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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The ratio of the present age of Rahul to that of Ravi is 3 : 11. Ravi is 12 years younger than Ritesh. Ritesh’s age after 7 years will be 85 years. What is the present age of Rahul’s father, who is 25 years older than Rahul?

Correct

Explanation:
Let the present age of Rahul and Ravi are 3x and 11x.
11x = 85-7-12 = 66
x=6
Rahul’s present age = 18
Present age of Rahul’s father = 18+25 = 43

Incorrect

Explanation:
Let the present age of Rahul and Ravi are 3x and 11x.
11x = 85-7-12 = 66
x=6
Rahul’s present age = 18
Present age of Rahul’s father = 18+25 = 43

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

In a factory, there are equal number of women and children. Women work for 6 hours a day and children for 4 hours a day. During festival time, the work load goes up by 50%. The government rule does not allow children to work for more than 6 hours day. If they are equally efficient and the extra work is done by women, then extra hours of work put in by women every day are

Correct

Explanation:
(M1*D1*T1)/W1 = (M2*D2*T2)/W2
They are equally efficient, So take M1=M2=1;
During the festival time, extra hours of Women work for one day is ‘x’
(1*1*(6+4))/1 = (1*1*(6+6+x))/1.5 => x=3

OR

let women=children=x
dowk done by women in 1 day x=1/6
dowk done by children in 1 day x=1/4
total work
2x= 1/6 + 1/4= 5/12
2x=5/12——–1
when work load up by 50%
children work 6 hrs and let women work y hrs
dowk done by women in 1 day x=1/y
dowk done by children in 1 day x=1/6
2x =1.5(1/6 + 1/y)— 2
frm eqn 1 & 2
5/12 = 1.5(1/6 + 1/y)
on solving we get
y=9 hrs
so extra work is done by women=9-6= 3 hrs

Incorrect

Explanation:
(M1*D1*T1)/W1 = (M2*D2*T2)/W2
They are equally efficient, So take M1=M2=1;
During the festival time, extra hours of Women work for one day is ‘x’
(1*1*(6+4))/1 = (1*1*(6+6+x))/1.5 => x=3

OR

let women=children=x
dowk done by women in 1 day x=1/6
dowk done by children in 1 day x=1/4
total work
2x= 1/6 + 1/4= 5/12
2x=5/12——–1
when work load up by 50%
children work 6 hrs and let women work y hrs
dowk done by women in 1 day x=1/y
dowk done by children in 1 day x=1/6
2x =1.5(1/6 + 1/y)— 2
frm eqn 1 & 2
5/12 = 1.5(1/6 + 1/y)
on solving we get
y=9 hrs
so extra work is done by women=9-6= 3 hrs

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

A shopkeeper purchases a packet of 50 candles at Rs 10 per candle. He sells a part of the packet at a profit of 30%. On the remaining part, he incurs a loss of 10%. If his overall profit on the whole packet is 10%, the number candles he sold at profit is

Correct

Explanation:
Shortcut:
Let 1/x part at 30% profit, then (1 – 1/x) at 10% loss
Then
(1/x)*(30) + (1 – 1/x)*(-10) = 10
Solve 1/x = 1/2
So at profit = 1/2 * 50 = 25
OR
Net profit 10% => 500+50 = 550
Number of candles sold at Profit = x ; Number of candles sold at loss=(50-x)
(10x * 130/100) + (10[50-x]*90/100) = 550
1300x+45000 -900x = 55000
400x = 10000
X = 25

Incorrect

Explanation:
Shortcut:
Let 1/x part at 30% profit, then (1 – 1/x) at 10% loss
Then
(1/x)*(30) + (1 – 1/x)*(-10) = 10
Solve 1/x = 1/2
So at profit = 1/2 * 50 = 25
OR
Net profit 10% => 500+50 = 550
Number of candles sold at Profit = x ; Number of candles sold at loss=(50-x)
(10x * 130/100) + (10[50-x]*90/100) = 550
1300x+45000 -900x = 55000
400x = 10000
X = 25

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Keshav is rowing a boat. He takes half time in moving a certain distance downstream than upstream. What is the ratio of the rate of boat in still water to the rate of current?

Correct

Explanation:
Shortcut:
Let downstream time = 2t and then upstream time = t
B = [t_{u} + t_{d}] / [t_{u} – t_{d}] * R
B = [2t+t] / [2t-t] * R
B/R = 3/1
OR
Let speed of Keshav’s boat in still water be x kmph and speed of current be y kmph
Downstream Speed= (x + y) kmph ; Upstream Speed = (x – y) kmph
Distance = A
2A/(x + y) = A/(x – y)
2(x – y) = x + y
2x – 2y = x + y
x = 3y
x:y = 3:1

Incorrect

Explanation:
Shortcut:
Let downstream time = 2t and then upstream time = t
B = [t_{u} + t_{d}] / [t_{u} – t_{d}] * R
B = [2t+t] / [2t-t] * R
B/R = 3/1
OR
Let speed of Keshav’s boat in still water be x kmph and speed of current be y kmph
Downstream Speed= (x + y) kmph ; Upstream Speed = (x – y) kmph
Distance = A
2A/(x + y) = A/(x – y)
2(x – y) = x + y
2x – 2y = x + y
x = 3y
x:y = 3:1

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Nine friends have a dinner in a hotel Eight of them spent Rs.12 each on their meals and the ninth spent Rs.16 more than the average expenditure of all the nine. What was the total money spent by them?

Correct

Explanation:
Average Expenditure of 9 Friends = x; Total amount = 9x
12*8 + (x+16) = 9X
x=14 => Total amount = 9*14=126

Incorrect

Explanation:
Average Expenditure of 9 Friends = x; Total amount = 9x
12*8 + (x+16) = 9X
x=14 => Total amount = 9*14=126

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

A, B and C entered into partnership in a business. A got 3/5 of the profit. B and C distributed the remaining profit equally. If C got Rs.400 less than A, the total profit was

Correct

Explanation:
Total Profit = x
Remaining Profit of B & C = x-(3/5) =2x/5 => B=x/5; C=x/5
3x/5 -x/5 = 400
x=1000

Incorrect

Explanation:
Total Profit = x
Remaining Profit of B & C = x-(3/5) =2x/5 => B=x/5; C=x/5
3x/5 -x/5 = 400
x=1000

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

A sum of Rs.1550 was lent partly at 5% and partly at 8% per annum SI. The total Interest received after four year was Rs.400. The ratio of the amount lent at 5% to that lent at 8% is

Correct

Explanation:
Shortcut:
Total r% = (400*100)/(4*1550) = 200/31
Now by allegation method:
5………………………….8
………..200/31
48/31………………..45/31
48 : 45
16 : 15
OR
Let the sum lent @ 5% = P ; let the Sum lent @ 8% = 1550 – P
{(P*5*4)/100 + ([1550-P]*8*4)/100 = 400
P=800
Sum lent @ 8% = 1550-800 = 750
Required Ratio = lent at 5% ; lent at 8% = 800:750 => 16:15

Incorrect

Explanation:
Shortcut:
Total r% = (400*100)/(4*1550) = 200/31
Now by allegation method:
5………………………….8
………..200/31
48/31………………..45/31
48 : 45
16 : 15
OR
Let the sum lent @ 5% = P ; let the Sum lent @ 8% = 1550 – P
{(P*5*4)/100 + ([1550-P]*8*4)/100 = 400
P=800
Sum lent @ 8% = 1550-800 = 750
Required Ratio = lent at 5% ; lent at 8% = 800:750 => 16:15