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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeJar A is sold at 18% profit & both Jars have the same cost price, if overall profit is 16%, and if Jar B is sold at Rs.70 more then find the cost price of Jar A.
Correct
Answer: 1) Rs. 500
Explanation:
Let the cost price of each Jar is Rs. 100x
Total CP = 200x
Since overall profit is 16%
Sum of SP of both the jars = 116% of 200x = 232x
SP of jar A = 118% of 100x = 118x
SP of jar B = 232x – 118x = 114x
Since jar B is sold at Rs. 70 more
114x 100x = 14x
14x = 70
X = 5
Cost price of jar A = 100*5 = Rs. 500Incorrect
Answer: 1) Rs. 500
Explanation:
Let the cost price of each Jar is Rs. 100x
Total CP = 200x
Since overall profit is 16%
Sum of SP of both the jars = 116% of 200x = 232x
SP of jar A = 118% of 100x = 118x
SP of jar B = 232x – 118x = 114x
Since jar B is sold at Rs. 70 more
114x 100x = 14x
14x = 70
X = 5
Cost price of jar A = 100*5 = Rs. 500 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude28 men can complete a work in 45 days, 35 men start work and work for x days after that 15 more men joined them and complete remaining work in 15(2/5) days, find the value of x.
Correct
Answer: 4) 14
Explanation:
Let the total work is 28*45 = 1260
Work done by 35 men is x days = 35x
Work done by (35+15) men in 15(2/5) days = 50 * 77/5 = 770
Since the work is completed,
35x + 770 = 1260
X = 14Incorrect
Answer: 4) 14
Explanation:
Let the total work is 28*45 = 1260
Work done by 35 men is x days = 35x
Work done by (35+15) men in 15(2/5) days = 50 * 77/5 = 770
Since the work is completed,
35x + 770 = 1260
X = 14 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA mixture of milk and water has 30% water, 80 litre mixture is removed, then milk becomes 64 litres more than water in remaining mixture. Find initial milk.
Correct
Answer: 4) 168 litres
Explanation:
Let the initial amount of milk in the mixture is 7x, and initial amount of water in the mixture is 3x
Now, 80 litres will be removed in the ratio as 7:3
Milk removed will be 56 litres and water removed will be 24 litres
Milk left = 7x56, water left = 3x 24
According to question,
7x – 56 – (3x24) = 64
4x – 32 = 64
X = 24
Therefore, initial milk = 7x = 7*24 = 168 litresIncorrect
Answer: 4) 168 litres
Explanation:
Let the initial amount of milk in the mixture is 7x, and initial amount of water in the mixture is 3x
Now, 80 litres will be removed in the ratio as 7:3
Milk removed will be 56 litres and water removed will be 24 litres
Milk left = 7x56, water left = 3x 24
According to question,
7x – 56 – (3x24) = 64
4x – 32 = 64
X = 24
Therefore, initial milk = 7x = 7*24 = 168 litres 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the speed of a boat and current is 11:3. The ratio of time taken of distance “D” in downstream and “D+45” in upstream is 2: 5. Find the distance D.
Correct
Answer: 1) 105
Explanation:
Let speed of boat = 11x and speed of current = 3x
Upstream speed =11x3x =8x
Downstream speed = 11x+3x =14x
According to question,
D/14x : (D+45) / 8x = 2:5
D/14x * 8x/(D+45) = 2/5
20D = 14D + 14*45
D = 105Incorrect
Answer: 1) 105
Explanation:
Let speed of boat = 11x and speed of current = 3x
Upstream speed =11x3x =8x
Downstream speed = 11x+3x =14x
According to question,
D/14x : (D+45) / 8x = 2:5
D/14x * 8x/(D+45) = 2/5
20D = 14D + 14*45
D = 105 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA invests “K” and after 4 month B invest “K 1260″. The ratio of total annualprofit and B’s profit is 9: 2. Find the value of “K”.
Correct
Answer: 3) 2205
Explanation:
Let the total annual profit = 9x
Profit of B = 2x
Profit of A will be = 9x2x = 7x
(Investment of A * Time)/(Investment of B * Time ) = Profit of A / Profit of B
Investment of A is for 12 months and Investment of B is for (124) = 8 months
(K *12) / {(K1260)*8} = 7/2
24K = 7*8* (K1260)
3K = 7K – 7*1260
K = 2205Incorrect
Answer: 3) 2205
Explanation:
Let the total annual profit = 9x
Profit of B = 2x
Profit of A will be = 9x2x = 7x
(Investment of A * Time)/(Investment of B * Time ) = Profit of A / Profit of B
Investment of A is for 12 months and Investment of B is for (124) = 8 months
(K *12) / {(K1260)*8} = 7/2
24K = 7*8* (K1260)
3K = 7K – 7*1260
K = 2205 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeAges of three friends A, B and C after 5 years will be in the ratio 8:9:6 and ratio of ages of B,C and D before 3 years was 7:4:5. What is the sum of the present age of B and D.
Correct
Answer: 4) 54 years
Explanation:
Let the age of A,B and C after 5 years is 8x, 9x and 6x respectively.
Present age of A,B and C is 8x5, 9x5 and 6x5 respectively.
Let the age of B, C and D before 3 years was 7y, 4y and 5y.
Present age of B, C and D is 7y +3, 4y +3, 5y + 3 .
Equating
the present age of B
9x5 = 7y + 3
9x7y = 8 …………..(1)
Equating the present age of C,
6x5 = 4y + 3
6x – 4y = 8 ……….(2)
From, equation (1) and (2), we get
X = y = 4
Present age of B = 7y+3 = 7*4 + 3 = 31
Present age of D = 5y+3 = 5*4+3 = 23
Sum of the present age of B and D = 31+23 = 54 yearsIncorrect
Answer: 4) 54 years
Explanation:
Let the age of A,B and C after 5 years is 8x, 9x and 6x respectively.
Present age of A,B and C is 8x5, 9x5 and 6x5 respectively.
Let the age of B, C and D before 3 years was 7y, 4y and 5y.
Present age of B, C and D is 7y +3, 4y +3, 5y + 3 .
Equating
the present age of B
9x5 = 7y + 3
9x7y = 8 …………..(1)
Equating the present age of C,
6x5 = 4y + 3
6x – 4y = 8 ……….(2)
From, equation (1) and (2), we get
X = y = 4
Present age of B = 7y+3 = 7*4 + 3 = 31
Present age of D = 5y+3 = 5*4+3 = 23
Sum of the present age of B and D = 31+23 = 54 years 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeWhen 60% of a number is added with that number and its result is multiplied by 15, then result becomes 480. Find the number?
Correct
Answer: 3) 20
Explanation:
Let the number is x
60% of x = (60x/100) = 3x/5
According to question,
(x+3x/5)*15 = 480
(8x/5)*15 = 480
24x =480
X=20Incorrect
Answer: 3) 20
Explanation:
Let the number is x
60% of x = (60x/100) = 3x/5
According to question,
(x+3x/5)*15 = 480
(8x/5)*15 = 480
24x =480
X=20 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIf the average of three numbers A, B and C is 42, average of A and C is 39, average of B and C is 44 then what will be the 3/4th of the number C.
Correct
Answer: 1) 30
Explanation:
(A+B+C)/3 = 42
(A+B+C) = 126 ……………(1)
(A+C)/2 = 39
(A+C) = 78 ………………(2)
Adding (A+C) = 78 , in equation (1), we get
B = 48
(B+C)/2 = 44
B+C = 88
48+C = 88
C =40
3/4th of the number C = (3/4)* 40 = 30Incorrect
Answer: 1) 30
Explanation:
(A+B+C)/3 = 42
(A+B+C) = 126 ……………(1)
(A+C)/2 = 39
(A+C) = 78 ………………(2)
Adding (A+C) = 78 , in equation (1), we get
B = 48
(B+C)/2 = 44
B+C = 88
48+C = 88
C =40
3/4th of the number C = (3/4)* 40 = 30 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThe perimeter of a rectangle is 74 cm and its breadth is 5 cm less than length. An equilateral triangle has side same as the breadth of the rectangle. Area of the equilateral triangle is
Correct
Answer: 5) 64√3
Explanation:
Perimeter of Rectangle = 2*(L+B)
2*(L+B) = 74
L+B = 37
Also, breadth is 5 less than length (L = B+5)
B+5+B = 37
2B = 32
B = 16
Area of the equilateral triangle = ( √3 /4) * (side)^{2}
= (√3 /4) * (16)^{2}
= 64 √3 sq cmIncorrect
Answer: 5) 64√3
Explanation:
Perimeter of Rectangle = 2*(L+B)
2*(L+B) = 74
L+B = 37
Also, breadth is 5 less than length (L = B+5)
B+5+B = 37
2B = 32
B = 16
Area of the equilateral triangle = ( √3 /4) * (side)^{2}
= (√3 /4) * (16)^{2}
= 64 √3 sq cm 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeAjay invests a principal amount of Rs. 5600 in a fixed deposit for 3.5 years. The rate at which he invests is 16% per annum. What will be the simple interest earned by him at the end of his investment tenure?
Correct
Answer: 3) Rs. 3136
Explanation:
Simple interest = (Principal*Rate*Time)/100
= (5600*16*3.5)/100
= 3136Incorrect
Answer: 3) Rs. 3136
Explanation:
Simple interest = (Principal*Rate*Time)/100
= (5600*16*3.5)/100
= 3136
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