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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(15): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.
Total number of students who are selected from Class A and E together is how much greater than the total number of students who are selected from Class B and F together?
Correct
Answer – 3. 18
Explanation:
Class A and E = 18 + 15 = 33%
Class B and F = 12 + 15 = 27%
6% of 300 = 18Incorrect
Answer – 3. 18
Explanation:
Class A and E = 18 + 15 = 33%
Class B and F = 12 + 15 = 27%
6% of 300 = 18 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(15): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.
If the total number of students is increased by 30% in June 2018 as compared to May 2018 then the total number of students will participate in June 2018 is
Correct
Answer – 3. 390
Explanation:
130/100 * 300 = 390Incorrect
Answer – 3. 390
Explanation:
130/100 * 300 = 390 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(15): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.
Find the central angle of total number of students who are selected from Class C?
Correct
Answer – 5. 64.8°
Explanation:
Central angle = 18/100 * 360 = 64.8°Incorrect
Answer – 5. 64.8°
Explanation:
Central angle = 18/100 * 360 = 64.8° 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(15): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.
Find the average number of students who are selected from Class B, C and D together?
Correct
Answer – 4. 52
Explanation:
(52/3*100) * 300 = 52Incorrect
Answer – 4. 52
Explanation:
(52/3*100) * 300 = 52 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(15): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.
Find the ratio between the total number of students who are selected from Class B and D together to total number of students who are selected from Class E and F together?
Correct
Answer – 4. 17 : 15
Explanation:
Ratio = 34 : 30 => 17:15Incorrect
Answer – 4. 17 : 15
Explanation:
Ratio = 34 : 30 => 17:15 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative Aptitude257 ? 191 168 149 132
Correct
Answer – 3. 220
Explanation:
Incorrect
Answer – 3. 220
Explanation:

Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitude20, 9, 7, 11, 29, ?
Correct
Answer – 3. 111
Explanation:
20 * 0.5 – 1 = 9
9 * 1 – 2 = 7
7 * 2 – 3 = 11
11 * 3 – 4 = 29
29 * 4 – 5 = 111Incorrect
Answer – 3. 111
Explanation:
20 * 0.5 – 1 = 9
9 * 1 – 2 = 7
7 * 2 – 3 = 11
11 * 3 – 4 = 29
29 * 4 – 5 = 111 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeRatio between speed of boat in still water to speed of stream is 8 : 1. It covers 67.5 km distance in 2 and half an hour in downstream. Then find the speed of boat?
Correct
Answer – 3. 24 kmph
Explanation:
67.5/2.5 = 8x + x
x = 27/9
x = 3kmph
Speed of boat in still water = 24 kmphIncorrect
Answer – 3. 24 kmph
Explanation:
67.5/2.5 = 8x + x
x = 27/9
x = 3kmph
Speed of boat in still water = 24 kmph 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThe perimeter of a rectangle whose length is 8m more than its breadth is 92m. what will be the area of the rectangle?
Correct
Answer – 4. 513m²
Explanation:
Breadth of rectangle = x metre
Length = (x + 8) metre
2(x + 8 + x) = 92
2x = 46 – 8 = 38
x= 19
Length = 19 + 8 = 27 metre
Area of the rectangle = 19 * 27 = 513m²Incorrect
Answer – 4. 513m²
Explanation:
Breadth of rectangle = x metre
Length = (x + 8) metre
2(x + 8 + x) = 92
2x = 46 – 8 = 38
x= 19
Length = 19 + 8 = 27 metre
Area of the rectangle = 19 * 27 = 513m² 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative Aptitude2x² – 11x + 14 = 0
y² – 9y + 20 = 0Correct
Answer – 2. X < Y
Explanation:
2x² – 11x + 14 = 0
x = 3.5, 2
y² – 9y + 20 = 0
y = 5, 4Incorrect
Answer – 2. X < Y
Explanation:
2x² – 11x + 14 = 0
x = 3.5, 2
y² – 9y + 20 = 0
y = 5, 4
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