# SBI PO 2015: Quantitative Aptitude Quiz Set 3

Hello Aspirants, Welcome to SBI PO 2015 Quiz Sections. Here is a set of question with solution in Quantitative Aptitude based on Sbi po exam. We hope it will helpful for exam. Kindly tell your suggestion in comment section.

1. A man loses rs 20 by selling some toys @rs 3 per piece and gains rs 30, if he sells them at rs3.25 per piece, the number of pieces sold by him are?
A. 50
B. 40
C. 200
D. 150
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Ans – C.200
Explanation:

cp when loss= 3x+20
cp when profit= 3.25x-30
cp=cp
3x+20=3.25x-30
50=0.25x
x=200

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2. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:
A. 2 hours
B. 1hour
C. 4hours
D. 5 hours
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Ans – B. 1hour
Explanation:
Let the duration of the flight be x hours.
Then, 600/X – 600/x + (1/2) = 200
600/x – 1200/2x + 1 = 200
x(2x + 1) = 3
2×2 + x – 3 = 0
(2x + 3)(x – 1) = 0
x = 1 hr. [neglecting the -ve value of x]

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3. The Average age of a class of 22 students is 21 years. The average increased by 1 when the teacher’s age also included. What is the age of the teacher?
A. 41
B. 42
C. 44
D. 45
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Ans – C . 44
Explanation: Avg x Number = Total
21 years x 22 nos = 462 years (1)
22 years x 23 nos = 506 years……(2)
Teacher’s age = (2) – (1) = 506 – 462 = 44 Years

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4. A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A. 2
B. 3 m
C. 5
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Explanation: Area of the park = (60 x 40) m2 = 2400 m2.
Area of the lawn = 2109 m2.
Area of the crossroads = (2400 – 2109) m2 = 291 m2.

See road is a rect. and they are intercrossing. let the width be x, then for one road area will be 40x and for the other road will be 60x since 60 and 40 will be the lengths of road.
also,There will be a common space for two roads. (width of two cross roads is width^2).

60x + 40x – x^2 = 291
x^2 – 100x + 291 = 0
(x – 97)(x – 3) = 0
x = 3.

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5. Nishu purchased furniture for Rs.60800. He marked the article 20% above the cost price and sold it by offering 15% discount. Find his profit or loss percent. Select the correct alternative from the given choices.
A. 4%
B. 2%
C. 6%
D. 5%
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Ans- B. 2%
Explanation: cost price= rs 60800
M.P= 60800 +[(20/100)x60800]
=rs 72960
Selling price = [(100-15)/100]x 72960= Rs 62016
profit=62016-60800= Rs 1216
profit %= (1216/60800)x100=2%

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6. In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, the dividend is
A. 4236
B. 4306
C. 4336
D. 5336
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Explanation: Divisor = (5 x 46) = 230.
Also, 10 x Q = 230
Q = 23. And, R = 46.
Dividend = (230 x 23 + 46) = 5336

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7. A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, 50% of the components were rejected. What is the loss to the manufacture?
A. Rs 12,000
B. Rs 13,000
C. Rs 14,000
D. Rs 15,000
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Ans – B (Rs 13,000)
Explanation: Total cost incurred = Rs.[100/125 x 25 x (95%of 2000) ]
Rs.(100/125 x 25 x 1900)= Rs.38000
Loss to the manufacture = Rs [35000-(25 x 1000)]- Rs. 13000

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8. A number when divided by 119 leaves 19 as remainder. If the same number is divided by 17, the remainder obtained is
A. 2
B. 4
C. 8
D. 10
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Explanation: Number = (119 x Q) + 19 = 17 x (7Q) + (17 + 2) = 17 x (7Q + 1) + 2
Required remainder = 2

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9. Agra Express Left Delhi from Agra at 14.30 hrs, travelling at a speed of 60 kmph and Rajdhani Express on the same day at 16.30 hrs, travelling at a speed of 80 kmph. How far away from Delhi will the two trains meet?
A. 140 km
B. 340 km
C. 480 km
D. 500 km
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Ans – C (480 km)
Explanation: Suppose they meet x hours after 14.30 hrs
Then, 60x = 80 (x – 2) or x = 8
Required distance = (60 x 8) km = 480 km

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10. Ten years ago, Kumar was thrice as old as Selva was but 10 years hence, he will be only twice as old. Find Selva’s present age?
A. 30
B. 32
C. 34
D. 36
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Ans – A (30)
Explanation: Let Kumar’s present age be x years and Selva’s present age be y years
Then, according to the first condition,
x – 10 = 3(y – 10)
or, x – 3y = -20 ……..(1)
Now. Kumar’s age after 10 years = (x + 10) years
Selva’s age after 10 years = (y + 10)
(x+10) = 2(y+10)
or, x – 2y = 10 ……..(2)
Solving (1) and (2), we get
x = 70 and y = 30
Kumar’s age = 70 years and Selva’s age = 30 years

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