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Question 1 of 10

1. Question

1 points

Category: Reasoning

Direction Q(1-5): Seating Arrangement
10 persons, Q through Z, are sitting around a circular table. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

BETWEEN

NUMBER OF PERSONS

S and T

7

W and R

4

R and Q

5

T and X

4

U and W

3

Z and V

3

S and V

8

V and X

5

Z and R

3

Who is sitting opposite to X?

Correct

Explanation:
Let the figure represent the table with seats numbered from 1 to 10.

Given that between X and T. there are four people, Let X be at R and T be at 6.
Between T and S, there are 7 people. Hence. S can be at 4 or 8.
Let S be at 4. Between S and V there are 8 people (i.e., they are sitting next to each other). Therefore, V can be at 5 or 3. If V is at 3, between V and X there will not be 5(or 3 people). Hence V must be at 5.

Between V and Z, there must be three people. Z can be at 1 or 9. Since X is at 1. Z must be at 9. Between Z and R, there are three people. R can be at 3 or 5. Since V is at 5. R must be at 3. R and W are opposite each other. Hence, W must be at 8. Between Q and R, there are five people. Hence Q must be at 7. Between U and W, there are three people. Hence. U must be at 2 and Y must be at 10.

If S is at 8, it will result in the same arrangement but in the anticlockwise direction.

Therefore, two cases are possible which are tabulated below:

POSITION

CASE-1

CASE-2

1

X

X

2

U

Y

3

R

Z

4

S

W

5

V

Q

6

T

T

7

Q

V

8

W

S

9

Z

R

10

Y

U

Incorrect

Explanation:
Let the figure represent the table with seats numbered from 1 to 10.

Given that between X and T. there are four people, Let X be at R and T be at 6.
Between T and S, there are 7 people. Hence. S can be at 4 or 8.
Let S be at 4. Between S and V there are 8 people (i.e., they are sitting next to each other). Therefore, V can be at 5 or 3. If V is at 3, between V and X there will not be 5(or 3 people). Hence V must be at 5.

Between V and Z, there must be three people. Z can be at 1 or 9. Since X is at 1. Z must be at 9. Between Z and R, there are three people. R can be at 3 or 5. Since V is at 5. R must be at 3. R and W are opposite each other. Hence, W must be at 8. Between Q and R, there are five people. Hence Q must be at 7. Between U and W, there are three people. Hence. U must be at 2 and Y must be at 10.

If S is at 8, it will result in the same arrangement but in the anticlockwise direction.

Therefore, two cases are possible which are tabulated below:

POSITION

CASE-1

CASE-2

1

X

X

2

U

Y

3

R

Z

4

S

W

5

V

Q

6

T

T

7

Q

V

8

W

S

9

Z

R

10

Y

U

Question 2 of 10

2. Question

1 points

Category: Reasoning

Direction Q(1-5): Seating Arrangement
10 persons, Q through Z, are sitting around a circular table. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

BETWEEN

NUMBER OF PERSONS

S and T

7

W and R

4

R and Q

5

T and X

4

U and W

3

Z and V

3

S and V

8

V and X

5

Z and R

3

Who among the following is sitting next to Z?

Correct

Explanation:
Y and W are sitting next to Z

Incorrect

Explanation:
Y and W are sitting next to Z

Question 3 of 10

3. Question

1 points

Category: Reasoning

Direction Q(1-5): Seating Arrangement
10 persons, Q through Z, are sitting around a circular table. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

BETWEEN

NUMBER OF PERSONS

S and T

7

W and R

4

R and Q

5

T and X

4

U and W

3

Z and V

3

S and V

8

V and X

5

Z and R

3

If the person to the left of Z and the person to the right of T are sitting next to each other, who is sitting to the left of X?

Correct

Incorrect

Question 4 of 10

4. Question

1 points

Category: Reasoning

Direction Q(1-5): Seating Arrangement
10 persons, Q through Z, are sitting around a circular table. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

BETWEEN

NUMBER OF PERSONS

S and T

7

W and R

4

R and Q

5

T and X

4

U and W

3

Z and V

3

S and V

8

V and X

5

Z and R

3

If there is exactly one person sitting between V and Q, who is sitting to the left of Y?

Correct

Incorrect

Question 5 of 10

5. Question

1 points

Category: Reasoning

Direction Q(1-5): Seating Arrangement
10 persons, Q through Z, are sitting around a circular table. The table below presents the number of persons sitting between two persons, not necessarily in one specific direction (clockwise or anticlockwise):

BETWEEN

NUMBER OF PERSONS

S and T

7

W and R

4

R and Q

5

T and X

4

U and W

3

Z and V

3

S and V

8

V and X

5

Z and R

3

Who is sitting opposite V?

Correct

Incorrect

Question 6 of 10

6. Question

1 points

Category: Reasoning

Direction: Q (6-10) – In a certain code language

He Love Affair – 12Z-& 8G+* 12K+*
Affair is Best – 12Z-& 13A-* 5H-&
Best always wins – 9V+* 13A-* 13Z-&
Hard work off – 9G+* 17V+* 14N+&

What can be the code for “clouds”?

Correct

Explanation:
A(1) B(2) C(3) D(4) E(5) F(6) G(7) H(8) I(9) J(10)
K(11) L(12) M(13) N(14) O(15) P(16) Q(17) R(18) S(19) T(20)
U(21) V(22) W(23) X(24) Y(25) Z(26)
He======8G+*
H=8[first]
E=5[last]
(8-5)+5=+8
Previous letter of 1^{st} letter (H) in word i.e G
2^{nd} letter in He is ‘e’, which is vowel hence *
affair========12Z-&
a=1[first]
r=18[last]
(1-18)+5=-12
Previous letter of 1^{st}letter(A) in word i.e Z
2^{nd} letter in Affair is ‘f’..hence f=&
If 2^{nd} letter in word is vowel then * else &

Incorrect

Explanation:
A(1) B(2) C(3) D(4) E(5) F(6) G(7) H(8) I(9) J(10)
K(11) L(12) M(13) N(14) O(15) P(16) Q(17) R(18) S(19) T(20)
U(21) V(22) W(23) X(24) Y(25) Z(26)
He======8G+*
H=8[first]
E=5[last]
(8-5)+5=+8
Previous letter of 1^{st} letter (H) in word i.e G
2^{nd} letter in He is ‘e’, which is vowel hence *
affair========12Z-&
a=1[first]
r=18[last]
(1-18)+5=-12
Previous letter of 1^{st}letter(A) in word i.e Z
2^{nd} letter in Affair is ‘f’..hence f=&
If 2^{nd} letter in word is vowel then * else &

Question 7 of 10

7. Question

1 points

Category: Reasoning

Direction: Q (6-10) – In a certain code language

He Love Affair – 12Z-& 8G+* 12K+*
Affair is Best – 12Z-& 13A-* 5H-&
Best always wins – 9V+* 13A-* 13Z-&
Hard work off – 9G+* 17V+* 14N+&

What is the code for “affair clouds pays off”?

Correct

Incorrect

Question 8 of 10

8. Question

1 points

Category: Reasoning

Direction: Q (6-10) – In a certain code language

He Love Affair – 12Z-& 8G+* 12K+*
Affair is Best – 12Z-& 13A-* 5H-&
Best always wins – 9V+* 13A-* 13Z-&
Hard work off – 9G+* 17V+* 14N+&

What can be the code for “failure”?

Correct

Explanation:
failure======6E+*
f=6
e=5
(6-5)+5=+6
Previous letter of 1^{st}letter(F) in word i.e E
2^{nd} letter in Failure is ‘a’, which is vowel hence *

Incorrect

Explanation:
failure======6E+*
f=6
e=5
(6-5)+5=+6
Previous letter of 1^{st}letter(F) in word i.e E
2^{nd} letter in Failure is ‘a’, which is vowel hence *

Question 9 of 10

9. Question

1 points

Category: Reasoning

Direction: Q (6-10) – In a certain code language

He Love Affair – 12Z-& 8G+* 12K+*
Affair is Best – 12Z-& 13A-* 5H-&
Best always wins – 9V+* 13A-* 13Z-&
Hard work off – 9G+* 17V+* 14N+&

What is the code for “love is always best” ?

Correct

Incorrect

Question 10 of 10

10. Question

1 points

Category: Reasoning

Direction: Q (6-10) – In a certain code language

He Love Affair – 12Z-& 8G+* 12K+*
Affair is Best – 12Z-& 13A-* 5H-&
Best always wins – 9V+* 13A-* 13Z-&
Hard work off – 9G+* 17V+* 14N+&

What can be the code for the word “fluorescent”?

Correct

Explanation:
fluorescent========9E-&
f=6[first]
t=20[last]
(6-20)+5=-9
Previous letter of 1^{st}letter(F) in word i.e E
2^{nd} letter in fluorescent is ‘l’..hence l=&
If 2^{nd} letter in word is vowel then * else &

Incorrect

Explanation:
fluorescent========9E-&
f=6[first]
t=20[last]
(6-20)+5=-9
Previous letter of 1^{st}letter(F) in word i.e E
2^{nd} letter in fluorescent is ‘l’..hence l=&
If 2^{nd} letter in word is vowel then * else &