 = 0
y (y+ 8) – 6(y + 8) = 0
(y6)(y+8)=0
y = 8, 6
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