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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Directions Q.(1-5): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.

Total number of students who are selected from Class A and E together is how much greater than the total number of students who are selected from Class B and F together?

Correct

Answer – 3. 18
Explanation:
Class A and E = 18 + 15 = 33%
Class B and F = 12 + 15 = 27%
6% of 300 = 18

Incorrect

Answer – 3. 18
Explanation:
Class A and E = 18 + 15 = 33%
Class B and F = 12 + 15 = 27%
6% of 300 = 18

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Directions Q.(1-5): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.

If the total number of students is increased by 30% in June 2018 as compared to May 2018 then the total number of students will participate in June 2018 is

Correct

Answer – 3. 390
Explanation:
130/100 * 300 = 390

Incorrect

Answer – 3. 390
Explanation:
130/100 * 300 = 390

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions Q.(1-5): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.

Find the central angle of total number of students who are selected from Class C?

Directions Q.(1-5): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.

Find the average number of students who are selected from Class B, C and D together?

Correct

Answer – 4. 52
Explanation:
(52/3*100) * 300 = 52

Incorrect

Answer – 4. 52
Explanation:
(52/3*100) * 300 = 52

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions Q.(1-5): Pie chart given below shows the total number of students who are selected for a competition in a school from five different classes in May 2018. Study the data carefully and answer the following questions.

Find the ratio between the total number of students who are selected from Class B and D together to total number of students who are selected from Class E and F together?

Ratio between speed of boat in still water to speed of stream is 8 : 1. It covers 67.5 km distance in 2 and half an hour in downstream. Then find the speed of boat?

Correct

Answer – 3. 24 kmph
Explanation:
67.5/2.5 = 8x + x
x = 27/9
x = 3kmph
Speed of boat in still water = 24 kmph

Incorrect

Answer – 3. 24 kmph
Explanation:
67.5/2.5 = 8x + x
x = 27/9
x = 3kmph
Speed of boat in still water = 24 kmph

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

The perimeter of a rectangle whose length is 8m more than its breadth is 92m. what will be the area of the rectangle?

Correct

Answer – 4. 513m²
Explanation:
Breadth of rectangle = x metre
Length = (x + 8) metre
2(x + 8 + x) = 92
2x = 46 – 8 = 38
x= 19
Length = 19 + 8 = 27 metre
Area of the rectangle = 19 * 27 = 513m²

Incorrect

Answer – 4. 513m²
Explanation:
Breadth of rectangle = x metre
Length = (x + 8) metre
2(x + 8 + x) = 92
2x = 46 – 8 = 38
x= 19
Length = 19 + 8 = 27 metre
Area of the rectangle = 19 * 27 = 513m²

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

2x² – 11x + 14 = 0
y² – 9y + 20 = 0

Correct

Answer – 2. X < Y
Explanation:
2x² – 11x + 14 = 0
x = 3.5, 2
y² – 9y + 20 = 0
y = 5, 4

Incorrect

Answer – 2. X < Y
Explanation:
2x² – 11x + 14 = 0
x = 3.5, 2
y² – 9y + 20 = 0
y = 5, 4

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